You are given an array nums of distinct integers.
In one operation, you can swap any two adjacent elements in the array.
\n\nAn arrangement of the array is considered valid if the parity of adjacent elements alternates, meaning every pair of neighboring elements consists of one even and one odd number.
\n\nReturn the minimum number of adjacent swaps required to transform nums into any valid arrangement.
If it is impossible to rearrange nums such that no two adjacent elements have the same parity, return -1.
\n
Example 1:
\n\nInput: nums = [2,4,6,5,7]
\n\nOutput: 3
\n\nExplanation:
\n\nSwapping 5 and 6, the array becomes [2,4,5,6,7]
Swapping 5 and 4, the array becomes [2,5,4,6,7]
Swapping 6 and 7, the array becomes [2,5,4,7,6]. The array is now a valid arrangement. Thus, the answer is 3.
Example 2:
\n\nInput: nums = [2,4,5,7]
\n\nOutput: 1
\n\nExplanation:
\n\nBy swapping 4 and 5, the array becomes [2,5,4,7], which is a valid arrangement. Thus, the answer is 1.
Example 3:
\n\nInput: nums = [1,2,3]
\n\nOutput: 0
\n\nExplanation:
\n\nThe array is already a valid arrangement. Thus, no operations are needed.
\nExample 4:
\n\nInput: nums = [4,5,6,8]
\n\nOutput: -1
\n\nExplanation:
\n\nNo valid arrangement is possible. Thus, the answer is -1.
\n\n
Constraints:
\n\n1 <= nums.length <= 1051 <= nums[i] <= 109nums are distinct.给你一个由互不相同的整数组成的数组 nums 。
在一次操作中，你可以交换任意两个 相邻 元素。
\n\n在一个排列中，当所有相邻元素的奇偶性交替出现，我们认为该排列是 有效排列。这意味着每对相邻元素中一个是偶数，一个是奇数。
\n\n请返回将 nums 变成任意一种 有效排列 所需的最小相邻交换次数。
如果无法重排 nums 来获得有效排列，则返回 -1。
\n\n
示例 1：
\n\n输入： nums = [2,4,6,5,7]
\n\n输出：3
\n\n解释：
\n\n将 5 和 6 交换，数组变成 [2,4,5,6,7]
将 5 和 4 交换，数组变成 [2,5,4,6,7]
将 6 和 7 交换，数组变成 [2,5,4,7,6]。此时是一个有效排列。因此答案是 3。
示例 2：
\n\n输入： nums = [2,4,5,7]
\n\n输出： 1
\n\n解释：
\n\n将 4 和 5 交换，数组变成 [2,5,4,7]。此时是一个有效排列。因此答案是 1。
示例 3：
\n\n输入： nums = [1,2,3]
\n\n输出： 0
\n\n解释：
\n\n数组已经是有效排列，因此不需要任何操作。
\n示例 4：
\n\n输入： nums = [4,5,6,8]
\n\n输出：-1
\n\n解释：
\n\n没有任何一种排列可以满足奇偶交替的要求，因此返回 -1。
\n\n\n
提示：
\n\n1 <= nums.length <= 1051 <= nums[i] <= 109nums 中的所有元素都是 唯一 的evenCnt and oddCnt in nums. If abs(evenCnt - oddCnt) > 1, return -1 immediately.",
"Let n = len(nums). You’ll try at most two target parity‐patterns: one starting with even at index 0, one with odd at index 0.",
"If n is odd, only the pattern whose starting parity matches the larger of evenCnt or oddCnt is feasible. If n is even, both starting‐even and starting‐odd patterns are possible—compute both and take the minimum.",
"For a given target pattern, collect the indices of all even elements in nums (or odd elements) and the indices where an even (or odd) should go in the pattern.",
"The minimum adjacent‐swap cost to align those elements is the sum of absolute differences between each element’s current index and its target index.",
"Return the smallest cost over valid patterns."
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