mirror of
https://gitee.com/coder-xiaomo/leetcode-problemset
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181 lines
16 KiB
JSON
181 lines
16 KiB
JSON
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"title": "Jump Game III",
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"content": "<p>Given an array of non-negative integers <code>arr</code>, you are initially positioned at <code>start</code> index of the array. When you are at index <code>i</code>, you can jump to <code>i + arr[i]</code> or <code>i - arr[i]</code>, check if you can reach to <strong>any</strong> index with value 0.</p>\n\n<p>Notice that you can not jump outside of the array at any time.</p>\n\n<p> </p>\n<p><strong>Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> arr = [4,2,3,0,3,1,2], start = 5\n<strong>Output:</strong> true\n<strong>Explanation:</strong> \nAll possible ways to reach at index 3 with value 0 are: \nindex 5 -> index 4 -> index 1 -> index 3 \nindex 5 -> index 6 -> index 4 -> index 1 -> index 3 \n</pre>\n\n<p><strong>Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> arr = [4,2,3,0,3,1,2], start = 0\n<strong>Output:</strong> true \n<strong>Explanation: \n</strong>One possible way to reach at index 3 with value 0 is: \nindex 0 -> index 4 -> index 1 -> index 3\n</pre>\n\n<p><strong>Example 3:</strong></p>\n\n<pre>\n<strong>Input:</strong> arr = [3,0,2,1,2], start = 2\n<strong>Output:</strong> false\n<strong>Explanation: </strong>There is no way to reach at index 1 with value 0.\n</pre>\n\n<p> </p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>1 <= arr.length <= 5 * 10<sup>4</sup></code></li>\n\t<li><code>0 <= arr[i] < arr.length</code></li>\n\t<li><code>0 <= start < arr.length</code></li>\n</ul>\n",
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"difficulty": "Medium",
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"exampleTestcases": "[4,2,3,0,3,1,2]\n5\n[4,2,3,0,3,1,2]\n0\n[3,0,2,1,2]\n2",
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"categoryTitle": "Algorithms",
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"code": "# @param {Integer[]} arr\n# @param {Integer} start\n# @return {Boolean}\ndef can_reach(arr, start)\n \nend",
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"code": "-spec can_reach(Arr :: [integer()], Start :: integer()) -> boolean().\ncan_reach(Arr, Start) ->\n .",
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"hints": [
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"Think of BFS to solve the problem.",
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"When you reach a position with a value = 0 then return true."
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],
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"solution": {
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