leetcode-problemset/leetcode-cn/originData/sort-integers-by-the-power-value.json

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            "title": "Sort Integers by The Power Value",
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            "content": "<p>The power of an integer <code>x</code> is defined as the number of steps needed to transform <code>x</code> into <code>1</code> using the following steps:</p>\n\n<ul>\n\t<li>if <code>x</code> is even then <code>x = x / 2</code></li>\n\t<li>if <code>x</code> is odd then <code>x = 3 * x + 1</code></li>\n</ul>\n\n<p>For example, the power of <code>x = 3</code> is <code>7</code> because <code>3</code> needs <code>7</code> steps to become <code>1</code> (<code>3 --&gt; 10 --&gt; 5 --&gt; 16 --&gt; 8 --&gt; 4 --&gt; 2 --&gt; 1</code>).</p>\n\n<p>Given three integers <code>lo</code>, <code>hi</code> and <code>k</code>. The task is to sort all integers in the interval <code>[lo, hi]</code> by the power value in <strong>ascending order</strong>, if two or more integers have <strong>the same</strong> power value sort them by <strong>ascending order</strong>.</p>\n\n<p>Return the <code>k<sup>th</sup></code> integer in the range <code>[lo, hi]</code> sorted by the power value.</p>\n\n<p>Notice that for any integer <code>x</code> <code>(lo &lt;= x &lt;= hi)</code> it is <strong>guaranteed</strong> that <code>x</code> will transform into <code>1</code> using these steps and that the power of <code>x</code> is will <strong>fit</strong> in a 32-bit signed integer.</p>\n\n<p>&nbsp;</p>\n<p><strong class=\"example\">Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> lo = 12, hi = 15, k = 2\n<strong>Output:</strong> 13\n<strong>Explanation:</strong> The power of 12 is 9 (12 --&gt; 6 --&gt; 3 --&gt; 10 --&gt; 5 --&gt; 16 --&gt; 8 --&gt; 4 --&gt; 2 --&gt; 1)\nThe power of 13 is 9\nThe power of 14 is 17\nThe power of 15 is 17\nThe interval sorted by the power value [12,13,14,15]. For k = 2 answer is the second element which is 13.\nNotice that 12 and 13 have the same power value and we sorted them in ascending order. Same for 14 and 15.\n</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> lo = 7, hi = 11, k = 4\n<strong>Output:</strong> 7\n<strong>Explanation:</strong> The power array corresponding to the interval [7, 8, 9, 10, 11] is [16, 3, 19, 6, 14].\nThe interval sorted by power is [8, 10, 11, 7, 9].\nThe fourth number in the sorted array is 7.\n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= lo &lt;= hi &lt;= 1000</code></li>\n\t<li><code>1 &lt;= k &lt;= hi - lo + 1</code></li>\n</ul>\n",
            "translatedTitle": "将整数按权重排序",
            "translatedContent": "<p>我们将整数 <code>x</code>&nbsp;的 <strong>权重</strong> 定义为按照下述规则将 <code>x</code>&nbsp;变成 <code>1</code>&nbsp;所需要的步数：</p>\n\n<ul>\n\t<li>如果&nbsp;<code>x</code>&nbsp;是偶数，那么&nbsp;<code>x = x / 2</code></li>\n\t<li>如果&nbsp;<code>x</code>&nbsp;是奇数，那么&nbsp;<code>x = 3 * x + 1</code></li>\n</ul>\n\n<p>比方说，x=3 的权重为 7 。因为 3 需要 7 步变成 1 （3 --&gt; 10 --&gt; 5 --&gt; 16 --&gt; 8 --&gt; 4 --&gt; 2 --&gt; 1）。</p>\n\n<p>给你三个整数&nbsp;<code>lo</code>，&nbsp;<code>hi</code> 和&nbsp;<code>k</code>&nbsp;。你的任务是将区间&nbsp;<code>[lo, hi]</code>&nbsp;之间的整数按照它们的权重&nbsp;<strong>升序排序&nbsp;</strong>，如果大于等于 2 个整数有&nbsp;<strong>相同</strong>&nbsp;的权重，那么按照数字自身的数值&nbsp;<strong>升序排序</strong>&nbsp;。</p>\n\n<p>请你返回区间&nbsp;<code>[lo, hi]</code>&nbsp;之间的整数按权重排序后的第&nbsp;<code>k</code>&nbsp;个数。</p>\n\n<p>注意，题目保证对于任意整数&nbsp;<code>x</code>&nbsp;<code>（lo &lt;= x &lt;= hi）</code>&nbsp;，它变成&nbsp;<code>1</code> 所需要的步数是一个 32 位有符号整数。</p>\n\n<p>&nbsp;</p>\n\n<p><strong>示例 1：</strong></p>\n\n<pre>\n<strong>输入：</strong>lo = 12, hi = 15, k = 2\n<strong>输出：</strong>13\n<strong>解释：</strong>12 的权重为 9（12 --&gt; 6 --&gt; 3 --&gt; 10 --&gt; 5 --&gt; 16 --&gt; 8 --&gt; 4 --&gt; 2 --&gt; 1）\n13 的权重为 9\n14 的权重为 17\n15 的权重为 17\n区间内的数按权重排序以后的结果为 [12,13,14,15] 。对于 k = 2 ，答案是第二个整数也就是 13 。\n注意，12 和 13 有相同的权重，所以我们按照它们本身升序排序。14 和 15 同理。\n</pre>\n\n<p><strong>示例 2：</strong></p>\n\n<pre>\n<strong>输入：</strong>lo = 7, hi = 11, k = 4\n<strong>输出：</strong>7\n<strong>解释：</strong>区间内整数 [7, 8, 9, 10, 11] 对应的权重为 [16, 3, 19, 6, 14] 。\n按权重排序后得到的结果为 [8, 10, 11, 7, 9] 。\n排序后数组中第 4 个数字为 7 。\n</pre>\n\n<p>&nbsp;</p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= lo &lt;= hi &lt;= 1000</code></li>\n\t<li><code>1 &lt;= k &lt;= hi - lo + 1</code></li>\n</ul>\n",
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