mirror of
https://gitee.com/coder-xiaomo/leetcode-problemset
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184 lines
22 KiB
JSON
184 lines
22 KiB
JSON
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"categoryTitle": "Algorithms",
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"boundTopicId": 79261,
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"title": "Sort the Matrix Diagonally",
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"content": "<p>A <strong>matrix diagonal</strong> is a diagonal line of cells starting from some cell in either the topmost row or leftmost column and going in the bottom-right direction until reaching the matrix's end. For example, the <strong>matrix diagonal</strong> starting from <code>mat[2][0]</code>, where <code>mat</code> is a <code>6 x 3</code> matrix, includes cells <code>mat[2][0]</code>, <code>mat[3][1]</code>, and <code>mat[4][2]</code>.</p>\n\n<p>Given an <code>m x n</code> matrix <code>mat</code> of integers, sort each <strong>matrix diagonal</strong> in ascending order and return <em>the resulting matrix</em>.</p>\n\n<p> </p>\n<p><strong class=\"example\">Example 1:</strong></p>\n<img alt=\"\" src=\"https://assets.leetcode.com/uploads/2020/01/21/1482_example_1_2.png\" style=\"width: 500px; height: 198px;\" />\n<pre>\n<strong>Input:</strong> mat = [[3,3,1,1],[2,2,1,2],[1,1,1,2]]\n<strong>Output:</strong> [[1,1,1,1],[1,2,2,2],[1,2,3,3]]\n</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> mat = [[11,25,66,1,69,7],[23,55,17,45,15,52],[75,31,36,44,58,8],[22,27,33,25,68,4],[84,28,14,11,5,50]]\n<strong>Output:</strong> [[5,17,4,1,52,7],[11,11,25,45,8,69],[14,23,25,44,58,15],[22,27,31,36,50,66],[84,28,75,33,55,68]]\n</pre>\n\n<p> </p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>m == mat.length</code></li>\n\t<li><code>n == mat[i].length</code></li>\n\t<li><code>1 <= m, n <= 100</code></li>\n\t<li><code>1 <= mat[i][j] <= 100</code></li>\n</ul>\n",
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"translatedTitle": "将矩阵按对角线排序",
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"translatedContent": "<p><strong>矩阵对角线</strong> 是一条从矩阵最上面行或者最左侧列中的某个元素开始的对角线，沿右下方向一直到矩阵末尾的元素。例如，矩阵 <code>mat</code> 有 <code>6</code> 行 <code>3</code> 列，从 <code>mat[2][0]</code> 开始的 <strong>矩阵对角线</strong> 将会经过 <code>mat[2][0]</code>、<code>mat[3][1]</code> 和 <code>mat[4][2]</code> 。</p>\n\n<p>给你一个 <code>m * n</code> 的整数矩阵 <code>mat</code> ，请你将同一条 <strong>矩阵对角线 </strong>上的元素按升序排序后，返回排好序的矩阵。</p>\n\n<p> </p>\n\n<p><strong>示例 1：</strong></p>\n\n<p><img alt=\"\" src=\"https://assets.leetcode-cn.com/aliyun-lc-upload/uploads/2020/01/25/1482_example_1_2.png\" style=\"height: 198px; width: 500px;\" /></p>\n\n<pre>\n<strong>输入：</strong>mat = [[3,3,1,1],[2,2,1,2],[1,1,1,2]]\n<strong>输出：</strong>[[1,1,1,1],[1,2,2,2],[1,2,3,3]]\n</pre>\n\n<p><strong>示例 2：</strong></p>\n\n<pre>\n<strong>输入：</strong>mat = [[11,25,66,1,69,7],[23,55,17,45,15,52],[75,31,36,44,58,8],[22,27,33,25,68,4],[84,28,14,11,5,50]]\n<strong>输出：</strong>[[5,17,4,1,52,7],[11,11,25,45,8,69],[14,23,25,44,58,15],[22,27,31,36,50,66],[84,28,75,33,55,68]]\n</pre>\n\n<p> </p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code>m == mat.length</code></li>\n\t<li><code>n == mat[i].length</code></li>\n\t<li><code>1 <= m, n <= 100</code></li>\n\t<li><code>1 <= mat[i][j] <= 100</code></li>\n</ul>\n",
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"Use a data structure to store all values of each diagonal.",
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"How to index the data structure with the id of the diagonal?",
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"All cells in the same diagonal (i,j) have the same difference so we can get the diagonal of a cell using the difference i-j."
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