mirror of
https://gitee.com/coder-xiaomo/leetcode-problemset
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183 lines
22 KiB
JSON
183 lines
22 KiB
JSON
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"title": "Maximal Score After Applying K Operations",
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"content": "<p>You are given a <strong>0-indexed</strong> integer array <code>nums</code> and an integer <code>k</code>. You have a <strong>starting score</strong> of <code>0</code>.</p>\n\n<p>In one <strong>operation</strong>:</p>\n\n<ol>\n\t<li>choose an index <code>i</code> such that <code>0 <= i < nums.length</code>,</li>\n\t<li>increase your <strong>score</strong> by <code>nums[i]</code>, and</li>\n\t<li>replace <code>nums[i]</code> with <code>ceil(nums[i] / 3)</code>.</li>\n</ol>\n\n<p>Return <em>the maximum possible <strong>score</strong> you can attain after applying <strong>exactly</strong></em> <code>k</code> <em>operations</em>.</p>\n\n<p>The ceiling function <code>ceil(val)</code> is the least integer greater than or equal to <code>val</code>.</p>\n\n<p> </p>\n<p><strong>Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> nums = [10,10,10,10,10], k = 5\n<strong>Output:</strong> 50\n<strong>Explanation:</strong> Apply the operation to each array element exactly once. The final score is 10 + 10 + 10 + 10 + 10 = 50.\n</pre>\n\n<p><strong>Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> nums = [1,10,3,3,3], k = 3\n<strong>Output:</strong> 17\n<strong>Explanation: </strong>You can do the following operations:\nOperation 1: Select i = 1, so nums becomes [1,<strong><u>4</u></strong>,3,3,3]. Your score increases by 10.\nOperation 2: Select i = 1, so nums becomes [1,<strong><u>2</u></strong>,3,3,3]. Your score increases by 4.\nOperation 3: Select i = 2, so nums becomes [1,1,<u><strong>1</strong></u>,3,3]. Your score increases by 3.\nThe final score is 10 + 4 + 3 = 17.\n</pre>\n\n<p> </p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>1 <= nums.length, k <= 10<sup>5</sup></code></li>\n\t<li><code>1 <= nums[i] <= 10<sup>9</sup></code></li>\n</ul>\n",
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"translatedTitle": "执行 K 次操作后的最大分数",
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"translatedContent": "<p>给你一个下标从 <strong>0</strong> 开始的整数数组 <code>nums</code> 和一个整数 <code>k</code> 。你的 <strong>起始分数</strong> 为 <code>0</code> 。</p>\n\n<p>在一步 <strong>操作</strong> 中:</p>\n\n<ol>\n\t<li>选出一个满足 <code>0 <= i < nums.length</code> 的下标 <code>i</code> ,</li>\n\t<li>将你的 <strong>分数</strong> 增加 <code>nums[i]</code> ,并且</li>\n\t<li>将 <code>nums[i]</code> 替换为 <code>ceil(nums[i] / 3)</code> 。</li>\n</ol>\n\n<p>返回在 <strong>恰好</strong> 执行 <code>k</code> 次操作后,你可能获得的最大分数。</p>\n\n<p>向上取整函数 <code>ceil(val)</code> 的结果是大于或等于 <code>val</code> 的最小整数。</p>\n\n<p> </p>\n\n<p><strong>示例 1:</strong></p>\n\n<pre>\n<strong>输入:</strong>nums = [10,10,10,10,10], k = 5\n<strong>输出:</strong>50\n<strong>解释:</strong>对数组中每个元素执行一次操作。最后分数是 10 + 10 + 10 + 10 + 10 = 50 。\n</pre>\n\n<p><strong>示例 2:</strong></p>\n\n<pre>\n<strong>输入:</strong>nums = [1,10,3,3,3], k = 3\n<strong>输出:</strong>17\n<strong>解释:</strong>可以执行下述操作:\n第 1 步操作:选中 i = 1 ,nums 变为 [1,<em><strong>4</strong></em>,3,3,3] 。分数增加 10 。\n第 2 步操作:选中 i = 1 ,nums 变为 [1,<em><strong>2</strong></em>,3,3,3] 。分数增加 4 。\n第 3 步操作:选中 i = 2 ,nums 变为 [1,2,<em><strong>1</strong></em>,3,3] 。分数增加 3 。\n最后分数是 10 + 4 + 3 = 17 。\n</pre>\n\n<p> </p>\n\n<p><strong>提示:</strong></p>\n\n<ul>\n\t<li><code>1 <= nums.length, k <= 10<sup>5</sup></code></li>\n\t<li><code>1 <= nums[i] <= 10<sup>9</sup></code></li>\n</ul>\n",
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