leetcode-problemset/leetcode-cn/originData/find-the-least-frequent-digit.json

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        "question": {
            "questionId": "3994",
            "questionFrontendId": "3663",
            "categoryTitle": "Algorithms",
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            "title": "Find The Least Frequent Digit",
            "titleSlug": "find-the-least-frequent-digit",
            "content": "<p>Given an integer <code>n</code>, find the digit that occurs <strong>least</strong> frequently in its decimal representation. If multiple digits have the same frequency, choose the <strong>smallest</strong> digit.</p>\n\n<p>Return the chosen digit as an integer.</p>\nThe <strong>frequency</strong> of a digit <code>x</code> is the number of times it appears in the decimal representation of <code>n</code>.\n<p>&nbsp;</p>\n<p><strong class=\"example\">Example 1:</strong></p>\n\n<div class=\"example-block\">\n<p><strong>Input:</strong> <span class=\"example-io\">n = 1553322</span></p>\n\n<p><strong>Output:</strong> 1</p>\n\n<p><strong>Explanation:</strong></p>\n\n<p>The least frequent digit in <code>n</code> is 1, which appears only once. All other digits appear twice.</p>\n</div>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<div class=\"example-block\">\n<p><strong>Input:</strong> <span class=\"example-io\">n = 723344511</span></p>\n\n<p><strong>Output:</strong> 2</p>\n\n<p><strong>Explanation:</strong></p>\n\n<p>The least frequent digits in <code>n</code> are 7, 2, and 5; each appears only once.</p>\n</div>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= n &lt;= 2<sup>31</sup>​​​​​​​ - 1</code></li>\n</ul>\n",
            "translatedTitle": "出现频率最低的数字",
            "translatedContent": "<p>给你一个整数 <code>n</code>，找出在其十进制表示中出现频率&nbsp;<strong>最低&nbsp;</strong>的数字。如果多个数字的出现频率相同，则选择&nbsp;<strong>最小&nbsp;</strong>的那个数字。</p>\n\n<p>以整数形式返回所选的数字。</p>\n\n<p>数字 <code>x</code> 的出现频率是指它在&nbsp;<code>n</code> 的十进制表示中的出现次数。</p>\n\n<p>&nbsp;</p>\n\n<p><strong class=\"example\">示例 1:</strong></p>\n\n<div class=\"example-block\">\n<p><strong>输入：</strong> <span class=\"example-io\">n = 1553322</span></p>\n\n<p><strong>输出：</strong> 1</p>\n\n<p><strong>解释：</strong></p>\n\n<p>在 <code>n</code> 中，出现频率最低的数字是 1，它只出现了一次。所有其他数字都出现了两次。</p>\n</div>\n\n<p><strong class=\"example\">示例 2:</strong></p>\n\n<div class=\"example-block\">\n<p><strong>输入：</strong> <span class=\"example-io\">n = 723344511</span></p>\n\n<p><strong>输出：</strong> 2</p>\n\n<p><strong>解释：</strong></p>\n\n<p>在 <code>n</code> 中，出现频率最低的数字是 7、2 和 5，它们都只出现了一次。</p>\n</div>\n\n<p>&nbsp;</p>\n\n<p><strong>提示:</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= n &lt;= 2<sup>31</sup> - 1</code></li>\n</ul>\n",
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                    "code": "class Solution {\npublic:\n    int getLeastFrequentDigit(int n) {\n        \n    }\n};",
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                    "code": "class Solution(object):\n    def getLeastFrequentDigit(self, n):\n        \"\"\"\n        :type n: int\n        :rtype: int\n        \"\"\"\n        ",
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                    "code": "/**\n * @param {number} n\n * @return {number}\n */\nvar getLeastFrequentDigit = function(n) {\n    \n};",
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                    "code": "# @param {Integer} n\n# @return {Integer}\ndef get_least_frequent_digit(n)\n    \nend",
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                    "lang": "Elixir",
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                    "code": "defmodule Solution do\n  @spec get_least_frequent_digit(n :: integer) :: integer\n  def get_least_frequent_digit(n) do\n    \n  end\nend",
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