mirror of
https://gitee.com/coder-xiaomo/leetcode-problemset
synced 2025-01-10 18:48:13 +08:00
189 lines
23 KiB
JSON
189 lines
23 KiB
JSON
{
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"questionId": "1615",
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"questionFrontendId": "1508",
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"categoryTitle": "Algorithms",
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"boundTopicId": 321850,
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"title": "Range Sum of Sorted Subarray Sums",
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"content": "<p>You are given the array <code>nums</code> consisting of <code>n</code> positive integers. You computed the sum of all non-empty continuous subarrays from the array and then sorted them in non-decreasing order, creating a new array of <code>n * (n + 1) / 2</code> numbers.</p>\n\n<p><em>Return the sum of the numbers from index </em><code>left</code><em> to index </em><code>right</code> (<strong>indexed from 1</strong>)<em>, inclusive, in the new array. </em>Since the answer can be a huge number return it modulo <code>10<sup>9</sup> + 7</code>.</p>\n\n<p> </p>\n<p><strong class=\"example\">Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> nums = [1,2,3,4], n = 4, left = 1, right = 5\n<strong>Output:</strong> 13 \n<strong>Explanation:</strong> All subarray sums are 1, 3, 6, 10, 2, 5, 9, 3, 7, 4. After sorting them in non-decreasing order we have the new array [1, 2, 3, 3, 4, 5, 6, 7, 9, 10]. The sum of the numbers from index le = 1 to ri = 5 is 1 + 2 + 3 + 3 + 4 = 13. \n</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> nums = [1,2,3,4], n = 4, left = 3, right = 4\n<strong>Output:</strong> 6\n<strong>Explanation:</strong> The given array is the same as example 1. We have the new array [1, 2, 3, 3, 4, 5, 6, 7, 9, 10]. The sum of the numbers from index le = 3 to ri = 4 is 3 + 3 = 6.\n</pre>\n\n<p><strong class=\"example\">Example 3:</strong></p>\n\n<pre>\n<strong>Input:</strong> nums = [1,2,3,4], n = 4, left = 1, right = 10\n<strong>Output:</strong> 50\n</pre>\n\n<p> </p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>n == nums.length</code></li>\n\t<li><code>1 <= nums.length <= 1000</code></li>\n\t<li><code>1 <= nums[i] <= 100</code></li>\n\t<li><code>1 <= left <= right <= n * (n + 1) / 2</code></li>\n</ul>\n",
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"translatedTitle": "子数组和排序后的区间和",
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"translatedContent": "<p>给你一个数组 <code>nums</code> ,它包含 <code>n</code> 个正整数。你需要计算所有非空连续子数组的和,并将它们按升序排序,得到一个新的包含 <code>n * (n + 1) / 2</code> 个数字的数组。</p>\n\n<p>请你返回在新数组中下标为<em> </em><code>left</code> 到 <code>right</code> <strong>(下标从 1 开始)</strong>的所有数字和(包括左右端点)。由于答案可能很大,请你将它对 10^9 + 7 取模后返回。</p>\n\n<p> </p>\n\n<p><strong>示例 1:</strong></p>\n\n<pre>\n<strong>输入:</strong>nums = [1,2,3,4], n = 4, left = 1, right = 5\n<strong>输出:</strong>13 \n<strong>解释:</strong>所有的子数组和为 1, 3, 6, 10, 2, 5, 9, 3, 7, 4 。将它们升序排序后,我们得到新的数组 [1, 2, 3, 3, 4, 5, 6, 7, 9, 10] 。下标从 le = 1 到 ri = 5 的和为 1 + 2 + 3 + 3 + 4 = 13 。\n</pre>\n\n<p><strong>示例 2:</strong></p>\n\n<pre>\n<strong>输入:</strong>nums = [1,2,3,4], n = 4, left = 3, right = 4\n<strong>输出:</strong>6\n<strong>解释:</strong>给定数组与示例 1 一样,所以新数组为 [1, 2, 3, 3, 4, 5, 6, 7, 9, 10] 。下标从 le = 3 到 ri = 4 的和为 3 + 3 = 6 。\n</pre>\n\n<p><strong>示例 3:</strong></p>\n\n<pre>\n<strong>输入:</strong>nums = [1,2,3,4], n = 4, left = 1, right = 10\n<strong>输出:</strong>50\n</pre>\n\n<p> </p>\n\n<p><strong>提示:</strong></p>\n\n<ul>\n\t<li><code>1 <= nums.length <= 10^3</code></li>\n\t<li><code>nums.length == n</code></li>\n\t<li><code>1 <= nums[i] <= 100</code></li>\n\t<li><code>1 <= left <= right <= n * (n + 1) / 2</code></li>\n</ul>\n",
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"Compute all sums and save it in array.",
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"Then just go from LEFT to RIGHT index and calculate answer modulo 1e9 + 7."
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