leetcode-problemset/leetcode-cn/originData/minimum-number-of-moves-to-make-palindrome.json

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            "categoryTitle": "Algorithms",
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            "title": "Minimum Number of Moves to Make Palindrome",
            "titleSlug": "minimum-number-of-moves-to-make-palindrome",
            "content": "<p>You are given a string <code>s</code> consisting only of lowercase English letters.</p>\n\n<p>In one <strong>move</strong>, you can select any two <strong>adjacent</strong> characters of <code>s</code> and swap them.</p>\n\n<p>Return <em>the <strong>minimum number of moves</strong> needed to make</em> <code>s</code> <em>a palindrome</em>.</p>\n\n<p><strong>Note</strong> that the input will be generated such that <code>s</code> can always be converted to a palindrome.</p>\n\n<p>&nbsp;</p>\n<p><strong class=\"example\">Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> s = &quot;aabb&quot;\n<strong>Output:</strong> 2\n<strong>Explanation:</strong>\nWe can obtain two palindromes from s, &quot;abba&quot; and &quot;baab&quot;. \n- We can obtain &quot;abba&quot; from s in 2 moves: &quot;a<u><strong>ab</strong></u>b&quot; -&gt; &quot;ab<u><strong>ab</strong></u>&quot; -&gt; &quot;abba&quot;.\n- We can obtain &quot;baab&quot; from s in 2 moves: &quot;a<u><strong>ab</strong></u>b&quot; -&gt; &quot;<u><strong>ab</strong></u>ab&quot; -&gt; &quot;baab&quot;.\nThus, the minimum number of moves needed to make s a palindrome is 2.\n</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> s = &quot;letelt&quot;\n<strong>Output:</strong> 2\n<strong>Explanation:</strong>\nOne of the palindromes we can obtain from s in 2 moves is &quot;lettel&quot;.\nOne of the ways we can obtain it is &quot;lete<u><strong>lt</strong></u>&quot; -&gt; &quot;let<u><strong>et</strong></u>l&quot; -&gt; &quot;lettel&quot;.\nOther palindromes such as &quot;tleelt&quot; can also be obtained in 2 moves.\nIt can be shown that it is not possible to obtain a palindrome in less than 2 moves.\n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= s.length &lt;= 2000</code></li>\n\t<li><code>s</code> consists only of lowercase English letters.</li>\n\t<li><code>s</code> can be converted to a palindrome using a finite number of moves.</li>\n</ul>\n",
            "translatedTitle": "得到回文串的最少操作次数",
            "translatedContent": "<p>给你一个只包含小写英文字母的字符串&nbsp;<code>s</code>&nbsp;。</p>\n\n<p>每一次 <strong>操作</strong>&nbsp;，你可以选择 <code>s</code>&nbsp;中两个 <strong>相邻</strong>&nbsp;的字符，并将它们交换。</p>\n\n<p>请你返回将 <code>s</code>&nbsp;变成回文串的 <strong>最少操作次数</strong>&nbsp;。</p>\n\n<p><strong>注意</strong>&nbsp;，输入数据会确保&nbsp;<code>s</code>&nbsp;一定能变成一个回文串。</p>\n\n<p>&nbsp;</p>\n\n<p><strong>示例 1：</strong></p>\n\n<pre><b>输入：</b>s = \"aabb\"\n<b>输出：</b>2\n<strong>解释：</strong>\n我们可以将 s 变成 2 个回文串，\"abba\" 和 \"baab\" 。\n- 我们可以通过 2 次操作得到 \"abba\" ：\"a<em><strong>ab</strong></em>b\" -&gt; \"ab<em><strong>ab</strong></em>\" -&gt; \"abba\" 。\n- 我们可以通过 2 次操作得到 \"baab\" ：\"a<em><strong>ab</strong></em>b\" -&gt; \"<em><strong>ab</strong></em>ab\" -&gt; \"baab\" 。\n因此，得到回文串的最少总操作次数为 2 。\n</pre>\n\n<p><strong>示例 2：</strong></p>\n\n<pre><b>输入：</b>s = \"letelt\"\n<b>输出：</b>2\n<strong>解释：</strong>\n通过 2 次操作从 s 能得到回文串 \"lettel\" 。\n其中一种方法是：\"lete<em><strong>lt</strong></em>\" -&gt; \"let<em><strong>et</strong></em>l\" -&gt; \"lettel\" 。\n其他回文串比方说 \"tleelt\" 也可以通过 2 次操作得到。\n可以证明少于 2 次操作，无法得到回文串。\n</pre>\n\n<p>&nbsp;</p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= s.length &lt;= 2000</code></li>\n\t<li><code>s</code>&nbsp;只包含小写英文字母。</li>\n\t<li><code>s</code>&nbsp;可以通过有限次操作得到一个回文串。</li>\n</ul>\n",
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                "Consider a greedy strategy.",
                "Let’s start by making the leftmost and rightmost characters match with some number of swaps.",
                "If we figure out how to do that using the minimum number of swaps, then we can delete the leftmost and rightmost characters and solve the problem recursively."
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