mirror of
https://gitee.com/coder-xiaomo/leetcode-problemset
synced 2025-01-25 17:50:26 +08:00
191 lines
27 KiB
JSON
191 lines
27 KiB
JSON
{
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"questionId": "1116",
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"questionFrontendId": "1161",
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"categoryTitle": "Algorithms",
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"boundTopicId": 4726,
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"title": "Maximum Level Sum of a Binary Tree",
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"titleSlug": "maximum-level-sum-of-a-binary-tree",
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"content": "<p>Given the <code>root</code> of a binary tree, the level of its root is <code>1</code>, the level of its children is <code>2</code>, and so on.</p>\n\n<p>Return the <strong>smallest</strong> level <code>x</code> such that the sum of all the values of nodes at level <code>x</code> is <strong>maximal</strong>.</p>\n\n<p> </p>\n<p><strong class=\"example\">Example 1:</strong></p>\n<img alt=\"\" src=\"https://assets.leetcode.com/uploads/2019/05/03/capture.JPG\" style=\"width: 200px; height: 175px;\" />\n<pre>\n<strong>Input:</strong> root = [1,7,0,7,-8,null,null]\n<strong>Output:</strong> 2\n<strong>Explanation: </strong>\nLevel 1 sum = 1.\nLevel 2 sum = 7 + 0 = 7.\nLevel 3 sum = 7 + -8 = -1.\nSo we return the level with the maximum sum which is level 2.\n</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> root = [989,null,10250,98693,-89388,null,null,null,-32127]\n<strong>Output:</strong> 2\n</pre>\n\n<p> </p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li>The number of nodes in the tree is in the range <code>[1, 10<sup>4</sup>]</code>.</li>\n\t<li><code>-10<sup>5</sup> <= Node.val <= 10<sup>5</sup></code></li>\n</ul>\n",
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"translatedTitle": "最大层内元素和",
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"translatedContent": "<p>给你一个二叉树的根节点 <code>root</code>。设根节点位于二叉树的第 <code>1</code> 层，而根节点的子节点位于第 <code>2</code> 层，依此类推。</p>\n\n<p>请返回层内元素之和 <strong>最大</strong> 的那几层（可能只有一层）的层号，并返回其中 <strong>最小</strong> 的那个。</p>\n\n<p> </p>\n\n<p><strong>示例 1：</strong></p>\n\n<p><strong><img alt=\"\" src=\"https://assets.leetcode-cn.com/aliyun-lc-upload/uploads/2019/08/17/capture.jpeg\" style=\"height: 175px; width: 200px;\" /></strong></p>\n\n<pre>\n<strong>输入：</strong>root = [1,7,0,7,-8,null,null]\n<strong>输出：</strong>2\n<strong>解释：</strong>\n第 1 层各元素之和为 1，\n第 2 层各元素之和为 7 + 0 = 7，\n第 3 层各元素之和为 7 + -8 = -1，\n所以我们返回第 2 层的层号，它的层内元素之和最大。\n</pre>\n\n<p><strong>示例 2：</strong></p>\n\n<pre>\n<strong>输入：</strong>root = [989,null,10250,98693,-89388,null,null,null,-32127]\n<strong>输出：</strong>2\n</pre>\n\n<p> </p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li>树中的节点数在<meta charset=\"UTF-8\" /> <code>[1, 10<sup>4</sup>]</code>范围内<meta charset=\"UTF-8\" /></li>\n\t<li><code>-10<sup>5</sup> <= Node.val <= 10<sup>5</sup></code></li>\n</ul>\n",
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"code": "/**\n * Definition for a binary tree node.\n * class TreeNode {\n * public $val = null;\n * public $left = null;\n * public $right = null;\n * function __construct($val = 0, $left = null, $right = null) {\n * $this->val = $val;\n * $this->left = $left;\n * $this->right = $right;\n * }\n * }\n */\nclass Solution {\n\n /**\n * @param TreeNode $root\n * @return Integer\n */\n function maxLevelSum($root) {\n\n }\n}",
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"code": "/**\n * Definition for a binary tree node.\n * public class TreeNode {\n * public var val: Int\n * public var left: TreeNode?\n * public var right: TreeNode?\n * public init() { self.val = 0; self.left = nil; self.right = nil; }\n * public init(_ val: Int) { self.val = val; self.left = nil; self.right = nil; }\n * public init(_ val: Int, _ left: TreeNode?, _ right: TreeNode?) {\n * self.val = val\n * self.left = left\n * self.right = right\n * }\n * }\n */\nclass Solution {\n func maxLevelSum(_ root: TreeNode?) -> Int {\n\n }\n}",
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"code": "/**\n * Example:\n * var ti = TreeNode(5)\n * var v = ti.`val`\n * Definition for a binary tree node.\n * class TreeNode(var `val`: Int) {\n * var left: TreeNode? = null\n * var right: TreeNode? = null\n * }\n */\nclass Solution {\n fun maxLevelSum(root: TreeNode?): Int {\n\n }\n}",
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"code": "# Definition for a binary tree node.\n# class TreeNode\n# attr_accessor :val, :left, :right\n# def initialize(val = 0, left = nil, right = nil)\n# @val = val\n# @left = left\n# @right = right\n# end\n# end\n# @param {TreeNode} root\n# @return {Integer}\ndef max_level_sum(root)\n\nend",
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"code": "/**\n * Definition for a binary tree node.\n * class TreeNode(_value: Int = 0, _left: TreeNode = null, _right: TreeNode = null) {\n * var value: Int = _value\n * var left: TreeNode = _left\n * var right: TreeNode = _right\n * }\n */\nobject Solution {\n def maxLevelSum(root: TreeNode): Int = {\n\n }\n}",
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"code": "// Definition for a binary tree node.\n// #[derive(Debug, PartialEq, Eq)]\n// pub struct TreeNode {\n// pub val: i32,\n// pub left: Option<Rc<RefCell<TreeNode>>>,\n// pub right: Option<Rc<RefCell<TreeNode>>>,\n// }\n//\n// impl TreeNode {\n// #[inline]\n// pub fn new(val: i32) -> Self {\n// TreeNode {\n// val,\n// left: None,\n// right: None\n// }\n// }\n// }\nuse std::rc::Rc;\nuse std::cell::RefCell;\nimpl Solution {\n pub fn max_level_sum(root: Option<Rc<RefCell<TreeNode>>>) -> i32 {\n\n }\n}",
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"code": "%% Definition for a binary tree node.\n%%\n%% -record(tree_node, {val = 0 :: integer(),\n%% left = null :: 'null' | #tree_node{},\n%% right = null :: 'null' | #tree_node{}}).\n\n-spec max_level_sum(Root :: #tree_node{} | null) -> integer().\nmax_level_sum(Root) ->\n .",
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"code": "# Definition for a binary tree node.\n#\n# defmodule TreeNode do\n# @type t :: %__MODULE__{\n# val: integer,\n# left: TreeNode.t() | nil,\n# right: TreeNode.t() | nil\n# }\n# defstruct val: 0, left: nil, right: nil\n# end\n\ndefmodule Solution do\n @spec max_level_sum(root :: TreeNode.t | nil) :: integer\n def max_level_sum(root) do\n \n end\nend",
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"Calculate the sum for each level then find the level with the maximum sum.",
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"How can you traverse the tree ?",
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"How can you sum up the values for every level ?",
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"Use DFS or BFS to traverse the tree keeping the level of each node, and sum up those values with a map or a frequency array."
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