leetcode-problemset/leetcode/originData/maximum-total-importance-of-roads.json

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            "title": "Maximum Total Importance of Roads",
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            "content": "<p>You are given an integer <code>n</code> denoting the number of cities in a country. The cities are numbered from <code>0</code> to <code>n - 1</code>.</p>\n\n<p>You are also given a 2D integer array <code>roads</code> where <code>roads[i] = [a<sub>i</sub>, b<sub>i</sub>]</code> denotes that there exists a <strong>bidirectional</strong> road connecting cities <code>a<sub>i</sub></code> and <code>b<sub>i</sub></code>.</p>\n\n<p>You need to assign each city with an integer value from <code>1</code> to <code>n</code>, where each value can only be used <strong>once</strong>. The <strong>importance</strong> of a road is then defined as the <strong>sum</strong> of the values of the two cities it connects.</p>\n\n<p>Return <em>the <strong>maximum total importance</strong> of all roads possible after assigning the values optimally.</em></p>\n\n<p>&nbsp;</p>\n<p><strong>Example 1:</strong></p>\n<img alt=\"\" src=\"https://assets.leetcode.com/uploads/2022/04/07/ex1drawio.png\" style=\"width: 290px; height: 215px;\" />\n<pre>\n<strong>Input:</strong> n = 5, roads = [[0,1],[1,2],[2,3],[0,2],[1,3],[2,4]]\n<strong>Output:</strong> 43\n<strong>Explanation:</strong> The figure above shows the country and the assigned values of [2,4,5,3,1].\n- The road (0,1) has an importance of 2 + 4 = 6.\n- The road (1,2) has an importance of 4 + 5 = 9.\n- The road (2,3) has an importance of 5 + 3 = 8.\n- The road (0,2) has an importance of 2 + 5 = 7.\n- The road (1,3) has an importance of 4 + 3 = 7.\n- The road (2,4) has an importance of 5 + 1 = 6.\nThe total importance of all roads is 6 + 9 + 8 + 7 + 7 + 6 = 43.\nIt can be shown that we cannot obtain a greater total importance than 43.\n</pre>\n\n<p><strong>Example 2:</strong></p>\n<img alt=\"\" src=\"https://assets.leetcode.com/uploads/2022/04/07/ex2drawio.png\" style=\"width: 281px; height: 151px;\" />\n<pre>\n<strong>Input:</strong> n = 5, roads = [[0,3],[2,4],[1,3]]\n<strong>Output:</strong> 20\n<strong>Explanation:</strong> The figure above shows the country and the assigned values of [4,3,2,5,1].\n- The road (0,3) has an importance of 4 + 5 = 9.\n- The road (2,4) has an importance of 2 + 1 = 3.\n- The road (1,3) has an importance of 3 + 5 = 8.\nThe total importance of all roads is 9 + 3 + 8 = 20.\nIt can be shown that we cannot obtain a greater total importance than 20.\n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>2 &lt;= n &lt;= 5 * 10<sup>4</sup></code></li>\n\t<li><code>1 &lt;= roads.length &lt;= 5 * 10<sup>4</sup></code></li>\n\t<li><code>roads[i].length == 2</code></li>\n\t<li><code>0 &lt;= a<sub>i</sub>, b<sub>i</sub> &lt;= n - 1</code></li>\n\t<li><code>a<sub>i</sub> != b<sub>i</sub></code></li>\n\t<li>There are no duplicate roads.</li>\n</ul>\n",
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                    "code": "class Solution(object):\n    def maximumImportance(self, n, roads):\n        \"\"\"\n        :type n: int\n        :type roads: List[List[int]]\n        :rtype: int\n        \"\"\"\n        ",
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                    "code": "# @param {Integer} n\n# @param {Integer[][]} roads\n# @return {Integer}\ndef maximum_importance(n, roads)\n    \nend",
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                "Consider what each city contributes to the total importance of all roads.",
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