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25 lines
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25 lines
1.0 KiB
HTML
<p>Given the <code>root</code> of a binary search tree, rearrange the tree in <strong>in-order</strong> so that the leftmost node in the tree is now the root of the tree, and every node has no left child and only one right child.</p>
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<p> </p>
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<p><strong class="example">Example 1:</strong></p>
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<img alt="" src="https://assets.leetcode.com/uploads/2020/11/17/ex1.jpg" style="width: 600px; height: 350px;" />
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<pre>
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<strong>Input:</strong> root = [5,3,6,2,4,null,8,1,null,null,null,7,9]
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<strong>Output:</strong> [1,null,2,null,3,null,4,null,5,null,6,null,7,null,8,null,9]
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</pre>
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<p><strong class="example">Example 2:</strong></p>
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<img alt="" src="https://assets.leetcode.com/uploads/2020/11/17/ex2.jpg" style="width: 300px; height: 114px;" />
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<pre>
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<strong>Input:</strong> root = [5,1,7]
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<strong>Output:</strong> [1,null,5,null,7]
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</pre>
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<p> </p>
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<p><strong>Constraints:</strong></p>
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<ul>
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<li>The number of nodes in the given tree will be in the range <code>[1, 100]</code>.</li>
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<li><code>0 <= Node.val <= 1000</code></li>
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</ul>
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