leetcode-problemset/leetcode-cn/originData/most-popular-video-creator.json

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        "question": {
            "questionId": "2543",
            "questionFrontendId": "2456",
            "categoryTitle": "Algorithms",
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            "title": "Most Popular Video Creator",
            "titleSlug": "most-popular-video-creator",
            "content": "<p>You are given two string arrays <code>creators</code> and <code>ids</code>, and an integer array <code>views</code>, all of length <code>n</code>. The <code>i<sup>th</sup></code> video on a platform was created by <code>creator[i]</code>, has an id of <code>ids[i]</code>, and has <code>views[i]</code> views.</p>\n\n<p>The <strong>popularity</strong> of a creator is the <strong>sum</strong> of the number of views on <strong>all</strong> of the creator&#39;s videos. Find the creator with the <strong>highest</strong> popularity and the id of their <strong>most</strong> viewed video.</p>\n\n<ul>\n\t<li>If multiple creators have the highest popularity, find all of them.</li>\n\t<li>If multiple videos have the highest view count for a creator, find the lexicographically <strong>smallest</strong> id.</li>\n</ul>\n\n<p>Return<em> a 2D array of strings </em><code>answer</code><em> where </em><code>answer[i] = [creator<sub>i</sub>, id<sub>i</sub>]</code><em> means that </em><code>creator<sub>i</sub></code> <em>has the <strong>highest</strong> popularity and </em><code>id<sub>i</sub></code><em> is the id of their most popular video.</em> The answer can be returned in any order.</p>\n\n<p>&nbsp;</p>\n<p><strong class=\"example\">Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> creators = [&quot;alice&quot;,&quot;bob&quot;,&quot;alice&quot;,&quot;chris&quot;], ids = [&quot;one&quot;,&quot;two&quot;,&quot;three&quot;,&quot;four&quot;], views = [5,10,5,4]\n<strong>Output:</strong> [[&quot;alice&quot;,&quot;one&quot;],[&quot;bob&quot;,&quot;two&quot;]]\n<strong>Explanation:</strong>\nThe popularity of alice is 5 + 5 = 10.\nThe popularity of bob is 10.\nThe popularity of chris is 4.\nalice and bob are the most popular creators.\nFor bob, the video with the highest view count is &quot;two&quot;.\nFor alice, the videos with the highest view count are &quot;one&quot; and &quot;three&quot;. Since &quot;one&quot; is lexicographically smaller than &quot;three&quot;, it is included in the answer.\n</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> creators = [&quot;alice&quot;,&quot;alice&quot;,&quot;alice&quot;], ids = [&quot;a&quot;,&quot;b&quot;,&quot;c&quot;], views = [1,2,2]\n<strong>Output:</strong> [[&quot;alice&quot;,&quot;b&quot;]]\n<strong>Explanation:</strong>\nThe videos with id &quot;b&quot; and &quot;c&quot; have the highest view count.\nSince &quot;b&quot; is lexicographically smaller than &quot;c&quot;, it is included in the answer.\n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>n == creators.length == ids.length == views.length</code></li>\n\t<li><code>1 &lt;= n &lt;= 10<sup>5</sup></code></li>\n\t<li><code>1 &lt;= creators[i].length, ids[i].length &lt;= 5</code></li>\n\t<li><code>creators[i]</code> and <code>ids[i]</code> consist only of lowercase English letters.</li>\n\t<li><code>0 &lt;= views[i] &lt;= 10<sup>5</sup></code></li>\n</ul>\n",
            "translatedTitle": "最流行的视频创作者",
            "translatedContent": "<p>给你两个字符串数组 <code>creators</code> 和 <code>ids</code> ，和一个整数数组 <code>views</code> ，所有数组的长度都是 <code>n</code> 。平台上第 <code>i</code> 个视频者是&nbsp;<code>creator[i]</code> ，视频分配的 id 是 <code>ids[i]</code> ，且播放量为 <code>views[i]</code> 。</p>\n\n<p>视频创作者的 <strong>流行度</strong> 是该创作者的 <strong>所有</strong> 视频的播放量的 <strong>总和</strong> 。请找出流行度 <strong>最高</strong> 创作者以及该创作者播放量 <strong>最大</strong> 的视频的 id 。</p>\n\n<ul>\n\t<li>如果存在多个创作者流行度都最高，则需要找出所有符合条件的创作者。</li>\n\t<li>如果某个创作者存在多个播放量最高的视频，则只需要找出字典序最小的 <code>id</code> 。</li>\n</ul>\n\n<p>返回一个二维字符串数组<em> </em><code>answer</code><em> </em>，其中<em> </em><code>answer[i] = [creator<sub>i</sub>, id<sub>i</sub>]</code><em> </em>表示<em> </em><code>creator<sub>i</sub></code> 的流行度 <strong>最高</strong> 且其最流行的视频 id 是<em> </em><code>id<sub>i</sub></code><em> </em>，可以按任何顺序返回该结果<em>。</em></p>\n\n<p>&nbsp;</p>\n\n<p><strong>示例 1：</strong></p>\n\n<pre>\n<strong>输入：</strong>creators = [\"alice\",\"bob\",\"alice\",\"chris\"], ids = [\"one\",\"two\",\"three\",\"four\"], views = [5,10,5,4]\n<strong>输出：</strong>[[\"alice\",\"one\"],[\"bob\",\"two\"]]\n<strong>解释：</strong>\nalice 的流行度是 5 + 5 = 10 。\nbob 的流行度是 10 。\nchris 的流行度是 4 。\nalice 和 bob 是流行度最高的创作者。\nbob 播放量最高的视频 id 为 \"two\" 。\nalice 播放量最高的视频 id 是 \"one\" 和 \"three\" 。由于 \"one\" 的字典序比 \"three\" 更小，所以结果中返回的 id 是 \"one\" 。\n</pre>\n\n<p><strong>示例 2：</strong></p>\n\n<pre>\n<strong>输入：</strong>creators = [\"alice\",\"alice\",\"alice\"], ids = [\"a\",\"b\",\"c\"], views = [1,2,2]\n<strong>输出：</strong>[[\"alice\",\"b\"]]\n<strong>解释：</strong>\nid 为 \"b\" 和 \"c\" 的视频都满足播放量最高的条件。\n由于 \"b\" 的字典序比 \"c\" 更小，所以结果中返回的 id 是 \"b\" 。\n</pre>\n\n<p>&nbsp;</p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code>n == creators.length == ids.length == views.length</code></li>\n\t<li><code>1 &lt;= n &lt;= 10<sup>5</sup></code></li>\n\t<li><code>1 &lt;= creators[i].length, ids[i].length &lt;= 5</code></li>\n\t<li><code>creators[i]</code> 和 <code>ids[i]</code> 仅由小写英文字母组成</li>\n\t<li><code>0 &lt;= views[i] &lt;= 10<sup>5</sup></code></li>\n</ul>\n",
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                    "lang": "C++",
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                    "code": "class Solution {\npublic:\n    vector<vector<string>> mostPopularCreator(vector<string>& creators, vector<string>& ids, vector<int>& views) {\n        \n    }\n};",
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                    "code": "class Solution(object):\n    def mostPopularCreator(self, creators, ids, views):\n        \"\"\"\n        :type creators: List[str]\n        :type ids: List[str]\n        :type views: List[int]\n        :rtype: List[List[str]]\n        \"\"\"",
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                    "code": "class Solution:\n    def mostPopularCreator(self, creators: List[str], ids: List[str], views: List[int]) -> List[List[str]]:",
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                    "code": "/**\n * Return an array of arrays of size *returnSize.\n * The sizes of the arrays are returned as *returnColumnSizes array.\n * Note: Both returned array and *columnSizes array must be malloced, assume caller calls free().\n */\nchar*** mostPopularCreator(char** creators, int creatorsSize, char** ids, int idsSize, int* views, int viewsSize, int* returnSize, int** returnColumnSizes) {\n    \n}",
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                    "code": "public class Solution {\n    public IList<IList<string>> MostPopularCreator(string[] creators, string[] ids, int[] views) {\n\n    }\n}",
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                    "code": "/**\n * @param {string[]} creators\n * @param {string[]} ids\n * @param {number[]} views\n * @return {string[][]}\n */\nvar mostPopularCreator = function(creators, ids, views) {\n\n};",
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                    "code": "class Solution {\n\n    /**\n     * @param String[] $creators\n     * @param String[] $ids\n     * @param Integer[] $views\n     * @return String[][]\n     */\n    function mostPopularCreator($creators, $ids, $views) {\n\n    }\n}",
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                    "code": "class Solution {\n  List<List<String>> mostPopularCreator(List<String> creators, List<String> ids, List<int> views) {\n    \n  }\n}",
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                    "code": "object Solution {\n    def mostPopularCreator(creators: Array[String], ids: Array[String], views: Array[Int]): List[List[String]] = {\n\n    }\n}",
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                    "code": "impl Solution {\n    pub fn most_popular_creator(creators: Vec<String>, ids: Vec<String>, views: Vec<i32>) -> Vec<Vec<String>> {\n\n    }\n}",
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                    "code": "-spec most_popular_creator(Creators :: [unicode:unicode_binary()], Ids :: [unicode:unicode_binary()], Views :: [integer()]) -> [[unicode:unicode_binary()]].\nmost_popular_creator(Creators, Ids, Views) ->\n  .",
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                "Use a hash table to store and categorize videos based on their creator.",
                "For each creator, iterate through all their videos and use three variables to keep track of their popularity, their most popular video, and the id of their most popular video."
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href=\\\"https:\\/\\/github.com\\/emirpasic\\/gods\\/tree\\/v1.18.1\\\" target=\\\"_blank\\\">https:\\/\\/godoc.org\\/github.com\\/emirpasic\\/gods@v1.18.1<\\/a> \\u7b2c\\u4e09\\u65b9\\u5e93\\u3002<\\/p>\"],\"python3\":[\"Python3\",\"<p>\\u7248\\u672c\\uff1a<code>Python 3.10<\\/code><\\/p>\\r\\n\\r\\n<p>\\u4e3a\\u4e86\\u65b9\\u4fbf\\u8d77\\u89c1\\uff0c\\u5927\\u90e8\\u5206\\u5e38\\u7528\\u5e93\\u5df2\\u7ecf\\u88ab\\u81ea\\u52a8 \\u5bfc\\u5165\\uff0c\\u5982<a href=\\\"https:\\/\\/docs.python.org\\/3\\/library\\/array.html\\\" target=\\\"_blank\\\">array<\\/a>, <a href=\\\"https:\\/\\/docs.python.org\\/3\\/library\\/bisect.html\\\" target=\\\"_blank\\\">bisect<\\/a>, <a href=\\\"https:\\/\\/docs.python.org\\/3\\/library\\/collections.html\\\" target=\\\"_blank\\\">collections<\\/a>\\u3002 \\u5982\\u679c\\u60a8\\u9700\\u8981\\u4f7f\\u7528\\u5176\\u4ed6\\u5e93\\u51fd\\u6570\\uff0c\\u8bf7\\u81ea\\u884c\\u5bfc\\u5165\\u3002<\\/p>\\r\\n\\r\\n<p>\\u5982\\u9700\\u4f7f\\u7528 Map\\/TreeMap 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