leetcode-problemset/leetcode-cn/originData/number-of-subarrays-that-match-a-pattern-i.json

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            "title": "Number of Subarrays That Match a Pattern I",
            "titleSlug": "number-of-subarrays-that-match-a-pattern-i",
            "content": "<p>You are given a <strong>0-indexed</strong> integer array <code>nums</code> of size <code>n</code>, and a <strong>0-indexed</strong> integer array <code>pattern</code> of size <code>m</code> consisting of integers <code>-1</code>, <code>0</code>, and <code>1</code>.</p>\n\n<p>A <span data-keyword=\"subarray\">subarray</span> <code>nums[i..j]</code> of size <code>m + 1</code> is said to match the <code>pattern</code> if the following conditions hold for each element <code>pattern[k]</code>:</p>\n\n<ul>\n\t<li><code>nums[i + k + 1] &gt; nums[i + k]</code> if <code>pattern[k] == 1</code>.</li>\n\t<li><code>nums[i + k + 1] == nums[i + k]</code> if <code>pattern[k] == 0</code>.</li>\n\t<li><code>nums[i + k + 1] &lt; nums[i + k]</code> if <code>pattern[k] == -1</code>.</li>\n</ul>\n\n<p>Return <em>the<strong> count</strong> of subarrays in</em> <code>nums</code> <em>that match the</em> <code>pattern</code>.</p>\n\n<p>&nbsp;</p>\n<p><strong class=\"example\">Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> nums = [1,2,3,4,5,6], pattern = [1,1]\n<strong>Output:</strong> 4\n<strong>Explanation:</strong> The pattern [1,1] indicates that we are looking for strictly increasing subarrays of size 3. In the array nums, the subarrays [1,2,3], [2,3,4], [3,4,5], and [4,5,6] match this pattern.\nHence, there are 4 subarrays in nums that match the pattern.\n</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> nums = [1,4,4,1,3,5,5,3], pattern = [1,0,-1]\n<strong>Output:</strong> 2\n<strong>Explanation: </strong>Here, the pattern [1,0,-1] indicates that we are looking for a sequence where the first number is smaller than the second, the second is equal to the third, and the third is greater than the fourth. In the array nums, the subarrays [1,4,4,1], and [3,5,5,3] match this pattern.\nHence, there are 2 subarrays in nums that match the pattern.\n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>2 &lt;= n == nums.length &lt;= 100</code></li>\n\t<li><code>1 &lt;= nums[i] &lt;= 10<sup>9</sup></code></li>\n\t<li><code>1 &lt;= m == pattern.length &lt; n</code></li>\n\t<li><code>-1 &lt;= pattern[i] &lt;= 1</code></li>\n</ul>\n",
            "translatedTitle": "匹配模式数组的子数组数目 I",
            "translatedContent": "<p>给你一个下标从 <strong>0</strong>&nbsp;开始长度为 <code>n</code>&nbsp;的整数数组&nbsp;<code>nums</code>&nbsp;，和一个下标从 <code>0</code>&nbsp;开始长度为 <code>m</code>&nbsp;的整数数组&nbsp;<code>pattern</code>&nbsp;，<code>pattern</code>&nbsp;数组只包含整数&nbsp;<code>-1</code>&nbsp;，<code>0</code>&nbsp;和&nbsp;<code>1</code>&nbsp;。</p>\n\n<p>大小为 <code>m + 1</code>&nbsp;的<span data-keyword=\"subarray\">子数组</span>&nbsp;<code>nums[i..j]</code>&nbsp;如果对于每个元素 <code>pattern[k]</code>&nbsp;都满足以下条件，那么我们说这个子数组匹配模式数组&nbsp;<code>pattern</code>&nbsp;：</p>\n\n<ul>\n\t<li>如果 <code>pattern[k] == 1</code> ，那么 <code>nums[i + k + 1] &gt; nums[i + k]</code></li>\n\t<li>如果&nbsp;<code>pattern[k] == 0</code>&nbsp;，那么&nbsp;<code>nums[i + k + 1] == nums[i + k]</code></li>\n\t<li>如果&nbsp;<code>pattern[k] == -1</code>&nbsp;，那么&nbsp;<code>nums[i + k + 1] &lt; nums[i + k]</code></li>\n</ul>\n\n<p>请你返回匹配 <code>pattern</code>&nbsp;的 <code>nums</code>&nbsp;子数组的 <strong>数目</strong>&nbsp;。</p>\n\n<p>&nbsp;</p>\n\n<p><strong class=\"example\">示例 1：</strong></p>\n\n<pre>\n<b>输入：</b>nums = [1,2,3,4,5,6], pattern = [1,1]\n<b>输出：</b>4\n<b>解释：</b>模式 [1,1] 说明我们要找的子数组是长度为 3 且严格上升的。在数组 nums 中，子数组 [1,2,3] ，[2,3,4] ，[3,4,5] 和 [4,5,6] 都匹配这个模式。\n所以 nums 中总共有 4 个子数组匹配这个模式。\n</pre>\n\n<p><strong class=\"example\">示例 2：</strong></p>\n\n<pre>\n<b>输入：</b>nums = [1,4,4,1,3,5,5,3], pattern = [1,0,-1]\n<b>输出：</b>2\n<strong>解释：</strong>这里，模式数组 [1,0,-1] 说明我们需要找的子数组中，第一个元素小于第二个元素，第二个元素等于第三个元素，第三个元素大于第四个元素。在 nums 中，子数组 [1,4,4,1] 和 [3,5,5,3] 都匹配这个模式。\n所以 nums 中总共有 2 个子数组匹配这个模式。\n</pre>\n\n<p>&nbsp;</p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code>2 &lt;= n == nums.length &lt;= 100</code></li>\n\t<li><code>1 &lt;= nums[i] &lt;= 10<sup>9</sup></code></li>\n\t<li><code>1 &lt;= m == pattern.length &lt; n</code></li>\n\t<li><code>-1 &lt;= pattern[i] &lt;= 1</code></li>\n</ul>\n",
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