leetcode-problemset/leetcode-cn/originData/minimum-operations-to-make-all-array-elements-equal.json

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            "questionId": "2718",
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            "categoryTitle": "Algorithms",
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            "title": "Minimum Operations to Make All Array Elements Equal",
            "titleSlug": "minimum-operations-to-make-all-array-elements-equal",
            "content": "<p>You are given an array <code>nums</code> consisting of positive integers.</p>\n\n<p>You are also given an integer array <code>queries</code> of size <code>m</code>. For the <code>i<sup>th</sup></code> query, you want to make all of the elements of <code>nums</code> equal to<code> queries[i]</code>. You can perform the following operation on the array <strong>any</strong> number of times:</p>\n\n<ul>\n\t<li><strong>Increase</strong> or <strong>decrease</strong> an element of the array by <code>1</code>.</li>\n</ul>\n\n<p>Return <em>an array </em><code>answer</code><em> of size </em><code>m</code><em> where </em><code>answer[i]</code><em> is the <strong>minimum</strong> number of operations to make all elements of </em><code>nums</code><em> equal to </em><code>queries[i]</code>.</p>\n\n<p><strong>Note</strong> that after each query the array is reset to its original state.</p>\n\n<p>&nbsp;</p>\n<p><strong class=\"example\">Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> nums = [3,1,6,8], queries = [1,5]\n<strong>Output:</strong> [14,10]\n<strong>Explanation:</strong> For the first query we can do the following operations:\n- Decrease nums[0] 2 times, so that nums = [1,1,6,8].\n- Decrease nums[2] 5 times, so that nums = [1,1,1,8].\n- Decrease nums[3] 7 times, so that nums = [1,1,1,1].\nSo the total number of operations for the first query is 2 + 5 + 7 = 14.\nFor the second query we can do the following operations:\n- Increase nums[0] 2 times, so that nums = [5,1,6,8].\n- Increase nums[1] 4 times, so that nums = [5,5,6,8].\n- Decrease nums[2] 1 time, so that nums = [5,5,5,8].\n- Decrease nums[3] 3 times, so that nums = [5,5,5,5].\nSo the total number of operations for the second query is 2 + 4 + 1 + 3 = 10.\n</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> nums = [2,9,6,3], queries = [10]\n<strong>Output:</strong> [20]\n<strong>Explanation:</strong> We can increase each value in the array to 10. The total number of operations will be 8 + 1 + 4 + 7 = 20.\n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>n == nums.length</code></li>\n\t<li><code>m == queries.length</code></li>\n\t<li><code>1 &lt;= n, m &lt;= 10<sup>5</sup></code></li>\n\t<li><code>1 &lt;= nums[i], queries[i] &lt;= 10<sup>9</sup></code></li>\n</ul>\n",
            "translatedTitle": "使数组元素全部相等的最少操作次数",
            "translatedContent": "<p>给你一个正整数数组&nbsp;<code>nums</code>&nbsp;。</p>\n\n<p>同时给你一个长度为 <code>m</code>&nbsp;的整数数组&nbsp;<code>queries</code>&nbsp;。第 <code>i</code>&nbsp;个查询中，你需要将 <code>nums</code>&nbsp;中所有元素变成&nbsp;<code>queries[i]</code>&nbsp;。你可以执行以下操作&nbsp;<strong>任意</strong>&nbsp;次：</p>\n\n<ul>\n\t<li>将数组里一个元素&nbsp;<strong>增大</strong>&nbsp;或者&nbsp;<strong>减小</strong>&nbsp;<code>1</code>&nbsp;。</li>\n</ul>\n\n<p>请你返回一个长度为 <code>m</code>&nbsp;的数组<em>&nbsp;</em><code>answer</code>&nbsp;，其中<em>&nbsp;</em><code>answer[i]</code>是将&nbsp;<code>nums</code>&nbsp;中所有元素变成&nbsp;<code>queries[i]</code>&nbsp;的&nbsp;<strong>最少</strong>&nbsp;操作次数。</p>\n\n<p><strong>注意</strong>，每次查询后，数组变回最开始的值。</p>\n\n<p>&nbsp;</p>\n\n<p><strong>示例 1：</strong></p>\n\n<pre><b>输入：</b>nums = [3,1,6,8], queries = [1,5]\n<b>输出：</b>[14,10]\n<b>解释：</b>第一个查询，我们可以执行以下操作：\n- 将 nums[0] 减小 2 次，nums = [1,1,6,8] 。\n- 将 nums[2] 减小 5 次，nums = [1,1,1,8] 。\n- 将 nums[3] 减小 7 次，nums = [1,1,1,1] 。\n第一个查询的总操作次数为 2 + 5 + 7 = 14 。\n第二个查询，我们可以执行以下操作：\n- 将 nums[0] 增大 2 次，nums = [5,1,6,8] 。\n- 将 nums[1] 增大 4 次，nums = [5,5,6,8] 。\n- 将 nums[2] 减小 1 次，nums = [5,5,5,8] 。\n- 将 nums[3] 减小 3 次，nums = [5,5,5,5] 。\n第二个查询的总操作次数为 2 + 4 + 1 + 3 = 10 。\n</pre>\n\n<p><strong>示例 2：</strong></p>\n\n<pre><b>输入：</b>nums = [2,9,6,3], queries = [10]\n<b>输出：</b>[20]\n<b>解释：</b>我们可以将数组中所有元素都增大到 10 ，总操作次数为 8 + 1 + 4 + 7 = 20 。\n</pre>\n\n<p>&nbsp;</p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code>n == nums.length</code></li>\n\t<li><code>m == queries.length</code></li>\n\t<li><code>1 &lt;= n, m &lt;= 10<sup>5</sup></code></li>\n\t<li><code>1 &lt;= nums[i], queries[i] &lt;= 10<sup>9</sup></code></li>\n</ul>\n",
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