leetcode-problemset/leetcode-cn/originData/longest-chunked-palindrome-decomposition.json

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            "title": "Longest Chunked Palindrome Decomposition",
            "titleSlug": "longest-chunked-palindrome-decomposition",
            "content": "<p>You are given a string <code>text</code>. You should split it to k substrings <code>(subtext<sub>1</sub>, subtext<sub>2</sub>, ..., subtext<sub>k</sub>)</code> such that:</p>\n\n<ul>\n\t<li><code>subtext<sub>i</sub></code> is a <strong>non-empty</strong> string.</li>\n\t<li>The concatenation of all the substrings is equal to <code>text</code> (i.e., <code>subtext<sub>1</sub> + subtext<sub>2</sub> + ... + subtext<sub>k</sub> == text</code>).</li>\n\t<li><code>subtext<sub>i</sub> == subtext<sub>k - i + 1</sub></code> for all valid values of <code>i</code> (i.e., <code>1 &lt;= i &lt;= k</code>).</li>\n</ul>\n\n<p>Return the largest possible value of <code>k</code>.</p>\n\n<p>&nbsp;</p>\n<p><strong class=\"example\">Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> text = &quot;ghiabcdefhelloadamhelloabcdefghi&quot;\n<strong>Output:</strong> 7\n<strong>Explanation:</strong> We can split the string on &quot;(ghi)(abcdef)(hello)(adam)(hello)(abcdef)(ghi)&quot;.\n</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> text = &quot;merchant&quot;\n<strong>Output:</strong> 1\n<strong>Explanation:</strong> We can split the string on &quot;(merchant)&quot;.\n</pre>\n\n<p><strong class=\"example\">Example 3:</strong></p>\n\n<pre>\n<strong>Input:</strong> text = &quot;antaprezatepzapreanta&quot;\n<strong>Output:</strong> 11\n<strong>Explanation:</strong> We can split the string on &quot;(a)(nt)(a)(pre)(za)(tep)(za)(pre)(a)(nt)(a)&quot;.\n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= text.length &lt;= 1000</code></li>\n\t<li><code>text</code> consists only of lowercase English characters.</li>\n</ul>\n",
            "translatedTitle": "段式回文",
            "translatedContent": "<p>你会得到一个字符串&nbsp;<code>text</code>&nbsp;。你应该把它分成 <code>k</code>&nbsp;个子字符串&nbsp;<code>(subtext1, subtext2，…， subtextk)</code>&nbsp;，要求满足:</p>\n\n<ul>\n\t<li><code>subtext<sub>i</sub></code><sub>&nbsp;</sub>是 <strong>非空&nbsp;</strong>字符串</li>\n\t<li>所有子字符串的连接等于 <code>text</code> ( 即<code>subtext<sub>1</sub>&nbsp;+ subtext<sub>2</sub>&nbsp;+ ... + subtext<sub>k</sub>&nbsp;== text</code>&nbsp;)</li>\n\t<li>对于所有 <font color=\"#c7254e\"><font face=\"Menlo, Monaco, Consolas, Courier New, monospace\"><span style=\"font-size:12.6px\"><span style=\"background-color:#f9f2f4\">i</span></span></font></font>&nbsp;的有效值( 即&nbsp;<code>1 &lt;= i&nbsp;&lt;= k</code> ) ，<code>subtext<sub>i</sub>&nbsp;== subtext<sub>k - i + 1</sub></code> 均成立</li>\n</ul>\n\n<p>返回<code>k</code>可能最大值。</p>\n\n<p>&nbsp;</p>\n\n<p><strong>示例 1：</strong></p>\n\n<pre>\n<strong>输入：</strong>text = \"ghiabcdefhelloadamhelloabcdefghi\"\n<strong>输出：</strong>7\n<strong>解释：</strong>我们可以把字符串拆分成 \"(ghi)(abcdef)(hello)(adam)(hello)(abcdef)(ghi)\"。\n</pre>\n\n<p><strong>示例 2：</strong></p>\n\n<pre>\n<strong>输入：</strong>text = \"merchant\"\n<strong>输出：</strong>1\n<strong>解释：</strong>我们可以把字符串拆分成 \"(merchant)\"。\n</pre>\n\n<p><strong>示例 3：</strong></p>\n\n<pre>\n<strong>输入：</strong>text = \"antaprezatepzapreanta\"\n<strong>输出：</strong>11\n<strong>解释：</strong>我们可以把字符串拆分成 \"(a)(nt)(a)(pre)(za)(tep)(za)(pre)(a)(nt)(a)\"。\n</pre>\n\n<p>&nbsp;</p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= text.length &lt;= 1000</code></li>\n\t<li><code>text</code>&nbsp;仅由小写英文字符组成</li>\n</ul>\n",
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