mirror of
				https://gitee.com/coder-xiaomo/leetcode-problemset
				synced 2025-10-26 07:18:56 +08:00 
			
		
		
		
	
		
			
				
	
	
		
			47 lines
		
	
	
		
			2.3 KiB
		
	
	
	
		
			HTML
		
	
	
	
	
	
			
		
		
	
	
			47 lines
		
	
	
		
			2.3 KiB
		
	
	
	
		
			HTML
		
	
	
	
	
	
| <p>Design an algorithm that accepts a stream of integers and retrieves the product of the last <code>k</code> integers of the stream.</p>
 | |
| 
 | |
| <p>Implement the <code>ProductOfNumbers</code> class:</p>
 | |
| 
 | |
| <ul>
 | |
| 	<li><code>ProductOfNumbers()</code> Initializes the object with an empty stream.</li>
 | |
| 	<li><code>void add(int num)</code> Appends the integer <code>num</code> to the stream.</li>
 | |
| 	<li><code>int getProduct(int k)</code> Returns the product of the last <code>k</code> numbers in the current list. You can assume that always the current list has at least <code>k</code> numbers.</li>
 | |
| </ul>
 | |
| 
 | |
| <p>The test cases are generated so that, at any time, the product of any contiguous sequence of numbers will fit into a single 32-bit integer without overflowing.</p>
 | |
| 
 | |
| <p> </p>
 | |
| <p><strong>Example:</strong></p>
 | |
| 
 | |
| <pre>
 | |
| <strong>Input</strong>
 | |
| ["ProductOfNumbers","add","add","add","add","add","getProduct","getProduct","getProduct","add","getProduct"]
 | |
| [[],[3],[0],[2],[5],[4],[2],[3],[4],[8],[2]]
 | |
| 
 | |
| <strong>Output</strong>
 | |
| [null,null,null,null,null,null,20,40,0,null,32]
 | |
| 
 | |
| <strong>Explanation</strong>
 | |
| ProductOfNumbers productOfNumbers = new ProductOfNumbers();
 | |
| productOfNumbers.add(3);        // [3]
 | |
| productOfNumbers.add(0);        // [3,0]
 | |
| productOfNumbers.add(2);        // [3,0,2]
 | |
| productOfNumbers.add(5);        // [3,0,2,5]
 | |
| productOfNumbers.add(4);        // [3,0,2,5,4]
 | |
| productOfNumbers.getProduct(2); // return 20. The product of the last 2 numbers is 5 * 4 = 20
 | |
| productOfNumbers.getProduct(3); // return 40. The product of the last 3 numbers is 2 * 5 * 4 = 40
 | |
| productOfNumbers.getProduct(4); // return 0. The product of the last 4 numbers is 0 * 2 * 5 * 4 = 0
 | |
| productOfNumbers.add(8);        // [3,0,2,5,4,8]
 | |
| productOfNumbers.getProduct(2); // return 32. The product of the last 2 numbers is 4 * 8 = 32 
 | |
| </pre>
 | |
| 
 | |
| <p> </p>
 | |
| <p><strong>Constraints:</strong></p>
 | |
| 
 | |
| <ul>
 | |
| 	<li><code>0 <= num <= 100</code></li>
 | |
| 	<li><code>1 <= k <= 4 * 10<sup>4</sup></code></li>
 | |
| 	<li>At most <code>4 * 10<sup>4</sup></code> calls will be made to <code>add</code> and <code>getProduct</code>.</li>
 | |
| 	<li>The product of the stream at any point in time will fit in a <strong>32-bit</strong> integer.</li>
 | |
| </ul>
 |