leetcode-problemset/leetcode-cn/originData/neighboring-bitwise-xor.json

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        "question": {
            "questionId": "2792",
            "questionFrontendId": "2683",
            "categoryTitle": "Algorithms",
            "boundTopicId": 2265988,
            "title": "Neighboring Bitwise XOR",
            "titleSlug": "neighboring-bitwise-xor",
            "content": "<p>A <strong>0-indexed</strong> array <code>derived</code> with length <code>n</code> is derived by computing the <strong>bitwise XOR</strong>&nbsp;(&oplus;) of adjacent values in a <strong>binary array</strong> <code>original</code> of length <code>n</code>.</p>\n\n<p>Specifically, for each index <code>i</code> in the range <code>[0, n - 1]</code>:</p>\n\n<ul>\n\t<li>If <code>i = n - 1</code>, then <code>derived[i] = original[i] &oplus; original[0]</code>.</li>\n\t<li>Otherwise, <code>derived[i] = original[i] &oplus; original[i + 1]</code>.</li>\n</ul>\n\n<p>Given an array <code>derived</code>, your task is to determine whether there exists a <strong>valid binary array</strong> <code>original</code> that could have formed <code>derived</code>.</p>\n\n<p>Return <em><strong>true</strong> if such an array exists or <strong>false</strong> otherwise.</em></p>\n\n<ul>\n\t<li>A binary array is an array containing only <strong>0&#39;s</strong> and <strong>1&#39;s</strong></li>\n</ul>\n\n<p>&nbsp;</p>\n<p><strong class=\"example\">Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> derived = [1,1,0]\n<strong>Output:</strong> true\n<strong>Explanation:</strong> A valid original array that gives derived is [0,1,0].\nderived[0] = original[0] &oplus; original[1] = 0 &oplus; 1 = 1 \nderived[1] = original[1] &oplus; original[2] = 1 &oplus; 0 = 1\nderived[2] = original[2] &oplus; original[0] = 0 &oplus; 0 = 0\n</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> derived = [1,1]\n<strong>Output:</strong> true\n<strong>Explanation:</strong> A valid original array that gives derived is [0,1].\nderived[0] = original[0] &oplus; original[1] = 1\nderived[1] = original[1] &oplus; original[0] = 1\n</pre>\n\n<p><strong class=\"example\">Example 3:</strong></p>\n\n<pre>\n<strong>Input:</strong> derived = [1,0]\n<strong>Output:</strong> false\n<strong>Explanation:</strong> There is no valid original array that gives derived.\n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>n == derived.length</code></li>\n\t<li><code>1 &lt;= n&nbsp;&lt;= 10<sup>5</sup></code></li>\n\t<li>The values in <code>derived</code>&nbsp;are either <strong>0&#39;s</strong> or <strong>1&#39;s</strong></li>\n</ul>\n",
            "translatedTitle": "相邻值的按位异或",
            "translatedContent": "<p>下标从 <strong>0</strong> 开始、长度为 <code>n</code> 的数组 <code>derived</code> 是由同样长度为 <code>n</code> 的原始 <strong>二进制数组</strong> <code>original</code> 通过计算相邻值的 <strong>按位异或（⊕）</strong>派生而来。</p>\n\n<p>特别地，对于范围&nbsp;<code>[0, n - 1]</code> 内的每个下标 <code>i</code> ：</p>\n\n<ul>\n\t<li>如果 <code>i = n - 1</code> ，那么 <code>derived[i] = original[i] ⊕ original[0]</code></li>\n\t<li>否则 <code>derived[i] = original[i] ⊕ original[i + 1]</code></li>\n</ul>\n\n<p>给你一个数组 <code>derived</code> ，请判断是否存在一个能够派生得到 <code>derived</code> 的 <strong>有效原始二进制数组</strong> <code>original</code> 。</p>\n\n<p>如果存在满足要求的原始二进制数组，返回 <em><strong>true</strong> </em>；否则，返回<em> <strong>false</strong> </em>。</p>\n\n<ul>\n\t<li>二进制数组是仅由 <strong>0</strong> 和 <strong>1</strong> 组成的数组。</li>\n</ul>\n\n<p>&nbsp;</p>\n\n<p><strong>示例 1：</strong></p>\n\n<pre><strong>输入：</strong>derived = [1,1,0]\n<strong>输出：</strong>true\n<strong>解释：</strong>能够派生得到 [1,1,0] 的有效原始二进制数组是 [0,1,0] ：\nderived[0] = original[0] ⊕ original[1] = 0 ⊕ 1 = 1 \nderived[1] = original[1] ⊕ original[2] = 1 ⊕ 0 = 1\nderived[2] = original[2] ⊕ original[0] = 0 ⊕ 0 = 0\n</pre>\n\n<p><strong>示例 2：</strong></p>\n\n<pre><strong>输入：</strong>derived = [1,1]\n<strong>输出：</strong>true\n<strong>解释：</strong>能够派生得到 [1,1] 的有效原始二进制数组是 [0,1] ：\nderived[0] = original[0] ⊕ original[1] = 1\nderived[1] = original[1] ⊕ original[0] = 1\n</pre>\n\n<p><strong>示例 3：</strong></p>\n\n<pre><strong>输入：</strong>derived = [1,0]\n<strong>输出：</strong>false\n<strong>解释：</strong>不存在能够派生得到 [1,0] 的有效原始二进制数组。\n</pre>\n\n<p>&nbsp;</p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code>n == derived.length</code></li>\n\t<li><code>1 &lt;= n&nbsp;&lt;= 10<sup>5</sup></code></li>\n\t<li><code>derived</code> 中的值不是 <strong>0</strong> 就是 <strong>1</strong> 。</li>\n</ul>\n",
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            "hints": [
                "Understand that from the original element, we are using each element twice to construct the derived array",
                "The xor-sum of the derived array should be 0 since there is always a duplicate occurrence of each element."
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