leetcode-problemset/leetcode-cn/originData/maximum-sum-queries.json

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            "questionId": "2839",
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            "categoryTitle": "Algorithms",
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            "title": "Maximum Sum Queries",
            "titleSlug": "maximum-sum-queries",
            "content": "<p>You are given two <strong>0-indexed</strong> integer arrays <code>nums1</code> and <code>nums2</code>, each of length <code>n</code>, and a <strong>1-indexed 2D array</strong> <code>queries</code> where <code>queries[i] = [x<sub>i</sub>, y<sub>i</sub>]</code>.</p>\n\n<p>For the <code>i<sup>th</sup></code> query, find the <strong>maximum value</strong> of <code>nums1[j] + nums2[j]</code> among all indices <code>j</code> <code>(0 &lt;= j &lt; n)</code>, where <code>nums1[j] &gt;= x<sub>i</sub></code> and <code>nums2[j] &gt;= y<sub>i</sub></code>, or <strong>-1</strong> if there is no <code>j</code> satisfying the constraints.</p>\n\n<p>Return <em>an array </em><code>answer</code><em> where </em><code>answer[i]</code><em> is the answer to the </em><code>i<sup>th</sup></code><em> query.</em></p>\n\n<p>&nbsp;</p>\n<p><strong class=\"example\">Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> nums1 = [4,3,1,2], nums2 = [2,4,9,5], queries = [[4,1],[1,3],[2,5]]\n<strong>Output:</strong> [6,10,7]\n<strong>Explanation:</strong> \nFor the 1st query <code node=\"[object Object]\">x<sub>i</sub> = 4</code>&nbsp;and&nbsp;<code node=\"[object Object]\">y<sub>i</sub> = 1</code>, we can select index&nbsp;<code node=\"[object Object]\">j = 0</code>&nbsp;since&nbsp;<code node=\"[object Object]\">nums1[j] &gt;= 4</code>&nbsp;and&nbsp;<code node=\"[object Object]\">nums2[j] &gt;= 1</code>. The sum&nbsp;<code node=\"[object Object]\">nums1[j] + nums2[j]</code>&nbsp;is 6, and we can show that 6 is the maximum we can obtain.\n\nFor the 2nd query <code node=\"[object Object]\">x<sub>i</sub> = 1</code>&nbsp;and&nbsp;<code node=\"[object Object]\">y<sub>i</sub> = 3</code>, we can select index&nbsp;<code node=\"[object Object]\">j = 2</code>&nbsp;since&nbsp;<code node=\"[object Object]\">nums1[j] &gt;= 1</code>&nbsp;and&nbsp;<code node=\"[object Object]\">nums2[j] &gt;= 3</code>. The sum&nbsp;<code node=\"[object Object]\">nums1[j] + nums2[j]</code>&nbsp;is 10, and we can show that 10 is the maximum we can obtain. \n\nFor the 3rd query <code node=\"[object Object]\">x<sub>i</sub> = 2</code>&nbsp;and&nbsp;<code node=\"[object Object]\">y<sub>i</sub> = 5</code>, we can select index&nbsp;<code node=\"[object Object]\">j = 3</code>&nbsp;since&nbsp;<code node=\"[object Object]\">nums1[j] &gt;= 2</code>&nbsp;and&nbsp;<code node=\"[object Object]\">nums2[j] &gt;= 5</code>. The sum&nbsp;<code node=\"[object Object]\">nums1[j] + nums2[j]</code>&nbsp;is 7, and we can show that 7 is the maximum we can obtain.\n\nTherefore, we return&nbsp;<code node=\"[object Object]\">[6,10,7]</code>.\n</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> nums1 = [3,2,5], nums2 = [2,3,4], queries = [[4,4],[3,2],[1,1]]\n<strong>Output:</strong> [9,9,9]\n<strong>Explanation:</strong> For this example, we can use index&nbsp;<code node=\"[object Object]\">j = 2</code>&nbsp;for all the queries since it satisfies the constraints for each query.\n</pre>\n\n<p><strong class=\"example\">Example 3:</strong></p>\n\n<pre>\n<strong>Input:</strong> nums1 = [2,1], nums2 = [2,3], queries = [[3,3]]\n<strong>Output:</strong> [-1]\n<strong>Explanation:</strong> There is one query in this example with <code node=\"[object Object]\">x<sub>i</sub></code> = 3 and <code node=\"[object Object]\">y<sub>i</sub></code> = 3. For every index, j, either nums1[j] &lt; <code node=\"[object Object]\">x<sub>i</sub></code> or nums2[j] &lt; <code node=\"[object Object]\">y<sub>i</sub></code>. Hence, there is no solution. \n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>nums1.length == nums2.length</code>&nbsp;</li>\n\t<li><code>n ==&nbsp;nums1.length&nbsp;</code></li>\n\t<li><code>1 &lt;= n &lt;= 10<sup>5</sup></code></li>\n\t<li><code>1 &lt;= nums1[i], nums2[i] &lt;= 10<sup>9</sup>&nbsp;</code></li>\n\t<li><code>1 &lt;= queries.length &lt;= 10<sup>5</sup></code></li>\n\t<li><code>queries[i].length ==&nbsp;2</code></li>\n\t<li><code>x<sub>i</sub>&nbsp;== queries[i][1]</code></li>\n\t<li><code>y<sub>i</sub> == queries[i][2]</code></li>\n\t<li><code>1 &lt;= x<sub>i</sub>, y<sub>i</sub> &lt;= 10<sup>9</sup></code></li>\n</ul>\n",
            "translatedTitle": "最大和查询",
            "translatedContent": "<p>给你两个长度为 <code>n</code> 、下标从 <strong>0</strong> 开始的整数数组 <code>nums1</code> 和 <code>nums2</code> ，另给你一个下标从 <strong>1</strong> 开始的二维数组 <code>queries</code> ，其中 <code>queries[i] = [x<sub>i</sub>, y<sub>i</sub>]</code> 。</p>\n\n<p>对于第 <code>i</code> 个查询，在所有满足 <code>nums1[j] &gt;= x<sub>i</sub></code> 且 <code>nums2[j] &gt;= y<sub>i</sub></code> 的下标 <code>j</code> <code>(0 &lt;= j &lt; n)</code> 中，找出 <code>nums1[j] + nums2[j]</code> 的 <strong>最大值</strong> ，如果不存在满足条件的 <code>j</code> 则返回 <strong>-1</strong> 。</p>\n\n<p>返回数组<em> </em><code>answer</code><em> ，</em>其中<em> </em><code>answer[i]</code><em> </em>是第 <code>i</code> 个查询的答案。</p>\n\n<p>&nbsp;</p>\n\n<p><strong>示例 1：</strong></p>\n\n<pre><strong>输入：</strong>nums1 = [4,3,1,2], nums2 = [2,4,9,5], queries = [[4,1],[1,3],[2,5]]\n<strong>输出：</strong>[6,10,7]\n<strong>解释：</strong>\n对于第 1 个查询：<code>x<sub>i</sub> = 4</code>&nbsp;且&nbsp;<code>y<sub>i</sub> = 1</code> ，可以选择下标&nbsp;<code>j = 0</code>&nbsp;，此时 <code>nums1[j] &gt;= 4</code>&nbsp;且&nbsp;<code>nums2[j] &gt;= 1</code> 。<code>nums1[j] + nums2[j]</code>&nbsp;等于 6 ，可以证明 6 是可以获得的最大值。\n对于第 2 个查询：<code>x<sub>i</sub> = 1</code>&nbsp;且&nbsp;<code>y<sub>i</sub> = 3</code> ，可以选择下标&nbsp;<code>j = 2</code>&nbsp;，此时 <code>nums1[j] &gt;= 1</code>&nbsp;且&nbsp;<code>nums2[j] &gt;= 3</code> 。<code>nums1[j] + nums2[j]</code>&nbsp;等于 10 ，可以证明 10 是可以获得的最大值。\n对于第 3 个查询：<code>x<sub>i</sub> = 2</code>&nbsp;且&nbsp;<code>y<sub>i</sub> = 5</code> ，可以选择下标&nbsp;<code>j = 3</code>&nbsp;，此时 <code>nums1[j] &gt;= 2</code>&nbsp;且&nbsp;<code>nums2[j] &gt;= 5</code> 。<code>nums1[j] + nums2[j]</code>&nbsp;等于 7 ，可以证明 7 是可以获得的最大值。\n因此，我们返回&nbsp;<code>[6,10,7]</code> 。\n</pre>\n\n<p><strong>示例 2：</strong></p>\n\n<pre><strong>输入：</strong>nums1 = [3,2,5], nums2 = [2,3,4], queries = [[4,4],[3,2],[1,1]]\n<strong>输出：</strong>[9,9,9]\n<strong>解释：</strong>对于这个示例，我们可以选择下标&nbsp;<code>j = 2</code>&nbsp;，该下标可以满足每个查询的限制。\n</pre>\n\n<p><strong>示例 3：</strong></p>\n\n<pre><strong>输入：</strong>nums1 = [2,1], nums2 = [2,3], queries = [[3,3]]\n<strong>输出：</strong>[-1]\n<strong>解释：</strong>示例中的查询 <code>x<sub>i</sub></code> = 3 且 <code>y<sub>i</sub></code> = 3 。对于每个下标 j ，都只满足 nums1[j] &lt; <code>x<sub>i</sub></code> 或者 nums2[j] &lt; <code>y<sub>i</sub></code> 。因此，不存在答案。 \n</pre>\n\n<p>&nbsp;</p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code>nums1.length == nums2.length</code>&nbsp;</li>\n\t<li><code>n ==&nbsp;nums1.length&nbsp;</code></li>\n\t<li><code>1 &lt;= n &lt;= 10<sup>5</sup></code></li>\n\t<li><code>1 &lt;= nums1[i], nums2[i] &lt;= 10<sup>9</sup>&nbsp;</code></li>\n\t<li><code>1 &lt;= queries.length &lt;= 10<sup>5</sup></code></li>\n\t<li><code>queries[i].length ==&nbsp;2</code></li>\n\t<li><code>x<sub>i</sub>&nbsp;== queries[i][1]</code></li>\n\t<li><code>y<sub>i</sub> == queries[i][2]</code></li>\n\t<li><code>1 &lt;= x<sub>i</sub>, y<sub>i</sub> &lt;= 10<sup>9</sup></code></li>\n</ul>\n",
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