leetcode-problemset/leetcode-cn/originData/maximum-rows-covered-by-columns.json

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        "question": {
            "questionId": "2482",
            "questionFrontendId": "6173",
            "categoryTitle": "Algorithms",
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            "title": "Maximum Rows Covered by Columns",
            "titleSlug": "maximum-rows-covered-by-columns",
            "content": "<p>You are given a <strong>0-indexed</strong> <code>m x n</code> binary matrix <code>mat</code> and an integer <code>cols</code>, which denotes the number of columns you must choose.</p>\n\n<p>A row is <strong>covered</strong> by a set of columns if each cell in the row that has a value of <code>1</code> also lies in one of the columns of the chosen set.</p>\n\n<p>Return <em>the <strong>maximum</strong> number of rows that can be <strong>covered</strong> by a set of </em><code>cols</code><em> columns.</em></p>\n\n<p>&nbsp;</p>\n<p><strong>Example 1:</strong></p>\n\n<p><strong><img alt=\"\" src=\"https://assets.leetcode.com/uploads/2022/07/14/rowscovered.png\" style=\"width: 250px; height: 417px;\" /></strong></p>\n\n<pre>\n<strong>Input:</strong> mat = [[0,0,0],[1,0,1],[0,1,1],[0,0,1]], cols = 2\n<strong>Output:</strong> 3\n<strong>Explanation:</strong>\nAs shown in the diagram above, one possible way of covering 3 rows is by selecting the 0th and 2nd columns.\nIt can be shown that no more than 3 rows can be covered, so we return 3.\n</pre>\n\n<p><strong>Example 2:</strong></p>\n\n<p><strong><img alt=\"\" src=\"https://assets.leetcode.com/uploads/2022/07/14/rowscovered2.png\" style=\"width: 83px; height: 247px;\" /></strong></p>\n\n<pre>\n<strong>Input:</strong> mat = [[1],[0]], cols = 1\n<strong>Output:</strong> 2\n<strong>Explanation:</strong>\nSelecting the only column will result in both rows being covered, since the entire matrix is selected.\nTherefore, we return 2.\n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>m == mat.length</code></li>\n\t<li><code>n == mat[i].length</code></li>\n\t<li><code>1 &lt;= m, n &lt;= 12</code></li>\n\t<li><code>mat[i][j]</code> is either <code>0</code> or <code>1</code>.</li>\n\t<li><code>1 &lt;= cols &lt;= n</code></li>\n</ul>\n",
            "translatedTitle": "被列覆盖的最多行数",
            "translatedContent": "<p>给你一个下标从 <strong>0</strong>&nbsp;开始的&nbsp;<code>m x n</code>&nbsp;二进制矩阵&nbsp;<code>mat</code>&nbsp;和一个整数&nbsp;<code>cols</code>&nbsp;，表示你需要选出的列数。</p>\n\n<p>如果一行中，所有的 <code>1</code> 都被你选中的列所覆盖，那么我们称这一行 <strong>被覆盖</strong>&nbsp;了。</p>\n\n<p>请你返回在选择 <code>cols</code>&nbsp;列的情况下，<strong>被覆盖</strong>&nbsp;的行数 <strong>最大</strong>&nbsp;为多少。</p>\n\n<p>&nbsp;</p>\n\n<p><strong>示例 1：</strong></p>\n\n<p><strong><img alt=\"\" src=\"https://assets.leetcode.com/uploads/2022/07/14/rowscovered.png\" style=\"width: 250px; height: 417px;\"></strong></p>\n\n<pre><b>输入：</b>mat = [[0,0,0],[1,0,1],[0,1,1],[0,0,1]], cols = 2\n<b>输出：</b>3\n<strong>解释：</strong>\n如上图所示，覆盖 3 行的一种可行办法是选择第 0 和第 2 列。\n可以看出，不存在大于 3 行被覆盖的方案，所以我们返回 3 。\n</pre>\n\n<p><strong>示例 2：</strong></p>\n\n<p><strong><img alt=\"\" src=\"https://assets.leetcode.com/uploads/2022/07/14/rowscovered2.png\" style=\"width: 83px; height: 247px;\"></strong></p>\n\n<pre><b>输入：</b>mat = [[1],[0]], cols = 1\n<b>输出：</b>2\n<strong>解释：</strong>\n选择唯一的一列，两行都被覆盖了，原因是整个矩阵都被覆盖了。\n所以我们返回 2 。\n</pre>\n\n<p>&nbsp;</p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code>m == mat.length</code></li>\n\t<li><code>n == mat[i].length</code></li>\n\t<li><code>1 &lt;= m, n &lt;= 12</code></li>\n\t<li><code>mat[i][j]</code>&nbsp;要么是&nbsp;<code>0</code>&nbsp;要么是&nbsp;<code>1</code>&nbsp;。</li>\n\t<li><code>1 &lt;= cols &lt;= n</code></li>\n</ul>\n",
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