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leetcode-problemset/leetcode/problem/sort-array-by-parity-ii.html

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<p>Given an array of integers <code>nums</code>, half of the integers in <code>nums</code> are <strong>odd</strong>, and the other half are <strong>even</strong>.</p>
<p>Sort the array so that whenever <code>nums[i]</code> is odd, <code>i</code> is <strong>odd</strong>, and whenever <code>nums[i]</code> is even, <code>i</code> is <strong>even</strong>.</p>
<p>Return <em>any answer array that satisfies this condition</em>.</p>
<p>&nbsp;</p>
<p><strong class="example">Example 1:</strong></p>
<pre>
<strong>Input:</strong> nums = [4,2,5,7]
<strong>Output:</strong> [4,5,2,7]
<strong>Explanation:</strong> [4,7,2,5], [2,5,4,7], [2,7,4,5] would also have been accepted.
</pre>
<p><strong class="example">Example 2:</strong></p>
<pre>
<strong>Input:</strong> nums = [2,3]
<strong>Output:</strong> [2,3]
</pre>
<p>&nbsp;</p>
<p><strong>Constraints:</strong></p>
<ul>
<li><code>2 &lt;= nums.length &lt;= 2 * 10<sup>4</sup></code></li>
<li><code>nums.length</code> is even.</li>
<li>Half of the integers in <code>nums</code> are even.</li>
<li><code>0 &lt;= nums[i] &lt;= 1000</code></li>
</ul>
<p>&nbsp;</p>
<p><strong>Follow Up:</strong> Could you solve it in-place?</p>