mirror of
https://gitee.com/coder-xiaomo/leetcode-problemset
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177 lines
26 KiB
JSON
177 lines
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"title": "Minimum Cost to Reach Destination in Time",
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"content": "<p>There is a country of <code>n</code> cities numbered from <code>0</code> to <code>n - 1</code> where <strong>all the cities are connected</strong> by bi-directional roads. The roads are represented as a 2D integer array <code>edges</code> where <code>edges[i] = [x<sub>i</sub>, y<sub>i</sub>, time<sub>i</sub>]</code> denotes a road between cities <code>x<sub>i</sub></code> and <code>y<sub>i</sub></code> that takes <code>time<sub>i</sub></code> minutes to travel. There may be multiple roads of differing travel times connecting the same two cities, but no road connects a city to itself.</p>\n\n<p>Each time you pass through a city, you must pay a passing fee. This is represented as a <strong>0-indexed</strong> integer array <code>passingFees</code> of length <code>n</code> where <code>passingFees[j]</code> is the amount of dollars you must pay when you pass through city <code>j</code>.</p>\n\n<p>In the beginning, you are at city <code>0</code> and want to reach city <code>n - 1</code> in <code>maxTime</code><strong> minutes or less</strong>. The <strong>cost</strong> of your journey is the <strong>summation of passing fees</strong> for each city that you passed through at some moment of your journey (<strong>including</strong> the source and destination cities).</p>\n\n<p>Given <code>maxTime</code>, <code>edges</code>, and <code>passingFees</code>, return <em>the <strong>minimum cost</strong> to complete your journey, or </em><code>-1</code><em> if you cannot complete it within </em><code>maxTime</code><em> minutes</em>.</p>\n\n<p> </p>\n<p><strong class=\"example\">Example 1:</strong></p>\n\n<p><img alt=\"\" src=\"https://assets.leetcode.com/uploads/2021/06/04/leetgraph1-1.png\" style=\"width: 371px; height: 171px;\" /></p>\n\n<pre>\n<strong>Input:</strong> maxTime = 30, edges = [[0,1,10],[1,2,10],[2,5,10],[0,3,1],[3,4,10],[4,5,15]], passingFees = [5,1,2,20,20,3]\n<strong>Output:</strong> 11\n<strong>Explanation:</strong> The path to take is 0 -> 1 -> 2 -> 5, which takes 30 minutes and has $11 worth of passing fees.\n</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<p><strong><img alt=\"\" src=\"https://assets.leetcode.com/uploads/2021/06/04/copy-of-leetgraph1-1.png\" style=\"width: 371px; height: 171px;\" /></strong></p>\n\n<pre>\n<strong>Input:</strong> maxTime = 29, edges = [[0,1,10],[1,2,10],[2,5,10],[0,3,1],[3,4,10],[4,5,15]], passingFees = [5,1,2,20,20,3]\n<strong>Output:</strong> 48\n<strong>Explanation:</strong> The path to take is 0 -> 3 -> 4 -> 5, which takes 26 minutes and has $48 worth of passing fees.\nYou cannot take path 0 -> 1 -> 2 -> 5 since it would take too long.\n</pre>\n\n<p><strong class=\"example\">Example 3:</strong></p>\n\n<pre>\n<strong>Input:</strong> maxTime = 25, edges = [[0,1,10],[1,2,10],[2,5,10],[0,3,1],[3,4,10],[4,5,15]], passingFees = [5,1,2,20,20,3]\n<strong>Output:</strong> -1\n<strong>Explanation:</strong> There is no way to reach city 5 from city 0 within 25 minutes.\n</pre>\n\n<p> </p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>1 <= maxTime <= 1000</code></li>\n\t<li><code>n == passingFees.length</code></li>\n\t<li><code>2 <= n <= 1000</code></li>\n\t<li><code>n - 1 <= edges.length <= 1000</code></li>\n\t<li><code>0 <= x<sub>i</sub>, y<sub>i</sub> <= n - 1</code></li>\n\t<li><code>1 <= time<sub>i</sub> <= 1000</code></li>\n\t<li><code>1 <= passingFees[j] <= 1000</code> </li>\n\t<li>The graph may contain multiple edges between two nodes.</li>\n\t<li>The graph does not contain self loops.</li>\n</ul>\n",
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"translatedTitle": "规定时间内到达终点的最小花费",
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"translatedContent": "<p>一个国家有 <code>n</code> 个城市，城市编号为 <code>0</code> 到 <code>n - 1</code> ，题目保证 <strong>所有城市</strong> 都由双向道路 <b>连接在一起</b> 。道路由二维整数数组 <code>edges</code> 表示，其中 <code>edges[i] = [x<sub>i</sub>, y<sub>i</sub>, time<sub>i</sub>]</code> 表示城市 <code>x<sub>i</sub></code> 和 <code>y<sub>i</sub></code> 之间有一条双向道路，耗费时间为 <code>time<sub>i</sub></code> 分钟。两个城市之间可能会有多条耗费时间不同的道路，但是不会有道路两头连接着同一座城市。</p>\n\n<p>每次经过一个城市时，你需要付通行费。通行费用一个长度为 <code>n</code> 且下标从 <strong>0</strong> 开始的整数数组 <code>passingFees</code> 表示，其中 <code>passingFees[j]</code> 是你经过城市 <code>j</code> 需要支付的费用。</p>\n\n<p>一开始，你在城市 <code>0</code> ，你想要在 <code>maxTime</code> <strong>分钟以内</strong> （包含 <code>maxTime</code> 分钟）到达城市 <code>n - 1</code> 。旅行的 <strong>费用</strong> 为你经过的所有城市 <strong>通行费之和</strong> （<strong>包括</strong> 起点和终点城市的通行费）。</p>\n\n<p>给你 <code>maxTime</code>，<code>edges</code> 和 <code>passingFees</code> ，请你返回完成旅行的 <strong>最小费用</strong> ，如果无法在 <code>maxTime</code> 分钟以内完成旅行，请你返回 <code>-1</code> 。</p>\n\n<p> </p>\n\n<p><strong>示例 1：</strong></p>\n\n<p><img alt=\"\" src=\"https://assets.leetcode.com/uploads/2021/06/04/leetgraph1-1.png\" style=\"width: 371px; height: 171px;\" /></p>\n\n<pre>\n<b>输入：</b>maxTime = 30, edges = [[0,1,10],[1,2,10],[2,5,10],[0,3,1],[3,4,10],[4,5,15]], passingFees = [5,1,2,20,20,3]\n<b>输出：</b>11\n<b>解释：</b>最优路径为 0 -> 1 -> 2 -> 5 ，总共需要耗费 30 分钟，需要支付 11 的通行费。\n</pre>\n\n<p><strong>示例 2：</strong></p>\n\n<p><strong><img alt=\"\" src=\"https://assets.leetcode.com/uploads/2021/06/04/copy-of-leetgraph1-1.png\" style=\"width: 371px; height: 171px;\" /></strong></p>\n\n<pre>\n<b>输入：</b>maxTime = 29, edges = [[0,1,10],[1,2,10],[2,5,10],[0,3,1],[3,4,10],[4,5,15]], passingFees = [5,1,2,20,20,3]\n<b>输出：</b>48\n<b>解释：</b>最优路径为 0 -> 3 -> 4 -> 5 ，总共需要耗费 26 分钟，需要支付 48 的通行费。\n你不能选择路径 0 -> 1 -> 2 -> 5 ，因为这条路径耗费的时间太长。\n</pre>\n\n<p><strong>示例 3：</strong></p>\n\n<pre>\n<b>输入：</b>maxTime = 25, edges = [[0,1,10],[1,2,10],[2,5,10],[0,3,1],[3,4,10],[4,5,15]], passingFees = [5,1,2,20,20,3]\n<b>输出：</b>-1\n<b>解释：</b>无法在 25 分钟以内从城市 0 到达城市 5 。\n</pre>\n\n<p> </p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code>1 <= maxTime <= 1000</code></li>\n\t<li><code>n == passingFees.length</code></li>\n\t<li><code>2 <= n <= 1000</code></li>\n\t<li><code>n - 1 <= edges.length <= 1000</code></li>\n\t<li><code>0 <= x<sub>i</sub>, y<sub>i</sub> <= n - 1</code></li>\n\t<li><code>1 <= time<sub>i</sub> <= 1000</code></li>\n\t<li><code>1 <= passingFees[j] <= 1000</code> </li>\n\t<li>图中两个节点之间可能有多条路径。</li>\n\t<li>图中不含有自环。</li>\n</ul>\n",
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