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leetcode-problemset/leetcode-cn/originData/longer-contiguous-segments-of-ones-than-zeros.json
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"question": {
"questionId": "1999",
"questionFrontendId": "1869",
"categoryTitle": "Algorithms",
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"title": "Longer Contiguous Segments of Ones than Zeros",
"titleSlug": "longer-contiguous-segments-of-ones-than-zeros",
"content": "<p>Given a binary string <code>s</code>, return <code>true</code><em> if the <strong>longest</strong> contiguous segment of </em><code>1</code>&#39;<em>s is <strong>strictly longer</strong> than the <strong>longest</strong> contiguous segment of </em><code>0</code>&#39;<em>s in </em><code>s</code>, or return <code>false</code><em> otherwise</em>.</p>\n\n<ul>\n\t<li>For example, in <code>s = &quot;<u>11</u>01<u>000</u>10&quot;</code> the longest continuous segment of <code>1</code>s has length <code>2</code>, and the longest continuous segment of <code>0</code>s has length <code>3</code>.</li>\n</ul>\n\n<p>Note that if there are no <code>0</code>&#39;s, then the longest continuous segment of <code>0</code>&#39;s is considered to have a length <code>0</code>. The same applies if there is no <code>1</code>&#39;s.</p>\n\n<p>&nbsp;</p>\n<p><strong class=\"example\">Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> s = &quot;1101&quot;\n<strong>Output:</strong> true\n<strong>Explanation:</strong>\nThe longest contiguous segment of 1s has length 2: &quot;<u>11</u>01&quot;\nThe longest contiguous segment of 0s has length 1: &quot;11<u>0</u>1&quot;\nThe segment of 1s is longer, so return true.\n</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> s = &quot;111000&quot;\n<strong>Output:</strong> false\n<strong>Explanation:</strong>\nThe longest contiguous segment of 1s has length 3: &quot;<u>111</u>000&quot;\nThe longest contiguous segment of 0s has length 3: &quot;111<u>000</u>&quot;\nThe segment of 1s is not longer, so return false.\n</pre>\n\n<p><strong class=\"example\">Example 3:</strong></p>\n\n<pre>\n<strong>Input:</strong> s = &quot;110100010&quot;\n<strong>Output:</strong> false\n<strong>Explanation:</strong>\nThe longest contiguous segment of 1s has length 2: &quot;<u>11</u>0100010&quot;\nThe longest contiguous segment of 0s has length 3: &quot;1101<u>000</u>10&quot;\nThe segment of 1s is not longer, so return false.\n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= s.length &lt;= 100</code></li>\n\t<li><code>s[i]</code> is either <code>&#39;0&#39;</code> or <code>&#39;1&#39;</code>.</li>\n</ul>\n",
"translatedTitle": "哪种连续子字符串更长",
"translatedContent": "<p>给你一个二进制字符串 <code>s</code> 。如果字符串中由 <code>1</code> 组成的 <strong>最长</strong> 连续子字符串 <strong>严格长于</strong> 由 <code>0</code> 组成的 <strong>最长</strong> 连续子字符串,返回 <code>true</code> ;否则,返回 <code>false</code><em> </em>。</p>\n\n<ul>\n\t<li>例如,<code>s = \"<strong>11</strong>01<strong>000</strong>10\"</code> 中,由 <code>1</code> 组成的最长连续子字符串的长度是 <code>2</code> ,由 <code>0</code> 组成的最长连续子字符串的长度是 <code>3</code> 。</li>\n</ul>\n\n<p>注意,如果字符串中不存在 <code>0</code> ,此时认为由 <code>0</code> 组成的最长连续子字符串的长度是 <code>0</code> 。字符串中不存在 <code>1</code> 的情况也适用此规则。</p>\n\n<p> </p>\n\n<p><strong>示例 1</strong></p>\n\n<pre>\n<strong>输入:</strong>s = \"1101\"\n<strong>输出:</strong>true\n<strong>解释:</strong>\n由 <code>1</code> 组成的最长连续子字符串的长度是 2\"<strong>11</strong>01\"\n由 <code>0</code> 组成的最长连续子字符串的长度是 1\"11<strong>0</strong>1\"\n由 1 组成的子字符串更长,故返回 true 。\n</pre>\n\n<p><strong>示例 2</strong></p>\n\n<pre>\n<strong>输入:</strong>s = \"111000\"\n<strong>输出:</strong>false\n<strong>解释:</strong>\n由 <code>1</code> 组成的最长连续子字符串的长度是 3\"<strong>111</strong>000\"\n由<code> 0</code> 组成的最长连续子字符串的长度是 3\"111<strong>000</strong>\"\n由 1 组成的子字符串不比由 0 组成的子字符串长,故返回 false 。\n</pre>\n\n<p><strong>示例 3</strong></p>\n\n<pre>\n<strong>输入:</strong>s = \"110100010\"\n<strong>输出:</strong>false\n<strong>解释:</strong>\n由 <code>1</code> 组成的最长连续子字符串的长度是 2\"<strong>11</strong>0100010\"\n由 <code>0</code> 组成的最长连续子字符串的长度是 3\"1101<strong>000</strong>10\"\n由 1 组成的子字符串不比由 0 组成的子字符串长,故返回 false 。\n</pre>\n\n<p> </p>\n\n<p><strong>提示:</strong></p>\n\n<ul>\n\t<li><code>1 <= s.length <= 100</code></li>\n\t<li><code>s[i]</code> 不是 <code>'0'</code> 就是 <code>'1'</code></li>\n</ul>\n",
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"Is there a way to iterate through the string to keep track of the current character and its count?"
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