{ "data": { "question": { "questionId": "100305", "questionFrontendId": "LCR 155", "categoryTitle": "Algorithms", "boundTopicId": 87118, "title": "将二叉搜索树转化为排序的双向链表", "titleSlug": "er-cha-sou-suo-shu-yu-shuang-xiang-lian-biao-lcof", "content": "English description is not available for the problem. Please switch to Chinese.", "translatedTitle": "将二叉搜索树转化为排序的双向链表", "translatedContent": "

将一个 二叉搜索树 就地转化为一个 已排序的双向循环链表 。

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对于双向循环列表，你可以将左右孩子指针作为双向循环链表的前驱和后继指针，第一个节点的前驱是最后一个节点，最后一个节点的后继是第一个节点。

\n\n

特别地，我们希望可以 就地 完成转换操作。当转化完成以后，树中节点的左指针需要指向前驱，树中节点的右指针需要指向后继。还需要返回链表中最小元素的指针。

\n\n

 

\n\n

示例 1：

\n\n
\n输入：root = [4,2,5,1,3] \n\n\n输出：[1,2,3,4,5]\n\n解释：下图显示了转化后的二叉搜索树，实线表示后继关系，虚线表示前驱关系。\n\n
\n\n

示例 2：

\n\n
\n输入：root = [2,1,3]\n输出：[1,2,3]\n
\n\n

示例 3：

\n\n
\n输入：root = []\n输出：[]\n解释：输入是空树，所以输出也是空链表。\n
\n\n

示例 4：

\n\n
\n输入：root = [1]\n输出：[1]\n
\n\n

 

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提示：

\n\n\n\n

注意：本题与主站 426 题相同：https://leetcode-cn.com/problems/convert-binary-search-tree-to-sorted-doubly-linked-list/

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