{ "data": { "question": { "questionId": "3994", "questionFrontendId": "3663", "categoryTitle": "Algorithms", "boundTopicId": 3767153, "title": "Find The Least Frequent Digit", "titleSlug": "find-the-least-frequent-digit", "content": "
Given an integer n
, find the digit that occurs least frequently in its decimal representation. If multiple digits have the same frequency, choose the smallest digit.
Return the chosen digit as an integer.
\nThe frequency of a digitx
is the number of times it appears in the decimal representation of n
.\n\n
Example 1:
\n\nInput: n = 1553322
\n\nOutput: 1
\n\nExplanation:
\n\nThe least frequent digit in n
is 1, which appears only once. All other digits appear twice.
Example 2:
\n\nInput: n = 723344511
\n\nOutput: 2
\n\nExplanation:
\n\nThe least frequent digits in n
are 7, 2, and 5; each appears only once.
\n
Constraints:
\n\n1 <= n <= 231 - 1
给你一个整数 n
,找出在其十进制表示中出现频率 最低 的数字。如果多个数字的出现频率相同,则选择 最小 的那个数字。
以整数形式返回所选的数字。
\n\n数字 x
的出现频率是指它在 n
的十进制表示中的出现次数。
\n\n
示例 1:
\n\n输入: n = 1553322
\n\n输出: 1
\n\n解释:
\n\n在 n
中,出现频率最低的数字是 1,它只出现了一次。所有其他数字都出现了两次。
示例 2:
\n\n输入: n = 723344511
\n\n输出: 2
\n\n解释:
\n\n在 n
中,出现频率最低的数字是 7、2 和 5,它们都只出现了一次。
\n\n
提示:
\n\n1 <= n <= 231 - 1
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