leetcode-problemset/leetcode-cn/originData/minimum-cost-to-change-the-final-value-of-expression.json

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            "questionId": "2008",
            "questionFrontendId": "1896",
            "categoryTitle": "Algorithms",
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            "title": "Minimum Cost to Change the Final Value of Expression",
            "titleSlug": "minimum-cost-to-change-the-final-value-of-expression",
            "content": "<p>You are given a <strong>valid</strong> boolean expression as a string <code>expression</code> consisting of the characters <code>&#39;1&#39;</code>,<code>&#39;0&#39;</code>,<code>&#39;&amp;&#39;</code> (bitwise <strong>AND</strong> operator),<code>&#39;|&#39;</code> (bitwise <strong>OR</strong> operator),<code>&#39;(&#39;</code>, and <code>&#39;)&#39;</code>.</p>\n\n<ul>\n\t<li>For example, <code>&quot;()1|1&quot;</code> and <code>&quot;(1)&amp;()&quot;</code> are <strong>not valid</strong> while <code>&quot;1&quot;</code>, <code>&quot;(((1))|(0))&quot;</code>, and <code>&quot;1|(0&amp;(1))&quot;</code> are <strong>valid</strong> expressions.</li>\n</ul>\n\n<p>Return<em> the <strong>minimum cost</strong> to change the final value of the expression</em>.</p>\n\n<ul>\n\t<li>For example, if <code>expression = &quot;1|1|(0&amp;0)&amp;1&quot;</code>, its <strong>value</strong> is <code>1|1|(0&amp;0)&amp;1 = 1|1|0&amp;1 = 1|0&amp;1 = 1&amp;1 = 1</code>. We want to apply operations so that the<strong> new</strong> expression evaluates to <code>0</code>.</li>\n</ul>\n\n<p>The <strong>cost</strong> of changing the final value of an expression is the <strong>number of operations</strong> performed on the expression. The types of <strong>operations</strong> are described as follows:</p>\n\n<ul>\n\t<li>Turn a <code>&#39;1&#39;</code> into a <code>&#39;0&#39;</code>.</li>\n\t<li>Turn a <code>&#39;0&#39;</code> into a <code>&#39;1&#39;</code>.</li>\n\t<li>Turn a <code>&#39;&amp;&#39;</code> into a <code>&#39;|&#39;</code>.</li>\n\t<li>Turn a <code>&#39;|&#39;</code> into a <code>&#39;&amp;&#39;</code>.</li>\n</ul>\n\n<p><strong>Note:</strong> <code>&#39;&amp;&#39;</code> does <strong>not</strong> take precedence over <code>&#39;|&#39;</code> in the <strong>order of calculation</strong>. Evaluate parentheses <strong>first</strong>, then in <strong>left-to-right</strong> order.</p>\n\n<p>&nbsp;</p>\n<p><strong class=\"example\">Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> expression = &quot;1&amp;(0|1)&quot;\n<strong>Output:</strong> 1\n<strong>Explanation:</strong> We can turn &quot;1&amp;(0<u><strong>|</strong></u>1)&quot; into &quot;1&amp;(0<u><strong>&amp;</strong></u>1)&quot; by changing the &#39;|&#39; to a &#39;&amp;&#39; using 1 operation.\nThe new expression evaluates to 0. \n</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> expression = &quot;(0&amp;0)&amp;(0&amp;0&amp;0)&quot;\n<strong>Output:</strong> 3\n<strong>Explanation:</strong> We can turn &quot;(0<u><strong>&amp;0</strong></u>)<strong><u>&amp;</u></strong>(0&amp;0&amp;0)&quot; into &quot;(0<u><strong>|1</strong></u>)<u><strong>|</strong></u>(0&amp;0&amp;0)&quot; using 3 operations.\nThe new expression evaluates to 1.\n</pre>\n\n<p><strong class=\"example\">Example 3:</strong></p>\n\n<pre>\n<strong>Input:</strong> expression = &quot;(0|(1|0&amp;1))&quot;\n<strong>Output:</strong> 1\n<strong>Explanation:</strong> We can turn &quot;(0|(<u><strong>1</strong></u>|0&amp;1))&quot; into &quot;(0|(<u><strong>0</strong></u>|0&amp;1))&quot; using 1 operation.\nThe new expression evaluates to 0.</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= expression.length &lt;= 10<sup>5</sup></code></li>\n\t<li><code>expression</code>&nbsp;only contains&nbsp;<code>&#39;1&#39;</code>,<code>&#39;0&#39;</code>,<code>&#39;&amp;&#39;</code>,<code>&#39;|&#39;</code>,<code>&#39;(&#39;</code>, and&nbsp;<code>&#39;)&#39;</code></li>\n\t<li>All parentheses&nbsp;are properly matched.</li>\n\t<li>There will be no empty parentheses (i.e:&nbsp;<code>&quot;()&quot;</code>&nbsp;is not a substring of&nbsp;<code>expression</code>).</li>\n</ul>\n",
            "translatedTitle": "反转表达式值的最少操作次数",
            "translatedContent": "<p>给你一个 <strong>有效的</strong> 布尔表达式，用字符串 <code>expression</code> 表示。这个字符串包含字符 <code>'1'</code>，<code>'0'</code>，<code>'&amp;'</code>（按位 <strong>与</strong> 运算），<code>'|'</code>（按位 <strong>或</strong> 运算），<code>'('</code> 和 <code>')'</code> 。</p>\n\n<ul>\n\t<li>比方说，<code>\"()1|1\"</code> 和 <code>\"(1)&amp;()\"</code> <strong>不是有效</strong> 布尔表达式。而 <code>\"1\"</code>， <code>\"(((1))|(0))\"</code> 和 <code>\"1|(0&amp;(1))\"</code> 是 <strong>有效</strong> 布尔表达式。</li>\n</ul>\n\n<p>你的目标是将布尔表达式的 <strong>值</strong> <strong>反转 </strong>（也就是将 <code>0</code> 变为 <code>1</code> ，或者将 <code>1</code> 变为 <code>0</code>），请你返回达成目标需要的 <strong>最少操作</strong> 次数。</p>\n\n<ul>\n\t<li>比方说，如果表达式 <code>expression = \"1|1|(0&amp;0)&amp;1\"</code> ，它的 <strong>值</strong> 为 <code>1|1|(0&amp;0)&amp;1 = 1|1|0&amp;1 = 1|0&amp;1 = 1&amp;1 = 1</code> 。我们想要执行操作将 <strong>新的</strong> 表达式的值变成 <code>0</code> 。</li>\n</ul>\n\n<p>可执行的 <strong>操作</strong> 如下：</p>\n\n<ul>\n\t<li>将一个 <code>'1'</code> 变成一个 <code>'0'</code> 。</li>\n\t<li>将一个 <code>'0'</code> 变成一个 <code>'1'</code> 。</li>\n\t<li>将一个 <code>'&amp;'</code> 变成一个 <code>'|'</code> 。</li>\n\t<li>将一个 <code>'|'</code> 变成一个 <code>'&amp;'</code> 。</li>\n</ul>\n\n<p><strong>注意：</strong><code>'&amp;'</code> 的 <strong>运算优先级</strong> 与 <code>'|'</code> <strong>相同</strong> 。计算表达式时，括号优先级 <strong>最高</strong> ，然后按照 <strong>从左到右</strong> 的顺序运算。</p>\n\n<p> </p>\n\n<p><strong>示例 1：</strong></p>\n\n<pre><b>输入：</b>expression = \"1&amp;(0|1)\"\n<b>输出：</b>1\n<b>解释：</b>我们可以将 \"1&amp;(0<strong>|</strong>1)\" 变成 \"1&amp;(0<strong>&amp;</strong>1)\" ，执行的操作为将一个 '|' 变成一个 '&amp;' ，执行了 1 次操作。\n新表达式的值为 0 。\n</pre>\n\n<p><strong>示例 2：</strong></p>\n\n<pre><b>输入：</b>expression = \"(0&amp;0)&amp;(0&amp;0&amp;0)\"\n<b>输出：</b>3\n<b>解释：</b>我们可以将 \"(0<strong>&amp;0</strong>)<strong>&amp;</strong>(0&amp;0&amp;0)\" 变成 \"(0<strong>|1</strong>)<strong>|</strong>(0&amp;0&amp;0)\" ，执行了 3 次操作。\n新表达式的值为 1 。\n</pre>\n\n<p><strong>示例 3：</strong></p>\n\n<pre><b>输入：</b>expression = \"(0|(1|0&amp;1))\"\n<b>输出：</b>1\n<b>解释：</b>我们可以将 \"(0|(<strong>1</strong>|0&amp;1))\" 变成 \"(0|(<strong>0</strong>|0&amp;1))\" ，执行了 1 次操作。\n新表达式的值为 0 。</pre>\n\n<p> </p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= expression.length &lt;= 10<sup>5</sup></code></li>\n\t<li><code>expression</code> 只包含 <code>'1'</code>，<code>'0'</code>，<code>'&amp;'</code>，<code>'|'</code>，<code>'('</code> 和 <code>')'</code></li>\n\t<li>所有括号都有与之匹配的对应括号。</li>\n\t<li>不会有空的括号（也就是说 <code>\"()\"</code> 不是 <code>expression</code> 的子字符串）。</li>\n</ul>\n",
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href=\\\"https:\\/\\/github.com\\/emirpasic\\/gods\\/tree\\/v1.18.1\\\" target=\\\"_blank\\\">https:\\/\\/godoc.org\\/github.com\\/emirpasic\\/gods@v1.18.1<\\/a> \\u7b2c\\u4e09\\u65b9\\u5e93\\u3002<\\/p>\"],\"python3\":[\"Python3\",\"<p>\\u7248\\u672c\\uff1a<code>Python 3.10<\\/code><\\/p>\\r\\n\\r\\n<p>\\u4e3a\\u4e86\\u65b9\\u4fbf\\u8d77\\u89c1\\uff0c\\u5927\\u90e8\\u5206\\u5e38\\u7528\\u5e93\\u5df2\\u7ecf\\u88ab\\u81ea\\u52a8 \\u5bfc\\u5165\\uff0c\\u5982<a href=\\\"https:\\/\\/docs.python.org\\/3\\/library\\/array.html\\\" target=\\\"_blank\\\">array<\\/a>, <a href=\\\"https:\\/\\/docs.python.org\\/3\\/library\\/bisect.html\\\" target=\\\"_blank\\\">bisect<\\/a>, <a href=\\\"https:\\/\\/docs.python.org\\/3\\/library\\/collections.html\\\" target=\\\"_blank\\\">collections<\\/a>\\u3002 \\u5982\\u679c\\u60a8\\u9700\\u8981\\u4f7f\\u7528\\u5176\\u4ed6\\u5e93\\u51fd\\u6570\\uff0c\\u8bf7\\u81ea\\u884c\\u5bfc\\u5165\\u3002<\\/p>\\r\\n\\r\\n<p>\\u5982\\u9700\\u4f7f\\u7528 Map\\/TreeMap 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