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"questionId" : "100305" ,
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"questionFrontendId" : "LCR 155" ,
"categoryTitle" : "Algorithms" ,
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"boundTopicId" : 87118 ,
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"title" : "将二叉搜索树转化为排序的双向链表" ,
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"titleSlug" : "er-cha-sou-suo-shu-yu-shuang-xiang-lian-biao-lcof" ,
"content" : "English description is not available for the problem. Please switch to Chinese." ,
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"translatedTitle" : "将二叉搜索树转化为排序的双向链表" ,
"translatedContent" : "<p>将一个 <strong>二叉搜索树</strong> 就地转化为一个 <strong>已排序的双向循环链表</strong> 。</p>\n\n<p>对于双向循环列表,你可以将左右孩子指针作为双向循环链表的前驱和后继指针,第一个节点的前驱是最后一个节点,最后一个节点的后继是第一个节点。</p>\n\n<p>特别地,我们希望可以 <strong>就地</strong> 完成转换操作。当转化完成以后,树中节点的左指针需要指向前驱,树中节点的右指针需要指向后继。还需要返回链表中最小元素的指针。</p>\n\n<p> </p>\n\n<p><strong>示例 1: </strong></p>\n\n<pre>\n<strong>输入:</strong>root = [4,2,5,1,3] \n\n<img src=\"https://assets.leetcode.com/uploads/2018/10/12/bstdllreturndll.png\" />\n<strong>输出:</strong>[1,2,3,4,5]\n\n<strong>解释:</strong>下图显示了转化后的二叉搜索树,实线表示后继关系,虚线表示前驱关系。\n<img src=\"https://assets.leetcode.com/uploads/2018/10/12/bstdllreturnbst.png\" />\n</pre>\n\n<p><strong>示例 2: </strong></p>\n\n<pre>\n<strong>输入:</strong>root = [2,1,3]\n<strong>输出:</strong>[1,2,3]\n</pre>\n\n<p><strong>示例 3: </strong></p>\n\n<pre>\n<strong>输入:</strong>root = []\n<strong>输出:</strong>[]\n<strong>解释:</strong>输入是空树,所以输出也是空链表。\n</pre>\n\n<p><strong>示例 4: </strong></p>\n\n<pre>\n<strong>输入:</strong>root = [1]\n<strong>输出:</strong>[1]\n</pre>\n\n<p> </p>\n\n<p><strong>提示:</strong></p>\n\n<ul>\n\t<li><code>-1000 <= Node.val <= 1000</code></li>\n\t<li><code>Node.left.val < Node.val < Node.right.val</code></li>\n\t<li><code>Node.val</code> 的所有值都是独一无二的</li>\n\t<li><code>0 <= Number of Nodes <= 2000</code></li>\n</ul>\n\n<p>注意:本题与主站 426 题相同:<a href=\"https://leetcode-cn.com/problems/convert-binary-search-tree-to-sorted-doubly-linked-list/\" rel=\"noopener noreferrer\" target=\"_blank\">https://leetcode-cn.com/problems/convert-binary-search-tree-to-sorted-doubly-linked-list/</a></p>\n" ,
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