mirror of
https://gitee.com/coder-xiaomo/leetcode-problemset
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161 lines
18 KiB
JSON
161 lines
18 KiB
JSON
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"questionId": "3309",
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"questionFrontendId": "3042",
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"title": "Count Prefix and Suffix Pairs I",
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"titleSlug": "count-prefix-and-suffix-pairs-i",
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"content": "<p>You are given a <strong>0-indexed</strong> string array <code>words</code>.</p>\n\n<p>Let's define a <strong>boolean</strong> function <code>isPrefixAndSuffix</code> that takes two strings, <code>str1</code> and <code>str2</code>:</p>\n\n<ul>\n\t<li><code>isPrefixAndSuffix(str1, str2)</code> returns <code>true</code> if <code>str1</code> is <strong>both</strong> a <span data-keyword=\"string-prefix\">prefix</span> and a <span data-keyword=\"string-suffix\">suffix</span> of <code>str2</code>, and <code>false</code> otherwise.</li>\n</ul>\n\n<p>For example, <code>isPrefixAndSuffix("aba", "ababa")</code> is <code>true</code> because <code>"aba"</code> is a prefix of <code>"ababa"</code> and also a suffix, but <code>isPrefixAndSuffix("abc", "abcd")</code> is <code>false</code>.</p>\n\n<p>Return <em>an integer denoting the <strong>number</strong> of index pairs </em><code>(i, j)</code><em> such that </em><code>i < j</code><em>, and </em><code>isPrefixAndSuffix(words[i], words[j])</code><em> is </em><code>true</code><em>.</em></p>\n\n<p> </p>\n<p><strong class=\"example\">Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> words = ["a","aba","ababa","aa"]\n<strong>Output:</strong> 4\n<strong>Explanation:</strong> In this example, the counted index pairs are:\ni = 0 and j = 1 because isPrefixAndSuffix("a", "aba") is true.\ni = 0 and j = 2 because isPrefixAndSuffix("a", "ababa") is true.\ni = 0 and j = 3 because isPrefixAndSuffix("a", "aa") is true.\ni = 1 and j = 2 because isPrefixAndSuffix("aba", "ababa") is true.\nTherefore, the answer is 4.</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> words = ["pa","papa","ma","mama"]\n<strong>Output:</strong> 2\n<strong>Explanation:</strong> In this example, the counted index pairs are:\ni = 0 and j = 1 because isPrefixAndSuffix("pa", "papa") is true.\ni = 2 and j = 3 because isPrefixAndSuffix("ma", "mama") is true.\nTherefore, the answer is 2. </pre>\n\n<p><strong class=\"example\">Example 3:</strong></p>\n\n<pre>\n<strong>Input:</strong> words = ["abab","ab"]\n<strong>Output:</strong> 0\n<strong>Explanation: </strong>In this example, the only valid index pair is i = 0 and j = 1, and isPrefixAndSuffix("abab", "ab") is false.\nTherefore, the answer is 0.</pre>\n\n<p> </p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>1 <= words.length <= 50</code></li>\n\t<li><code>1 <= words[i].length <= 10</code></li>\n\t<li><code>words[i]</code> consists only of lowercase English letters.</li>\n</ul>\n",
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"difficulty": "Easy",
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"exampleTestcases": "[\"a\",\"aba\",\"ababa\",\"aa\"]\n[\"pa\",\"papa\",\"ma\",\"mama\"]\n[\"abab\",\"ab\"]",
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"code": "class Solution(object):\n def countPrefixSuffixPairs(self, words):\n \"\"\"\n :type words: List[str]\n :rtype: int\n \"\"\"\n ",
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"Iterate through all index pairs <code>(i, j)</code>, such that <code>i < j</code>, and check <code>isPrefixAndSuffix(words[i], words[j])</code>.",
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"The answer is the total number of pairs where <code>isPrefixAndSuffix(words[i], words[j]) == true</code>."
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"sampleTestCase": "[\"a\",\"aba\",\"ababa\",\"aa\"]",
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