mirror of
https://gitee.com/coder-xiaomo/leetcode-problemset
synced 2025-01-10 18:48:13 +08:00
35 lines
1.6 KiB
HTML
35 lines
1.6 KiB
HTML
<p>You are given an array of non-negative integers <code>nums</code> and an integer <code>k</code>. In one operation, you may choose <strong>any</strong> element from <code>nums</code> and <strong>increment</strong> it by <code>1</code>.</p>
|
|
|
|
<p>Return<em> the <strong>maximum</strong> <strong>product</strong> of </em><code>nums</code><em> after <strong>at most</strong> </em><code>k</code><em> operations. </em>Since the answer may be very large, return it <b>modulo</b> <code>10<sup>9</sup> + 7</code>. Note that you should maximize the product before taking the modulo. </p>
|
|
|
|
<p> </p>
|
|
<p><strong>Example 1:</strong></p>
|
|
|
|
<pre>
|
|
<strong>Input:</strong> nums = [0,4], k = 5
|
|
<strong>Output:</strong> 20
|
|
<strong>Explanation:</strong> Increment the first number 5 times.
|
|
Now nums = [5, 4], with a product of 5 * 4 = 20.
|
|
It can be shown that 20 is maximum product possible, so we return 20.
|
|
Note that there may be other ways to increment nums to have the maximum product.
|
|
</pre>
|
|
|
|
<p><strong>Example 2:</strong></p>
|
|
|
|
<pre>
|
|
<strong>Input:</strong> nums = [6,3,3,2], k = 2
|
|
<strong>Output:</strong> 216
|
|
<strong>Explanation:</strong> Increment the second number 1 time and increment the fourth number 1 time.
|
|
Now nums = [6, 4, 3, 3], with a product of 6 * 4 * 3 * 3 = 216.
|
|
It can be shown that 216 is maximum product possible, so we return 216.
|
|
Note that there may be other ways to increment nums to have the maximum product.
|
|
</pre>
|
|
|
|
<p> </p>
|
|
<p><strong>Constraints:</strong></p>
|
|
|
|
<ul>
|
|
<li><code>1 <= nums.length, k <= 10<sup>5</sup></code></li>
|
|
<li><code>0 <= nums[i] <= 10<sup>6</sup></code></li>
|
|
</ul>
|