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leetcode-problemset/leetcode-cn/originData/cong-wei-dao-tou-da-yin-lian-biao-lcof.json
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{
"data": {
"question": {
"questionId": "100282",
"questionFrontendId": "剑指 Offer 06",
"categoryTitle": "LCOF",
"boundTopicId": 85499,
"title": "从尾到头打印链表 LCOF",
"titleSlug": "cong-wei-dao-tou-da-yin-lian-biao-lcof",
"content": "<p>English description is not available for the problem. Please switch to Chinese.</p>",
"translatedTitle": "从尾到头打印链表",
"translatedContent": "<p>输入一个链表的头节点,从尾到头反过来返回每个节点的值(用数组返回)。</p>\n\n<p>&nbsp;</p>\n\n<p><strong>示例 1</strong></p>\n\n<pre><strong>输入:</strong>head = [1,3,2]\n<strong>输出:</strong>[2,3,1]</pre>\n\n<p>&nbsp;</p>\n\n<p><strong>限制:</strong></p>\n\n<p><code>0 &lt;= 链表长度 &lt;= 10000</code></p>\n",
"isPaidOnly": false,
"difficulty": "Easy",
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"dislikes": 0,
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"code": "/**\n * Definition for singly-linked list.\n * public class ListNode {\n * int val;\n * ListNode next;\n * ListNode(int x) { val = x; }\n * }\n */\nclass Solution {\n public int[] reversePrint(ListNode head) {\n\n }\n}",
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"code": "# Definition for singly-linked list.\n# class ListNode(object):\n# def __init__(self, x):\n# self.val = x\n# self.next = None\n\nclass Solution(object):\n def reversePrint(self, head):\n \"\"\"\n :type head: ListNode\n :rtype: List[int]\n \"\"\"",
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"code": "/**\n * Definition for singly-linked list.\n * function ListNode(val) {\n * this.val = val;\n * this.next = null;\n * }\n */\n/**\n * @param {ListNode} head\n * @return {number[]}\n */\nvar reversePrint = function(head) {\n\n};",
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"code": "// Definition for singly-linked list.\n// #[derive(PartialEq, Eq, Clone, Debug)]\n// pub struct ListNode {\n// pub val: i32,\n// pub next: Option<Box<ListNode>>\n// }\n// \n// impl ListNode {\n// #[inline]\n// fn new(val: i32) -> Self {\n// ListNode {\n// next: None,\n// val\n// }\n// }\n// }\nimpl Solution {\n pub fn reverse_print(head: Option<Box<ListNode>>) -> Vec<i32> {\n\n }\n}",
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