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43 lines
2.0 KiB
HTML
<p>You have <code>k</code> bags. You are given a <strong>0-indexed</strong> integer array <code>weights</code> where <code>weights[i]</code> is the weight of the <code>i<sup>th</sup></code> marble. You are also given the integer <code>k.</code></p>
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<p>Divide the marbles into the <code>k</code> bags according to the following rules:</p>
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<ul>
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<li>No bag is empty.</li>
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<li>If the <code>i<sup>th</sup></code> marble and <code>j<sup>th</sup></code> marble are in a bag, then all marbles with an index between the <code>i<sup>th</sup></code> and <code>j<sup>th</sup></code> indices should also be in that same bag.</li>
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<li>If a bag consists of all the marbles with an index from <code>i</code> to <code>j</code> inclusively, then the cost of the bag is <code>weights[i] + weights[j]</code>.</li>
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</ul>
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<p>The <strong>score</strong> after distributing the marbles is the sum of the costs of all the <code>k</code> bags.</p>
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<p>Return <em>the <strong>difference</strong> between the <strong>maximum</strong> and <strong>minimum</strong> scores among marble distributions</em>.</p>
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<p> </p>
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<p><strong class="example">Example 1:</strong></p>
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<pre>
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<strong>Input:</strong> weights = [1,3,5,1], k = 2
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<strong>Output:</strong> 4
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<strong>Explanation:</strong>
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The distribution [1],[3,5,1] results in the minimal score of (1+1) + (3+1) = 6.
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The distribution [1,3],[5,1], results in the maximal score of (1+3) + (5+1) = 10.
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Thus, we return their difference 10 - 6 = 4.
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</pre>
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<p><strong class="example">Example 2:</strong></p>
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<pre>
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<strong>Input:</strong> weights = [1, 3], k = 2
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<strong>Output:</strong> 0
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<strong>Explanation:</strong> The only distribution possible is [1],[3].
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Since both the maximal and minimal score are the same, we return 0.
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</pre>
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<p> </p>
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<p><strong>Constraints:</strong></p>
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<ul>
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<li><code>1 <= k <= weights.length <= 10<sup>5</sup></code></li>
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<li><code>1 <= weights[i] <= 10<sup>9</sup></code></li>
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</ul>
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