leetcode-problemset/leetcode-cn/originData/number-of-substrings-with-only-1s.json

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            "questionId": "1636",
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            "categoryTitle": "Algorithms",
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            "title": "Number of Substrings With Only 1s",
            "titleSlug": "number-of-substrings-with-only-1s",
            "content": "<p>Given a binary string <code>s</code>, return <em>the number of substrings with all characters</em> <code>1</code><em>&#39;s</em>. Since the answer may be too large, return it modulo <code>10<sup>9</sup> + 7</code>.</p>\n\n<p>&nbsp;</p>\n<p><strong class=\"example\">Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> s = &quot;0110111&quot;\n<strong>Output:</strong> 9\n<strong>Explanation:</strong> There are 9 substring in total with only 1&#39;s characters.\n&quot;1&quot; -&gt; 5 times.\n&quot;11&quot; -&gt; 3 times.\n&quot;111&quot; -&gt; 1 time.</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> s = &quot;101&quot;\n<strong>Output:</strong> 2\n<strong>Explanation:</strong> Substring &quot;1&quot; is shown 2 times in s.\n</pre>\n\n<p><strong class=\"example\">Example 3:</strong></p>\n\n<pre>\n<strong>Input:</strong> s = &quot;111111&quot;\n<strong>Output:</strong> 21\n<strong>Explanation:</strong> Each substring contains only 1&#39;s characters.\n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= s.length &lt;= 10<sup>5</sup></code></li>\n\t<li><code>s[i]</code> is either <code>&#39;0&#39;</code> or <code>&#39;1&#39;</code>.</li>\n</ul>\n",
            "translatedTitle": "仅含 1 的子串数",
            "translatedContent": "<p>给你一个二进制字符串 <code>s</code>（仅由 &#39;0&#39; 和 &#39;1&#39; 组成的字符串）。</p>\n\n<p>返回所有字符都为 1 的子字符串的数目。</p>\n\n<p>由于答案可能很大，请你将它对 10^9 + 7 取模后返回。</p>\n\n<p>&nbsp;</p>\n\n<p><strong>示例 1：</strong></p>\n\n<pre><strong>输入：</strong>s = &quot;0110111&quot;\n<strong>输出</strong>：9\n<strong>解释：</strong>共有 9 个子字符串仅由 &#39;1&#39; 组成\n&quot;1&quot; -&gt; 5 次\n&quot;11&quot; -&gt; 3 次\n&quot;111&quot; -&gt; 1 次</pre>\n\n<p><strong>示例 2：</strong></p>\n\n<pre><strong>输入：</strong>s = &quot;101&quot;\n<strong>输出：</strong>2\n<strong>解释：</strong>子字符串 &quot;1&quot; 在 s 中共出现 2 次\n</pre>\n\n<p><strong>示例 3：</strong></p>\n\n<pre><strong>输入：</strong>s = &quot;111111&quot;\n<strong>输出：</strong>21\n<strong>解释：</strong>每个子字符串都仅由 &#39;1&#39; 组成\n</pre>\n\n<p><strong>示例 4：</strong></p>\n\n<pre><strong>输入：</strong>s = &quot;000&quot;\n<strong>输出：</strong>0\n</pre>\n\n<p>&nbsp;</p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code>s[i] == &#39;0&#39;</code> 或 <code>s[i] == &#39;1&#39;</code></li>\n\t<li><code>1 &lt;= s.length &lt;= 10^5</code></li>\n</ul>\n",
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                "Count number of 1s in each consecutive-1 group. For a group with n consecutive 1s, the total contribution of it to the final answer is (n + 1) * n // 2."
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