leetcode-problemset/leetcode-cn/originData/minimum-height-tree-lcci.json

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        "question": {
            "questionId": "100174",
            "questionFrontendId": "面试题 04.02",
            "categoryTitle": "LCCI",
            "boundTopicId": 46188,
            "title": "Minimum Height Tree LCCI",
            "titleSlug": "minimum-height-tree-lcci",
            "content": "<p>Given a sorted (increasing order) array with unique integer elements, write an algo&shy;rithm to create a binary search tree with minimal height.</p>\r\n\r\n<p><strong>Example:</strong></p>\r\n\r\n<pre>\r\nGiven sorted array: [-10,-3,0,5,9],\r\n\r\nOne possible answer is: [0,-3,9,-10,null,5]，which represents the following tree: \r\n\r\n          0 \r\n         / \\ \r\n       -3   9 \r\n       /   / \r\n     -10  5 \r\n</pre>\r\n",
            "translatedTitle": "最小高度树",
            "translatedContent": "<p>给定一个有序整数数组，元素各不相同且按升序排列，编写一个算法，创建一棵高度最小的二叉搜索树。</p><strong>示例:</strong><pre>给定有序数组: [-10,-3,0,5,9],<br><br>一个可能的答案是：[0,-3,9,-10,null,5]，它可以表示下面这个高度平衡二叉搜索树：<br><br>          0 <br>         / &#92 <br>       -3   9 <br>       /   / <br>     -10  5 <br></pre>",
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                    "code": "/**\n * Definition for a binary tree node.\n * class TreeNode {\n *     val: number\n *     left: TreeNode | null\n *     right: TreeNode | null\n *     constructor(val?: number, left?: TreeNode | null, right?: TreeNode | null) {\n *         this.val = (val===undefined ? 0 : val)\n *         this.left = (left===undefined ? null : left)\n *         this.right = (right===undefined ? null : right)\n *     }\n * }\n */\n\nfunction sortedArrayToBST(nums: number[]): TreeNode | null {\n\n};",
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                    "code": "/**\n * Definition for a binary tree node.\n * class TreeNode {\n *   int val;\n *   TreeNode? left;\n *   TreeNode? right;\n *   TreeNode([this.val = 0, this.left, this.right]);\n * }\n */\nclass Solution {\n  TreeNode? sortedArrayToBST(List<int> nums) {\n\n  }\n}",
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                    "code": "/**\n * Definition for a binary tree node.\n * type TreeNode struct {\n *     Val int\n *     Left *TreeNode\n *     Right *TreeNode\n * }\n */\nfunc sortedArrayToBST(nums []int) *TreeNode {\n\n}",
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                    "code": "// Definition for a binary tree node.\n// #[derive(Debug, PartialEq, Eq)]\n// pub struct TreeNode {\n//   pub val: i32,\n//   pub left: Option<Rc<RefCell<TreeNode>>>,\n//   pub right: Option<Rc<RefCell<TreeNode>>>,\n// }\n// \n// impl TreeNode {\n//   #[inline]\n//   pub fn new(val: i32) -> Self {\n//     TreeNode {\n//       val,\n//       left: None,\n//       right: None\n//     }\n//   }\n// }\nuse std::rc::Rc;\nuse std::cell::RefCell;\nimpl Solution {\n    pub fn sorted_array_to_bst(nums: Vec<i32>) -> Option<Rc<RefCell<TreeNode>>> {\n\n    }\n}",
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                    "code": "; Definition for a binary tree node.\n#|\n\n; val : integer?\n; left : (or/c tree-node? #f)\n; right : (or/c tree-node? #f)\n(struct tree-node\n  (val left right) #:mutable #:transparent)\n\n; constructor\n(define (make-tree-node [val 0])\n  (tree-node val #f #f))\n\n|#\n\n(define/contract (sorted-array-to-bst nums)\n  (-> (listof exact-integer?) (or/c tree-node? #f))\n\n  )",
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                    "code": "%% Definition for a binary tree node.\n%%\n%% -record(tree_node, {val = 0 :: integer(),\n%%                     left = null  :: 'null' | #tree_node{},\n%%                     right = null :: 'null' | #tree_node{}}).\n\n-spec sorted_array_to_bst(Nums :: [integer()]) -> #tree_node{} | null.\nsorted_array_to_bst(Nums) ->\n  .",
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                    "code": "# Definition for a binary tree node.\n#\n# defmodule TreeNode do\n#   @type t :: %__MODULE__{\n#           val: integer,\n#           left: TreeNode.t() | nil,\n#           right: TreeNode.t() | nil\n#         }\n#   defstruct val: 0, left: nil, right: nil\n# end\n\ndefmodule Solution do\n  @spec sorted_array_to_bst(nums :: [integer]) :: TreeNode.t | nil\n  def sorted_array_to_bst(nums) do\n\n  end\nend",
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            "hints": [
                "最小的二叉树在每个节点左侧的节点数与右侧相同。现在我们把注意力放到根节点上，你要如何保证位于根的左侧和右侧的节点数量大致相同呢？",
                "你可以通过找到“理想”的下一个要添加的元素和多次调用insertValue来实现。这样效率会有点儿低，因为你必须反复遍历树。尝试用递归代替。你能把这个问题分解为子问题吗？",
                "想象一下，我们有一个createMinimalTree方法可以返回给定数组的最小树（但由于一些奇怪的原因不在树的根上操作）。你能用这个操作树的根节点吗？你能写出函数的基线条件吗？非常好！那基本上是整个函数了。"
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