mirror of
https://gitee.com/coder-xiaomo/leetcode-problemset
synced 2025-01-10 18:48:13 +08:00
185 lines
21 KiB
JSON
185 lines
21 KiB
JSON
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"questionId": "301",
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"categoryTitle": "Algorithms",
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"boundTopicId": 1780,
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"title": "Remove Invalid Parentheses",
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"titleSlug": "remove-invalid-parentheses",
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"content": "<p>Given a string <code>s</code> that contains parentheses and letters, remove the minimum number of invalid parentheses to make the input string valid.</p>\n\n<p>Return <em>a list of <strong>unique strings</strong> that are valid with the minimum number of removals</em>. You may return the answer in <strong>any order</strong>.</p>\n\n<p> </p>\n<p><strong class=\"example\">Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> s = "()())()"\n<strong>Output:</strong> ["(())()","()()()"]\n</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> s = "(a)())()"\n<strong>Output:</strong> ["(a())()","(a)()()"]\n</pre>\n\n<p><strong class=\"example\">Example 3:</strong></p>\n\n<pre>\n<strong>Input:</strong> s = ")("\n<strong>Output:</strong> [""]\n</pre>\n\n<p> </p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>1 <= s.length <= 25</code></li>\n\t<li><code>s</code> consists of lowercase English letters and parentheses <code>'('</code> and <code>')'</code>.</li>\n\t<li>There will be at most <code>20</code> parentheses in <code>s</code>.</li>\n</ul>\n",
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"translatedTitle": "删除无效的括号",
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"translatedContent": "<p>给你一个由若干括号和字母组成的字符串 <code>s</code> ，删除最小数量的无效括号，使得输入的字符串有效。</p>\n\n<p>返回所有可能的结果。答案可以按 <strong>任意顺序</strong> 返回。</p>\n\n<p> </p>\n\n<p><strong>示例 1：</strong></p>\n\n<pre>\n<strong>输入：</strong>s = \"()())()\"\n<strong>输出：</strong>[\"(())()\",\"()()()\"]\n</pre>\n\n<p><strong>示例 2：</strong></p>\n\n<pre>\n<strong>输入：</strong>s = \"(a)())()\"\n<strong>输出：</strong>[\"(a())()\",\"(a)()()\"]\n</pre>\n\n<p><strong>示例 3：</strong></p>\n\n<pre>\n<strong>输入：</strong>s = \")(\"\n<strong>输出：</strong>[\"\"]\n</pre>\n\n<p> </p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code>1 <= s.length <= 25</code></li>\n\t<li><code>s</code> 由小写英文字母以及括号 <code>'('</code> 和 <code>')'</code> 组成</li>\n\t<li><code>s</code> 中至多含 <code>20</code> 个括号</li>\n</ul>\n",
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"difficulty": "Hard",
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"code": "class Solution(object):\n def removeInvalidParentheses(self, s):\n \"\"\"\n :type s: str\n :rtype: List[str]\n \"\"\"",
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"code": "/**\n * Note: The returned array must be malloced, assume caller calls free().\n */\nchar** removeInvalidParentheses(char* s, int* returnSize) {\n \n}",
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"code": "-spec remove_invalid_parentheses(S :: unicode:unicode_binary()) -> [unicode:unicode_binary()].\nremove_invalid_parentheses(S) ->\n .",
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"code": "defmodule Solution do\n @spec remove_invalid_parentheses(s :: String.t) :: [String.t]\n def remove_invalid_parentheses(s) do\n \n end\nend",
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"Since we do not know which brackets can be removed, we try all the options! We can use recursion.",
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"In the recursion, for each bracket, we can either use it or remove it.",
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"Recursion will generate all the valid parentheses strings but we want the ones with the least number of parentheses deleted.",
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"We can count the number of invalid brackets to be deleted and only generate the valid strings in the recusrion."
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