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leetcode-problemset/leetcode-cn/problem (Chinese)/项目员工 I [project-employees-i].html
2023-12-09 18:53:53 +08:00

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<p>项目表&nbsp;<code>Project</code>&nbsp;</p>
<pre>
+-------------+---------+
| Column Name | Type |
+-------------+---------+
| project_id | int |
| employee_id | int |
+-------------+---------+
主键为 (project_id, employee_id)。
employee_id 是员工表 <code>Employee 表的外键。</code>
</pre>
<p>员工表&nbsp;<code>Employee</code></p>
<pre>
+------------------+---------+
| Column Name | Type |
+------------------+---------+
| employee_id | int |
| name | varchar |
| experience_years | int |
+------------------+---------+
主键是 employee_id。
</pre>
<p>&nbsp;</p>
<p>请写一个 SQL&nbsp;语句,查询每一个项目中员工的&nbsp;<strong>平均&nbsp;</strong>工作年限,<strong>精确到小数点后两位</strong></p>
<p>查询结果的格式如下:</p>
<pre>
Project 表:
+-------------+-------------+
| project_id | employee_id |
+-------------+-------------+
| 1 | 1 |
| 1 | 2 |
| 1 | 3 |
| 2 | 1 |
| 2 | 4 |
+-------------+-------------+
Employee 表:
+-------------+--------+------------------+
| employee_id | name | experience_years |
+-------------+--------+------------------+
| 1 | Khaled | 3 |
| 2 | Ali | 2 |
| 3 | John | 1 |
| 4 | Doe | 2 |
+-------------+--------+------------------+
Result 表:
+-------------+---------------+
| project_id | average_years |
+-------------+---------------+
| 1 | 2.00 |
| 2 | 2.50 |
+-------------+---------------+
第一个项目中,员工的平均工作年限是 (3 + 2 + 1) / 3 = 2.00;第二个项目中,员工的平均工作年限是 (3 + 2) / 2 = 2.50
</pre>