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45 lines
1.7 KiB
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45 lines
1.7 KiB
HTML
<p>Given an array <code>nums</code> sorted in <strong>non-decreasing</strong> order, return <em>the maximum between the number of positive integers and the number of negative integers.</em></p>
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<ul>
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<li>In other words, if the number of positive integers in <code>nums</code> is <code>pos</code> and the number of negative integers is <code>neg</code>, then return the maximum of <code>pos</code> and <code>neg</code>.</li>
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</ul>
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<p><strong>Note</strong> that <code>0</code> is neither positive nor negative.</p>
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<p> </p>
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<p><strong class="example">Example 1:</strong></p>
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<pre>
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<strong>Input:</strong> nums = [-2,-1,-1,1,2,3]
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<strong>Output:</strong> 3
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<strong>Explanation:</strong> There are 3 positive integers and 3 negative integers. The maximum count among them is 3.
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</pre>
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<p><strong class="example">Example 2:</strong></p>
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<pre>
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<strong>Input:</strong> nums = [-3,-2,-1,0,0,1,2]
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<strong>Output:</strong> 3
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<strong>Explanation:</strong> There are 2 positive integers and 3 negative integers. The maximum count among them is 3.
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</pre>
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<p><strong class="example">Example 3:</strong></p>
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<pre>
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<strong>Input:</strong> nums = [5,20,66,1314]
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<strong>Output:</strong> 4
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<strong>Explanation:</strong> There are 4 positive integers and 0 negative integers. The maximum count among them is 4.
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</pre>
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<p> </p>
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<p><strong>Constraints:</strong></p>
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<ul>
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<li><code>1 <= nums.length <= 2000</code></li>
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<li><code>-2000 <= nums[i] <= 2000</code></li>
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<li><code>nums</code> is sorted in a <strong>non-decreasing order</strong>.</li>
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</ul>
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<p> </p>
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<p><strong>Follow up:</strong> Can you solve the problem in <code>O(log(n))</code> time complexity?</p>
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