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leetcode-problemset/leetcode-cn/originData/wiggle-sort-ii.json
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"categoryTitle": "Algorithms",
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"title": "Wiggle Sort II",
"titleSlug": "wiggle-sort-ii",
"content": "<p>Given an integer array <code>nums</code>, reorder it such that <code>nums[0] &lt; nums[1] &gt; nums[2] &lt; nums[3]...</code>.</p>\n\n<p>You may assume the input array always has a valid answer.</p>\n\n<p>&nbsp;</p>\n<p><strong class=\"example\">Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> nums = [1,5,1,1,6,4]\n<strong>Output:</strong> [1,6,1,5,1,4]\n<strong>Explanation:</strong> [1,4,1,5,1,6] is also accepted.\n</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> nums = [1,3,2,2,3,1]\n<strong>Output:</strong> [2,3,1,3,1,2]\n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= nums.length &lt;= 5 * 10<sup>4</sup></code></li>\n\t<li><code>0 &lt;= nums[i] &lt;= 5000</code></li>\n\t<li>It is guaranteed that there will be an answer for the given input <code>nums</code>.</li>\n</ul>\n\n<p>&nbsp;</p>\n<strong>Follow Up:</strong> Can you do it in <code>O(n)</code> time and/or <strong>in-place</strong> with <code>O(1)</code> extra space?",
"translatedTitle": "摆动排序 II",
"translatedContent": "<p>给你一个整数数组 <code>nums</code>,将它重新排列成 <code>nums[0] < nums[1] > nums[2] < nums[3]...</code> 的顺序。</p>\n\n<p>你可以假设所有输入数组都可以得到满足题目要求的结果。</p>\n\n<p> </p>\n\n<p><strong>示例 1</strong></p>\n\n<pre>\n<strong>输入:</strong>nums = [1,5,1,1,6,4]\n<strong>输出:</strong>[1,6,1,5,1,4]\n<strong>解释:</strong>[1,4,1,5,1,6] 同样是符合题目要求的结果,可以被判题程序接受。\n</pre>\n\n<p><strong>示例 2</strong></p>\n\n<pre>\n<strong>输入:</strong>nums = [1,3,2,2,3,1]\n<strong>输出:</strong>[2,3,1,3,1,2]\n</pre>\n\n<p> </p>\n\n<p><strong>提示:</strong></p>\n\n<ul>\n\t<li><code>1 <= nums.length <= 5 * 10<sup>4</sup></code></li>\n\t<li><code>0 <= nums[i] <= 5000</code></li>\n\t<li>题目数据保证,对于给定的输入 <code>nums</code> ,总能产生满足题目要求的结果</li>\n</ul>\n\n<p> </p>\n\n<p><strong>进阶:</strong>你能用 O(n) 时间复杂度和 / 或原地 O(1) 额外空间来实现吗?</p>\n",
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