mirror of
https://gitee.com/coder-xiaomo/leetcode-problemset
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208 lines
22 KiB
JSON
208 lines
22 KiB
JSON
{
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"data": {
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"question": {
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"questionId": "493",
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"questionFrontendId": "493",
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"categoryTitle": "Algorithms",
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"boundTopicId": 1794,
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"title": "Reverse Pairs",
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"titleSlug": "reverse-pairs",
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"content": "<p>Given an integer array <code>nums</code>, return <em>the number of <strong>reverse pairs</strong> in the array</em>.</p>\n\n<p>A <strong>reverse pair</strong> is a pair <code>(i, j)</code> where:</p>\n\n<ul>\n\t<li><code>0 <= i < j < nums.length</code> and</li>\n\t<li><code>nums[i] > 2 * nums[j]</code>.</li>\n</ul>\n\n<p> </p>\n<p><strong class=\"example\">Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> nums = [1,3,2,3,1]\n<strong>Output:</strong> 2\n<strong>Explanation:</strong> The reverse pairs are:\n(1, 4) --> nums[1] = 3, nums[4] = 1, 3 > 2 * 1\n(3, 4) --> nums[3] = 3, nums[4] = 1, 3 > 2 * 1\n</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> nums = [2,4,3,5,1]\n<strong>Output:</strong> 3\n<strong>Explanation:</strong> The reverse pairs are:\n(1, 4) --> nums[1] = 4, nums[4] = 1, 4 > 2 * 1\n(2, 4) --> nums[2] = 3, nums[4] = 1, 3 > 2 * 1\n(3, 4) --> nums[3] = 5, nums[4] = 1, 5 > 2 * 1\n</pre>\n\n<p> </p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>1 <= nums.length <= 5 * 10<sup>4</sup></code></li>\n\t<li><code>-2<sup>31</sup> <= nums[i] <= 2<sup>31</sup> - 1</code></li>\n</ul>\n",
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"translatedTitle": "翻转对",
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"translatedContent": "<p>给定一个数组 <code>nums</code> ，如果 <code>i < j</code> 且 <code>nums[i] > 2*nums[j]</code> 我们就将 <code>(i, j)</code> 称作一个<strong><em>重要翻转对</em></strong>。</p>\n\n<p>你需要返回给定数组中的重要翻转对的数量。</p>\n\n<p><strong>示例 1:</strong></p>\n\n<pre>\n<strong>输入</strong>: [1,3,2,3,1]\n<strong>输出</strong>: 2\n</pre>\n\n<p><strong>示例 2:</strong></p>\n\n<pre>\n<strong>输入</strong>: [2,4,3,5,1]\n<strong>输出</strong>: 3\n</pre>\n\n<p><strong>注意:</strong></p>\n\n<ol>\n\t<li>给定数组的长度不会超过<code>50000</code>。</li>\n\t<li>输入数组中的所有数字都在32位整数的表示范围内。</li>\n</ol>\n",
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"difficulty": "Hard",
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"name": "Binary Indexed Tree",
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"name": "Divide and Conquer",
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"name": "Merge Sort",
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"hints": [
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"Use the merge-sort technique.",
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"Divide the array into two parts and sort them.",
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"For each integer in the first part, count the number of integers that satisfy the condition from the second part. Use the pointer to help you in the counting process."
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],
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"sampleTestCase": "[1,3,2,3,1]",
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