mirror of
https://gitee.com/coder-xiaomo/leetcode-problemset
synced 2025-01-10 18:48:13 +08:00
179 lines
20 KiB
JSON
179 lines
20 KiB
JSON
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"categoryTitle": "Algorithms",
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"boundTopicId": 102336,
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"title": "Number of Days Between Two Dates",
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"titleSlug": "number-of-days-between-two-dates",
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"content": "<p>Write a program to count the number of days between two dates.</p>\n\n<p>The two dates are given as strings, their format is <code>YYYY-MM-DD</code> as shown in the examples.</p>\n\n<p> </p>\n<p><strong class=\"example\">Example 1:</strong></p>\n<pre><strong>Input:</strong> date1 = \"2019-06-29\", date2 = \"2019-06-30\"\n<strong>Output:</strong> 1\n</pre><p><strong class=\"example\">Example 2:</strong></p>\n<pre><strong>Input:</strong> date1 = \"2020-01-15\", date2 = \"2019-12-31\"\n<strong>Output:</strong> 15\n</pre>\n<p> </p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li>The given dates are valid dates between the years <code>1971</code> and <code>2100</code>.</li>\n</ul>\n",
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"translatedTitle": "日期之间隔几天",
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"translatedContent": "<p>请你编写一个程序来计算两个日期之间隔了多少天。</p>\n\n<p>日期以字符串形式给出,格式为 <code>YYYY-MM-DD</code>,如示例所示。</p>\n\n<p> </p>\n\n<p><strong>示例 1:</strong></p>\n\n<pre><strong>输入:</strong>date1 = "2019-06-29", date2 = "2019-06-30"\n<strong>输出:</strong>1\n</pre>\n\n<p><strong>示例 2:</strong></p>\n\n<pre><strong>输入:</strong>date1 = "2020-01-15", date2 = "2019-12-31"\n<strong>输出:</strong>15\n</pre>\n\n<p> </p>\n\n<p><strong>提示:</strong></p>\n\n<ul>\n\t<li>给定的日期是 <code>1971</code> 年到 <code>2100</code> 年之间的有效日期。</li>\n</ul>\n",
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"difficulty": "Easy",
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"code": "class Solution {\npublic:\n int daysBetweenDates(string date1, string date2) {\n\n }\n};",
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"code": "class Solution {\n public int daysBetweenDates(String date1, String date2) {\n\n }\n}",
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"code": "class Solution(object):\n def daysBetweenDates(self, date1, date2):\n \"\"\"\n :type date1: str\n :type date2: str\n :rtype: int\n \"\"\"",
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"code": "# @param {String} date1\n# @param {String} date2\n# @return {Integer}\ndef days_between_dates(date1, date2)\n\nend",
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"code": "impl Solution {\n pub fn days_between_dates(date1: String, date2: String) -> i32 {\n\n }\n}",
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"code": "-spec days_between_dates(Date1 :: unicode:unicode_binary(), Date2 :: unicode:unicode_binary()) -> integer().\ndays_between_dates(Date1, Date2) ->\n .",
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"code": "defmodule Solution do\n @spec days_between_dates(date1 :: String.t, date2 :: String.t) :: integer\n def days_between_dates(date1, date2) do\n \n end\nend",
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"hints": [
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"Create a function f(date) that counts the number of days from 1900-01-01 to date. How can we calculate the answer ?",
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"The answer is just |f(date1) - f(date2)|.",
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"How to construct f(date) ?",
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"For each year from 1900 to year - 1 sum up 365 or 366 in case of leap years. Then sum up for each month the number of days, consider the case when the current year is leap, finally sum up the days."
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],
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"sampleTestCase": "\"2019-06-29\"\n\"2019-06-30\"",
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