leetcode-problemset/leetcode-cn/originData/magical-string.json

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            "title": "Magical String",
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            "content": "<p>A magical string <code>s</code> consists of only <code>&#39;1&#39;</code> and <code>&#39;2&#39;</code> and obeys the following rules:</p>\n\n<ul>\n\t<li>The string s is magical because concatenating the number of contiguous occurrences of characters <code>&#39;1&#39;</code> and <code>&#39;2&#39;</code> generates the string <code>s</code> itself.</li>\n</ul>\n\n<p>The first few elements of <code>s</code> is <code>s = &quot;1221121221221121122&hellip;&hellip;&quot;</code>. If we group the consecutive <code>1</code>&#39;s and <code>2</code>&#39;s in <code>s</code>, it will be <code>&quot;1 22 11 2 1 22 1 22 11 2 11 22 ......&quot;</code> and the occurrences of <code>1</code>&#39;s or <code>2</code>&#39;s in each group are <code>&quot;1 2 2 1 1 2 1 2 2 1 2 2 ......&quot;</code>. You can see that the occurrence sequence is <code>s</code> itself.</p>\n\n<p>Given an integer <code>n</code>, return the number of <code>1</code>&#39;s in the first <code>n</code> number in the magical string <code>s</code>.</p>\n\n<p>&nbsp;</p>\n<p><strong class=\"example\">Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> n = 6\n<strong>Output:</strong> 3\n<strong>Explanation:</strong> The first 6 elements of magical string s is &quot;122112&quot; and it contains three 1&#39;s, so return 3.\n</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> n = 1\n<strong>Output:</strong> 1\n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= n &lt;= 10<sup>5</sup></code></li>\n</ul>\n",
            "translatedTitle": "神奇字符串",
            "translatedContent": "<p>神奇字符串 <code>s</code> 仅由 <code>'1'</code> 和 <code>'2'</code> 组成，并需要遵守下面的规则：</p>\n\n<ul>\n\t<li>神奇字符串 s 的神奇之处在于，串联字符串中 <code>'1'</code> 和 <code>'2'</code> 的连续出现次数可以生成该字符串。</li>\n</ul>\n\n<p><code>s</code> 的前几个元素是 <code>s = \"1221121221221121122……\"</code> 。如果将 <code>s</code> 中连续的若干 <code>1</code> 和 <code>2</code> 进行分组，可以得到 <code>\"1 22 11 2 1 22 1 22 11 2 11 22 ......\"</code> 。每组中 <code>1</code> 或者 <code>2</code> 的出现次数分别是 <code>\"1 2 2 1 1 2 1 2 2 1 2 2 ......\"</code> 。上面的出现次数正是 <code>s</code> 自身。</p>\n\n<p>给你一个整数 <code>n</code> ，返回在神奇字符串 <code>s</code> 的前 <code>n</code> 个数字中 <code>1</code> 的数目。</p>\n\n<p>&nbsp;</p>\n\n<p><strong>示例 1：</strong></p>\n\n<pre>\n<strong>输入：</strong>n = 6\n<strong>输出：</strong>3\n<strong>解释：</strong>神奇字符串 s 的前 6 个元素是 “<code>122112</code>”，它包含三个 1，因此返回 3 。 \n</pre>\n\n<p><strong>示例 2：</strong></p>\n\n<pre>\n<strong>输入：</strong>n = 1\n<strong>输出：</strong>1\n</pre>\n\n<p>&nbsp;</p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= n &lt;= 10<sup>5</sup></code></li>\n</ul>\n",
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