leetcode-problemset/leetcode-cn/originData/lexicographically-smallest-equivalent-string.json

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        "question": {
            "questionId": "1058",
            "questionFrontendId": "1061",
            "categoryTitle": "Algorithms",
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            "title": "Lexicographically Smallest Equivalent String",
            "titleSlug": "lexicographically-smallest-equivalent-string",
            "content": "<p>You are given two strings of the same length <code>s1</code> and <code>s2</code> and a string <code>baseStr</code>.</p>\n\n<p>We say <code>s1[i]</code> and <code>s2[i]</code> are equivalent characters.</p>\n\n<ul>\n\t<li>For example, if <code>s1 = &quot;abc&quot;</code> and <code>s2 = &quot;cde&quot;</code>, then we have <code>&#39;a&#39; == &#39;c&#39;</code>, <code>&#39;b&#39; == &#39;d&#39;</code>, and <code>&#39;c&#39; == &#39;e&#39;</code>.</li>\n</ul>\n\n<p>Equivalent characters follow the usual rules of any equivalence relation:</p>\n\n<ul>\n\t<li><strong>Reflexivity:</strong> <code>&#39;a&#39; == &#39;a&#39;</code>.</li>\n\t<li><strong>Symmetry:</strong> <code>&#39;a&#39; == &#39;b&#39;</code> implies <code>&#39;b&#39; == &#39;a&#39;</code>.</li>\n\t<li><strong>Transitivity:</strong> <code>&#39;a&#39; == &#39;b&#39;</code> and <code>&#39;b&#39; == &#39;c&#39;</code> implies <code>&#39;a&#39; == &#39;c&#39;</code>.</li>\n</ul>\n\n<p>For example, given the equivalency information from <code>s1 = &quot;abc&quot;</code> and <code>s2 = &quot;cde&quot;</code>, <code>&quot;acd&quot;</code> and <code>&quot;aab&quot;</code> are equivalent strings of <code>baseStr = &quot;eed&quot;</code>, and <code>&quot;aab&quot;</code> is the lexicographically smallest equivalent string of <code>baseStr</code>.</p>\n\n<p>Return <em>the lexicographically smallest equivalent string of </em><code>baseStr</code><em> by using the equivalency information from </em><code>s1</code><em> and </em><code>s2</code>.</p>\n\n<p>&nbsp;</p>\n<p><strong class=\"example\">Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> s1 = &quot;parker&quot;, s2 = &quot;morris&quot;, baseStr = &quot;parser&quot;\n<strong>Output:</strong> &quot;makkek&quot;\n<strong>Explanation:</strong> Based on the equivalency information in s1 and s2, we can group their characters as [m,p], [a,o], [k,r,s], [e,i].\nThe characters in each group are equivalent and sorted in lexicographical order.\nSo the answer is &quot;makkek&quot;.\n</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> s1 = &quot;hello&quot;, s2 = &quot;world&quot;, baseStr = &quot;hold&quot;\n<strong>Output:</strong> &quot;hdld&quot;\n<strong>Explanation: </strong>Based on the equivalency information in s1 and s2, we can group their characters as [h,w], [d,e,o], [l,r].\nSo only the second letter &#39;o&#39; in baseStr is changed to &#39;d&#39;, the answer is &quot;hdld&quot;.\n</pre>\n\n<p><strong class=\"example\">Example 3:</strong></p>\n\n<pre>\n<strong>Input:</strong> s1 = &quot;leetcode&quot;, s2 = &quot;programs&quot;, baseStr = &quot;sourcecode&quot;\n<strong>Output:</strong> &quot;aauaaaaada&quot;\n<strong>Explanation:</strong> We group the equivalent characters in s1 and s2 as [a,o,e,r,s,c], [l,p], [g,t] and [d,m], thus all letters in baseStr except &#39;u&#39; and &#39;d&#39; are transformed to &#39;a&#39;, the answer is &quot;aauaaaaada&quot;.\n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= s1.length, s2.length, baseStr &lt;= 1000</code></li>\n\t<li><code>s1.length == s2.length</code></li>\n\t<li><code>s1</code>, <code>s2</code>, and <code>baseStr</code> consist of lowercase English letters.</li>\n</ul>\n",
            "translatedTitle": "按字典序排列最小的等效字符串",
            "translatedContent": "<p>给出长度相同的两个字符串<code>s1</code> 和&nbsp;<code>s2</code>&nbsp;，还有一个字符串&nbsp;<code>baseStr</code>&nbsp;。</p>\n\n<p>其中 &nbsp;<code>s1[i]</code>&nbsp;和&nbsp;<code>s2[i]</code>&nbsp; 是一组等价字符。</p>\n\n<ul>\n\t<li>举个例子，如果&nbsp;<code>s1 = \"abc\"</code> 且&nbsp;<code>s2 = \"cde\"</code>，那么就有&nbsp;<code>'a' == 'c', 'b' == 'd', 'c' == 'e'</code>。</li>\n</ul>\n\n<p>等价字符遵循任何等价关系的一般规则：</p>\n\n<ul>\n\t<li><strong>&nbsp;自反性&nbsp;</strong>：<code>'a' == 'a'</code></li>\n\t<li>&nbsp;<strong>对称性&nbsp;</strong>：<code>'a' == 'b'</code> 则必定有 <code>'b' == 'a'</code></li>\n\t<li>&nbsp;<strong>传递性</strong> ：<code>'a' == 'b'</code> 且 <code>'b' == 'c'</code> 就表明 <code>'a' == 'c'</code></li>\n</ul>\n\n<p>例如，&nbsp;<code>s1 = \"abc\"</code>&nbsp;和&nbsp;<code>s2 = \"cde\"</code>&nbsp;的等价信息和之前的例子一样，那么&nbsp;<code>baseStr = \"eed\"</code>&nbsp;, <code>\"acd\"</code>&nbsp;或&nbsp;<code>\"aab\"</code>，这三个字符串都是等价的，而&nbsp;<code>\"aab\"</code>&nbsp;是&nbsp;<code>baseStr</code>&nbsp;的按字典序最小的等价字符串</p>\n\n<p>利用<em>&nbsp;</em><code>s1</code>&nbsp;和&nbsp;<code>s2</code>&nbsp;的等价信息，找出并返回<em>&nbsp;</em><code>baseStr</code><em>&nbsp;</em>的按字典序排列最小的等价字符串。</p>\n\n<p>&nbsp;</p>\n\n<p><strong>示例 1：</strong></p>\n\n<pre>\n<strong>输入：</strong>s1 = \"parker\", s2 = \"morris\", baseStr = \"parser\"\n<strong>输出：</strong>\"makkek\"\n<strong>解释：</strong>根据 <code>A</code> 和 <code>B 中的等价信息，</code>我们可以将这些字符分为 <code>[m,p]</code>, <code>[a,o]</code>, <code>[k,r,s]</code>, <code>[e,i] 共 4 组</code>。每组中的字符都是等价的，并按字典序排列。所以答案是 <code>\"makkek\"</code>。\n</pre>\n\n<p><strong>示例 2：</strong></p>\n\n<pre>\n<strong>输入：</strong>s1 = \"hello\", s2 = \"world\", baseStr = \"hold\"\n<strong>输出：</strong>\"hdld\"\n<strong>解释：</strong>根据 <code>A</code> 和 <code>B 中的等价信息，</code>我们可以将这些字符分为 <code>[h,w]</code>, <code>[d,e,o]</code>, <code>[l,r] 共 3 组</code>。所以只有 S 中的第二个字符 <code>'o'</code> 变成 <code>'d'，最后答案为 </code><code>\"hdld\"</code>。\n</pre>\n\n<p><strong>示例 3：</strong></p>\n\n<pre>\n<strong>输入：</strong>s1 = \"leetcode\", s2 = \"programs\", baseStr = \"sourcecode\"\n<strong>输出：</strong>\"aauaaaaada\"\n<strong>解释：</strong>我们可以把 A 和 B 中的等价字符分为 <code>[a,o,e,r,s,c]</code>, <code>[l,p]</code>, <code>[g,t]</code> 和 <code>[d,m] 共 4 组</code>，因此 <code>S</code> 中除了 <code>'u'</code> 和 <code>'d'</code> 之外的所有字母都转化成了 <code>'a'</code>，最后答案为 <code>\"aauaaaaada\"</code>。\n</pre>\n\n<p>&nbsp;</p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= s1.length, s2.length, baseStr &lt;= 1000</code></li>\n\t<li><code>s1.length == s2.length</code></li>\n\t<li>字符串<code>s1</code>,&nbsp;<code>s2</code>, and&nbsp;<code>baseStr</code>&nbsp;仅由从&nbsp;<code>'a'</code> 到&nbsp;<code>'z'</code>&nbsp;的小写英文字母组成。</li>\n</ul>\n",
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href=\\\"https:\\/\\/github.com\\/emirpasic\\/gods\\/tree\\/v1.18.1\\\" target=\\\"_blank\\\">https:\\/\\/godoc.org\\/github.com\\/emirpasic\\/gods@v1.18.1<\\/a> \\u7b2c\\u4e09\\u65b9\\u5e93\\u3002<\\/p>\"],\"python3\":[\"Python3\",\"<p>\\u7248\\u672c\\uff1a<code>Python 3.10<\\/code><\\/p>\\r\\n\\r\\n<p>\\u4e3a\\u4e86\\u65b9\\u4fbf\\u8d77\\u89c1\\uff0c\\u5927\\u90e8\\u5206\\u5e38\\u7528\\u5e93\\u5df2\\u7ecf\\u88ab\\u81ea\\u52a8 \\u5bfc\\u5165\\uff0c\\u5982<a href=\\\"https:\\/\\/docs.python.org\\/3\\/library\\/array.html\\\" target=\\\"_blank\\\">array<\\/a>, <a href=\\\"https:\\/\\/docs.python.org\\/3\\/library\\/bisect.html\\\" target=\\\"_blank\\\">bisect<\\/a>, <a href=\\\"https:\\/\\/docs.python.org\\/3\\/library\\/collections.html\\\" target=\\\"_blank\\\">collections<\\/a>\\u3002 \\u5982\\u679c\\u60a8\\u9700\\u8981\\u4f7f\\u7528\\u5176\\u4ed6\\u5e93\\u51fd\\u6570\\uff0c\\u8bf7\\u81ea\\u884c\\u5bfc\\u5165\\u3002<\\/p>\\r\\n\\r\\n<p>\\u5982\\u9700\\u4f7f\\u7528 Map\\/TreeMap 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