leetcode-problemset/leetcode-cn/originData/spiral-matrix-iv.json

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        "question": {
            "questionId": "2411",
            "questionFrontendId": "2326",
            "categoryTitle": "Algorithms",
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            "title": "Spiral Matrix IV",
            "titleSlug": "spiral-matrix-iv",
            "content": "<p>You are given two integers <code>m</code> and <code>n</code>, which represent the dimensions of a matrix.</p>\n\n<p>You are also given the <code>head</code> of a linked list of integers.</p>\n\n<p>Generate an <code>m x n</code> matrix that contains the integers in the linked list presented in <strong>spiral</strong> order <strong>(clockwise)</strong>, starting from the <strong>top-left</strong> of the matrix. If there are remaining empty spaces, fill them with <code>-1</code>.</p>\n\n<p>Return <em>the generated matrix</em>.</p>\n\n<p>&nbsp;</p>\n<p><strong class=\"example\">Example 1:</strong></p>\n<img alt=\"\" src=\"https://assets.leetcode.com/uploads/2022/05/09/ex1new.jpg\" style=\"width: 240px; height: 150px;\" />\n<pre>\n<strong>Input:</strong> m = 3, n = 5, head = [3,0,2,6,8,1,7,9,4,2,5,5,0]\n<strong>Output:</strong> [[3,0,2,6,8],[5,0,-1,-1,1],[5,2,4,9,7]]\n<strong>Explanation:</strong> The diagram above shows how the values are printed in the matrix.\nNote that the remaining spaces in the matrix are filled with -1.\n</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n<img alt=\"\" src=\"https://assets.leetcode.com/uploads/2022/05/11/ex2.jpg\" style=\"width: 221px; height: 60px;\" />\n<pre>\n<strong>Input:</strong> m = 1, n = 4, head = [0,1,2]\n<strong>Output:</strong> [[0,1,2,-1]]\n<strong>Explanation:</strong> The diagram above shows how the values are printed from left to right in the matrix.\nThe last space in the matrix is set to -1.</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= m, n &lt;= 10<sup>5</sup></code></li>\n\t<li><code>1 &lt;= m * n &lt;= 10<sup>5</sup></code></li>\n\t<li>The number of nodes in the list is in the range <code>[1, m * n]</code>.</li>\n\t<li><code>0 &lt;= Node.val &lt;= 1000</code></li>\n</ul>\n",
            "translatedTitle": "螺旋矩阵 IV",
            "translatedContent": "<p>给你两个整数：<code>m</code> 和 <code>n</code> ，表示矩阵的维数。</p>\n\n<p>另给你一个整数链表的头节点 <code>head</code> 。</p>\n\n<p>请你生成一个大小为 <code>m x n</code> 的螺旋矩阵，矩阵包含链表中的所有整数。链表中的整数从矩阵 <strong>左上角</strong> 开始、<strong>顺时针 </strong>按 <strong>螺旋</strong> 顺序填充。如果还存在剩余的空格，则用 <code>-1</code> 填充。</p>\n\n<p>返回生成的矩阵。</p>\n\n<p>&nbsp;</p>\n\n<p><strong>示例 1：</strong></p>\n<img alt=\"\" src=\"https://assets.leetcode.com/uploads/2022/05/09/ex1new.jpg\" style=\"width: 240px; height: 150px;\">\n<pre><strong>输入：</strong>m = 3, n = 5, head = [3,0,2,6,8,1,7,9,4,2,5,5,0]\n<strong>输出：</strong>[[3,0,2,6,8],[5,0,-1,-1,1],[5,2,4,9,7]]\n<strong>解释：</strong>上图展示了链表中的整数在矩阵中是如何排布的。\n注意，矩阵中剩下的空格用 -1 填充。\n</pre>\n\n<p><strong>示例 2：</strong></p>\n<img alt=\"\" src=\"https://assets.leetcode.com/uploads/2022/05/11/ex2.jpg\" style=\"width: 221px; height: 60px;\">\n<pre><strong>输入：</strong>m = 1, n = 4, head = [0,1,2]\n<strong>输出：</strong>[[0,1,2,-1]]\n<strong>解释：</strong>上图展示了链表中的整数在矩阵中是如何从左到右排布的。 \n注意，矩阵中剩下的空格用 -1 填充。</pre>\n\n<p>&nbsp;</p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= m, n &lt;= 10<sup>5</sup></code></li>\n\t<li><code>1 &lt;= m * n &lt;= 10<sup>5</sup></code></li>\n\t<li>链表中节点数目在范围 <code>[1, m * n]</code> 内</li>\n\t<li><code>0 &lt;= Node.val &lt;= 1000</code></li>\n</ul>\n",
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                    "code": "/**\n * Definition for singly-linked list.\n * struct ListNode {\n *     int val;\n *     ListNode *next;\n *     ListNode() : val(0), next(nullptr) {}\n *     ListNode(int x) : val(x), next(nullptr) {}\n *     ListNode(int x, ListNode *next) : val(x), next(next) {}\n * };\n */\nclass Solution {\npublic:\n    vector<vector<int>> spiralMatrix(int m, int n, ListNode* head) {\n        \n    }\n};",
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                    "code": "/**\n * Definition for singly-linked list.\n * public class ListNode {\n *     int val;\n *     ListNode next;\n *     ListNode() {}\n *     ListNode(int val) { this.val = val; }\n *     ListNode(int val, ListNode next) { this.val = val; this.next = next; }\n * }\n */\nclass Solution {\n    public int[][] spiralMatrix(int m, int n, ListNode head) {\n\n    }\n}",
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                    "code": "# Definition for singly-linked list.\n# class ListNode(object):\n#     def __init__(self, val=0, next=None):\n#         self.val = val\n#         self.next = next\nclass Solution(object):\n    def spiralMatrix(self, m, n, head):\n        \"\"\"\n        :type m: int\n        :type n: int\n        :type head: Optional[ListNode]\n        :rtype: List[List[int]]\n        \"\"\"",
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                    "code": "# Definition for singly-linked list.\n# class ListNode:\n#     def __init__(self, val=0, next=None):\n#         self.val = val\n#         self.next = next\nclass Solution:\n    def spiralMatrix(self, m: int, n: int, head: Optional[ListNode]) -> List[List[int]]:",
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                {
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                    "code": "/**\n * Definition for singly-linked list.\n * struct ListNode {\n *     int val;\n *     struct ListNode *next;\n * };\n */\n/**\n * Return an array of arrays of size *returnSize.\n * The sizes of the arrays are returned as *returnColumnSizes array.\n * Note: Both returned array and *columnSizes array must be malloced, assume caller calls free().\n */\nint** spiralMatrix(int m, int n, struct ListNode* head, int* returnSize, int** returnColumnSizes) {\n    \n}",
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                    "code": "/**\n * Definition for singly-linked list.\n * public class ListNode {\n *     public int val;\n *     public ListNode next;\n *     public ListNode(int val=0, ListNode next=null) {\n *         this.val = val;\n *         this.next = next;\n *     }\n * }\n */\npublic class Solution {\n    public int[][] SpiralMatrix(int m, int n, ListNode head) {\n\n    }\n}",
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                    "lang": "JavaScript",
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                    "code": "/**\n * Definition for singly-linked list.\n * function ListNode(val, next) {\n *     this.val = (val===undefined ? 0 : val)\n *     this.next = (next===undefined ? null : next)\n * }\n */\n/**\n * @param {number} m\n * @param {number} n\n * @param {ListNode} head\n * @return {number[][]}\n */\nvar spiralMatrix = function(m, n, head) {\n\n};",
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                    "code": "/**\n * Definition for singly-linked list.\n * class ListNode {\n *     val: number\n *     next: ListNode | null\n *     constructor(val?: number, next?: ListNode | null) {\n *         this.val = (val===undefined ? 0 : val)\n *         this.next = (next===undefined ? null : next)\n *     }\n * }\n */\n\nfunction spiralMatrix(m: number, n: number, head: ListNode | null): number[][] {\n    \n};",
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                    "code": "/**\n * Definition for a singly-linked list.\n * class ListNode {\n *     public $val = 0;\n *     public $next = null;\n *     function __construct($val = 0, $next = null) {\n *         $this->val = $val;\n *         $this->next = $next;\n *     }\n * }\n */\nclass Solution {\n\n    /**\n     * @param Integer $m\n     * @param Integer $n\n     * @param ListNode $head\n     * @return Integer[][]\n     */\n    function spiralMatrix($m, $n, $head) {\n\n    }\n}",
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                    "code": "/**\n * Definition for singly-linked list.\n * public class ListNode {\n *     public var val: Int\n *     public var next: ListNode?\n *     public init() { self.val = 0; self.next = nil; }\n *     public init(_ val: Int) { self.val = val; self.next = nil; }\n *     public init(_ val: Int, _ next: ListNode?) { self.val = val; self.next = next; }\n * }\n */\nclass Solution {\n    func spiralMatrix(_ m: Int, _ n: Int, _ head: ListNode?) -> [[Int]] {\n\n    }\n}",
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                    "lang": "Kotlin",
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                    "code": "/**\n * Example:\n * var li = ListNode(5)\n * var v = li.`val`\n * Definition for singly-linked list.\n * class ListNode(var `val`: Int) {\n *     var next: ListNode? = null\n * }\n */\nclass Solution {\n    fun spiralMatrix(m: Int, n: Int, head: ListNode?): Array<IntArray> {\n\n    }\n}",
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                    "code": "/**\n * Definition for singly-linked list.\n * class ListNode {\n *   int val;\n *   ListNode? next;\n *   ListNode([this.val = 0, this.next]);\n * }\n */\nclass Solution {\n  List<List<int>> spiralMatrix(int m, int n, ListNode? head) {\n    \n  }\n}",
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                    "code": "/**\n * Definition for singly-linked list.\n * type ListNode struct {\n *     Val int\n *     Next *ListNode\n * }\n */\nfunc spiralMatrix(m int, n int, head *ListNode) [][]int {\n\n}",
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                    "code": "# Definition for singly-linked list.\n# class ListNode\n#     attr_accessor :val, :next\n#     def initialize(val = 0, _next = nil)\n#         @val = val\n#         @next = _next\n#     end\n# end\n# @param {Integer} m\n# @param {Integer} n\n# @param {ListNode} head\n# @return {Integer[][]}\ndef spiral_matrix(m, n, head)\n\nend",
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                    "code": "/**\n * Definition for singly-linked list.\n * class ListNode(_x: Int = 0, _next: ListNode = null) {\n *   var next: ListNode = _next\n *   var x: Int = _x\n * }\n */\nobject Solution {\n    def spiralMatrix(m: Int, n: Int, head: ListNode): Array[Array[Int]] = {\n\n    }\n}",
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                    "code": "// Definition for singly-linked list.\n// #[derive(PartialEq, Eq, Clone, Debug)]\n// pub struct ListNode {\n//   pub val: i32,\n//   pub next: Option<Box<ListNode>>\n// }\n//\n// impl ListNode {\n//   #[inline]\n//   fn new(val: i32) -> Self {\n//     ListNode {\n//       next: None,\n//       val\n//     }\n//   }\n// }\nimpl Solution {\n    pub fn spiral_matrix(m: i32, n: i32, head: Option<Box<ListNode>>) -> Vec<Vec<i32>> {\n\n    }\n}",
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                    "code": "; Definition for singly-linked list:\n#|\n\n; val : integer?\n; next : (or/c list-node? #f)\n(struct list-node\n  (val next) #:mutable #:transparent)\n\n; constructor\n(define (make-list-node [val 0])\n  (list-node val #f))\n\n|#\n\n(define/contract (spiral-matrix m n head)\n  (-> exact-integer? exact-integer? (or/c list-node? #f) (listof (listof exact-integer?)))\n  )",
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                    "code": "%% Definition for singly-linked list.\n%%\n%% -record(list_node, {val = 0 :: integer(),\n%%                     next = null :: 'null' | #list_node{}}).\n\n-spec spiral_matrix(M :: integer(), N :: integer(), Head :: #list_node{} | null) -> [[integer()]].\nspiral_matrix(M, N, Head) ->\n  .",
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                    "lang": "Elixir",
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                    "code": "# Definition for singly-linked list.\n#\n# defmodule ListNode do\n#   @type t :: %__MODULE__{\n#           val: integer,\n#           next: ListNode.t() | nil\n#         }\n#   defstruct val: 0, next: nil\n# end\n\ndefmodule Solution do\n  @spec spiral_matrix(m :: integer, n :: integer, head :: ListNode.t | nil) :: [[integer]]\n  def spiral_matrix(m, n, head) do\n    \n  end\nend",
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                "First, generate an m x n matrix filled with -1s.",
                "Navigate within the matrix at (i, j) with the help of a direction vector ⟨di, dj⟩. At (i, j), you need to decide if you can keep going in the current direction.",
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