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"question": {
"questionId": "1000315",
"questionFrontendId": "剑指 Offer II 054",
"categoryTitle": "LCOF2",
"boundTopicId": 910309,
"title": "所有大于等于节点的值之和",
"titleSlug": "w6cpku",
"content": "<p>English description is not available for the problem. Please switch to Chinese.</p>\n",
"translatedTitle": "所有大于等于节点的值之和",
"translatedContent": "<p><span style=\"font-size:10.5pt\"><span style=\"font-family:Calibri\"><span style=\"font-size:10.5000pt\"><span style=\"font-family:宋体\"><font face=\"宋体\">给定一个二叉搜索树,请将它的每个</font></span></span></span></span>节点<span style=\"font-size:10.5pt\"><span style=\"font-family:Calibri\"><span style=\"font-size:10.5000pt\"><span style=\"font-family:宋体\"><font face=\"宋体\">的值替换成树中大于或者等于该</font></span></span></span></span>节点<span style=\"font-size:10.5pt\"><span style=\"font-family:Calibri\"><span style=\"font-size:10.5000pt\"><span style=\"font-family:宋体\"><font face=\"宋体\">值的所有</font></span></span></span></span>节点<span style=\"font-size:10.5pt\"><span style=\"font-family:Calibri\"><span style=\"font-size:10.5000pt\"><span style=\"font-family:宋体\"><font face=\"宋体\">值之和。</font></span></span></span></span></p>\n\n<p style=\"margin:0pt 0pt 0.0001pt; text-align:justify\">&nbsp;</p>\n\n<p>提醒一下,二叉搜索树满足下列约束条件:</p>\n\n<ul>\n\t<li>节点的左子树仅包含键<strong> 小于 </strong>节点键的节点。</li>\n\t<li>节点的右子树仅包含键<strong> 大于</strong> 节点键的节点。</li>\n\t<li>左右子树也必须是二叉搜索树。</li>\n</ul>\n\n<p>&nbsp;</p>\n\n<p><strong>示例 1</strong></p>\n\n<p><strong><img alt=\"\" src=\"https://assets.leetcode-cn.com/aliyun-lc-upload/uploads/2019/05/03/tree.png\" style=\"height: 364px; width: 534px;\" /></strong></p>\n\n<pre>\n<strong>输入:</strong>root<strong> </strong>=<strong> </strong>[4,1,6,0,2,5,7,null,null,null,3,null,null,null,8]\n<strong>输出:</strong>[30,36,21,36,35,26,15,null,null,null,33,null,null,null,8]\n</pre>\n\n<p><strong>示例 2</strong></p>\n\n<pre>\n<strong>输入:</strong>root = [0,null,1]\n<strong>输出:</strong>[1,null,1]\n</pre>\n\n<p><strong>示例 3</strong></p>\n\n<pre>\n<strong>输入:</strong>root = [1,0,2]\n<strong>输出:</strong>[3,3,2]\n</pre>\n\n<p><strong>示例 4</strong></p>\n\n<pre>\n<strong>输入:</strong>root = [3,2,4,1]\n<strong>输出:</strong>[7,9,4,10]\n</pre>\n\n<p>&nbsp;</p>\n\n<p><strong>提示:</strong></p>\n\n<ul>\n\t<li>树中的节点数介于 <code>0</code>&nbsp;和 <code>10<sup>4</sup></code><sup>&nbsp;</sup>之间。</li>\n\t<li>每个节点的值介于 <code>-10<sup>4</sup></code>&nbsp;和&nbsp;<code>10<sup>4</sup></code>&nbsp;之间。</li>\n\t<li>树中的所有值 <strong>互不相同</strong> 。</li>\n\t<li>给定的树为二叉搜索树。</li>\n</ul>\n\n<p>&nbsp;</p>\n\n<p><meta charset=\"UTF-8\" />注意:</p>\n\n<ul>\n\t<li>本题与主站 538&nbsp;题相同:&nbsp;<a href=\"https://leetcode-cn.com/problems/convert-bst-to-greater-tree/\">https://leetcode-cn.com/problems/convert-bst-to-greater-tree/</a></li>\n\t<li>本题与主站 1038&nbsp;题相同:<a href=\"https://leetcode-cn.com/problems/binary-search-tree-to-greater-sum-tree/\">https://leetcode-cn.com/problems/binary-search-tree-to-greater-sum-tree/</a></li>\n</ul>\n",
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"code": "/**\n * Definition for a binary tree node.\n * struct TreeNode {\n * int val;\n * TreeNode *left;\n * TreeNode *right;\n * TreeNode() : val(0), left(nullptr), right(nullptr) {}\n * TreeNode(int x) : val(x), left(nullptr), right(nullptr) {}\n * TreeNode(int x, TreeNode *left, TreeNode *right) : val(x), left(left), right(right) {}\n * };\n */\nclass Solution {\npublic:\n TreeNode* convertBST(TreeNode* root) {\n\n }\n};",
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"code": "/**\n * Definition for a binary tree node.\n * function TreeNode(val, left, right) {\n * this.val = (val===undefined ? 0 : val)\n * this.left = (left===undefined ? null : left)\n * this.right = (right===undefined ? null : right)\n * }\n */\n/**\n * @param {TreeNode} root\n * @return {TreeNode}\n */\nvar convertBST = function(root) {\n\n};",
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"code": "/**\n * Example:\n * var ti = TreeNode(5)\n * var v = ti.`val`\n * Definition for a binary tree node.\n * class TreeNode(var `val`: Int) {\n * var left: TreeNode? = null\n * var right: TreeNode? = null\n * }\n */\nclass Solution {\n fun convertBST(root: TreeNode?): TreeNode? {\n\n }\n}",
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"code": "// Definition for a binary tree node.\n// #[derive(Debug, PartialEq, Eq)]\n// pub struct TreeNode {\n// pub val: i32,\n// pub left: Option<Rc<RefCell<TreeNode>>>,\n// pub right: Option<Rc<RefCell<TreeNode>>>,\n// }\n//\n// impl TreeNode {\n// #[inline]\n// pub fn new(val: i32) -> Self {\n// TreeNode {\n// val,\n// left: None,\n// right: None\n// }\n// }\n// }\nuse std::rc::Rc;\nuse std::cell::RefCell;\nimpl Solution {\n pub fn convert_bst(root: Option<Rc<RefCell<TreeNode>>>) -> Option<Rc<RefCell<TreeNode>>> {\n\n }\n}",
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1.17<\\/code><\\/p>\\r\\n\\r\\n<p>\\u652f\\u6301 <a href=\\\"https:\\/\\/godoc.org\\/github.com\\/emirpasic\\/gods\\\" target=\\\"_blank\\\">https:\\/\\/godoc.org\\/github.com\\/emirpasic\\/gods<\\/a> \\u7b2c\\u4e09\\u65b9\\u5e93\\u3002<\\/p>\"],\"python3\":[\"Python3\",\"<p>\\u7248\\u672c\\uff1a<code>Python 3.10<\\/code><\\/p>\\r\\n\\r\\n<p>\\u4e3a\\u4e86\\u65b9\\u4fbf\\u8d77\\u89c1\\uff0c\\u5927\\u90e8\\u5206\\u5e38\\u7528\\u5e93\\u5df2\\u7ecf\\u88ab\\u81ea\\u52a8 \\u5bfc\\u5165\\uff0c\\u5982<a href=\\\"https:\\/\\/docs.python.org\\/3\\/library\\/array.html\\\" target=\\\"_blank\\\">array<\\/a>, <a href=\\\"https:\\/\\/docs.python.org\\/3\\/library\\/bisect.html\\\" target=\\\"_blank\\\">bisect<\\/a>, <a href=\\\"https:\\/\\/docs.python.org\\/3\\/library\\/collections.html\\\" target=\\\"_blank\\\">collections<\\/a>\\u3002 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