leetcode-problemset/leetcode-cn/originData/remove-adjacent-almost-equal-characters.json

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        "question": {
            "questionId": "3230",
            "questionFrontendId": "2957",
            "categoryTitle": "Algorithms",
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            "title": "Remove Adjacent Almost-Equal Characters",
            "titleSlug": "remove-adjacent-almost-equal-characters",
            "content": "<p>You are given a <strong>0-indexed</strong> string <code>word</code>.</p>\n\n<p>In one operation, you can pick any index <code>i</code> of <code>word</code> and change <code>word[i]</code> to any lowercase English letter.</p>\n\n<p>Return <em>the <strong>minimum</strong> number of operations needed to remove all adjacent <strong>almost-equal</strong> characters from</em> <code>word</code>.</p>\n\n<p>Two characters <code>a</code> and <code>b</code> are <strong>almost-equal</strong> if <code>a == b</code> or <code>a</code> and <code>b</code> are adjacent in the alphabet.</p>\n\n<p>&nbsp;</p>\n<p><strong class=\"example\">Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> word = &quot;aaaaa&quot;\n<strong>Output:</strong> 2\n<strong>Explanation:</strong> We can change word into &quot;a<strong><u>c</u></strong>a<u><strong>c</strong></u>a&quot; which does not have any adjacent almost-equal characters.\nIt can be shown that the minimum number of operations needed to remove all adjacent almost-equal characters from word is 2.\n</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> word = &quot;abddez&quot;\n<strong>Output:</strong> 2\n<strong>Explanation:</strong> We can change word into &quot;<strong><u>y</u></strong>bd<u><strong>o</strong></u>ez&quot; which does not have any adjacent almost-equal characters.\nIt can be shown that the minimum number of operations needed to remove all adjacent almost-equal characters from word is 2.</pre>\n\n<p><strong class=\"example\">Example 3:</strong></p>\n\n<pre>\n<strong>Input:</strong> word = &quot;zyxyxyz&quot;\n<strong>Output:</strong> 3\n<strong>Explanation:</strong> We can change word into &quot;z<u><strong>a</strong></u>x<u><strong>a</strong></u>x<strong><u>a</u></strong>z&quot; which does not have any adjacent almost-equal characters. \nIt can be shown that the minimum number of operations needed to remove all adjacent almost-equal characters from word is 3.\n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= word.length &lt;= 100</code></li>\n\t<li><code>word</code> consists only of lowercase English letters.</li>\n</ul>\n",
            "translatedTitle": "消除相邻近似相等字符",
            "translatedContent": "<p>给你一个下标从 <strong>0</strong>&nbsp;开始的字符串&nbsp;<code>word</code>&nbsp;。</p>\n\n<p>一次操作中，你可以选择&nbsp;<code>word</code>&nbsp;中任意一个下标 <code>i</code>&nbsp;，将&nbsp;<code>word[i]</code> 修改成任意一个小写英文字母。</p>\n\n<p>请你返回消除 <code>word</code>&nbsp;中所有相邻 <strong>近似相等</strong>&nbsp;字符的 <strong>最少</strong>&nbsp;操作次数。</p>\n\n<p>两个字符&nbsp;<code>a</code> 和&nbsp;<code>b</code>&nbsp;如果满足&nbsp;<code>a == b</code>&nbsp;或者&nbsp;<code>a</code> 和&nbsp;<code>b</code>&nbsp;在字母表中是相邻的，那么我们称它们是 <strong>近似相等</strong>&nbsp;字符。</p>\n\n<p>&nbsp;</p>\n\n<p><strong class=\"example\">示例 1：</strong></p>\n\n<pre>\n<b>输入：</b>word = \"aaaaa\"\n<b>输出：</b>2\n<b>解释：</b>我们将 word 变为 \"a<em><strong>c</strong></em>a<em><strong>c</strong></em>a\" ，该字符串没有相邻近似相等字符。\n消除 word 中所有相邻近似相等字符最少需要 2 次操作。\n</pre>\n\n<p><strong class=\"example\">示例 2：</strong></p>\n\n<pre>\n<b>输入：</b>word = \"abddez\"\n<b>输出：</b>2\n<b>解释：</b>我们将 word 变为 \"<em><strong>y</strong></em>bd<em><strong>o</strong></em>ez\" ，该字符串没有相邻近似相等字符。\n消除 word 中所有相邻近似相等字符最少需要 2 次操作。</pre>\n\n<p><strong class=\"example\">示例 3：</strong></p>\n\n<pre>\n<b>输入：</b>word = \"zyxyxyz\"\n<b>输出：</b>3\n<b>解释：</b>我们将 word 变为 \"z<em><strong>a</strong></em>x<em><strong>a</strong></em>x<em><strong>a</strong></em>z\" ，该字符串没有相邻近似相等字符。\n消除 word 中所有相邻近似相等字符最少需要 3 次操作\n</pre>\n\n<p>&nbsp;</p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= word.length &lt;= 100</code></li>\n\t<li><code>word</code>&nbsp;只包含小写英文字母。</li>\n</ul>\n",
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            "hints": [
                "For <code>i > 0</code>, if <code>word[i]</code> and <code>word[i - 1]</code> are adjacent, we will change <code>word[i]</code> to another character. Which character should we change it to?",
                "We will change <code>word[i]</code> to some character that is not adjacent to <code>word[i - 1]</code> nor <code>word[i + 1]</code> (if it exists). Such a character always exists. However, since the problem does not ask for the final state of the string, It is enough to prove that the character exists and we do not need to find it."
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