mirror of
https://gitee.com/coder-xiaomo/leetcode-problemset
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189 lines
28 KiB
JSON
189 lines
28 KiB
JSON
{
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"questionId": "2646",
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"questionFrontendId": "2583",
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"categoryTitle": "Algorithms",
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"boundTopicId": 2143004,
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"title": "Kth Largest Sum in a Binary Tree",
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"titleSlug": "kth-largest-sum-in-a-binary-tree",
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"content": "<p>You are given the <code>root</code> of a binary tree and a positive integer <code>k</code>.</p>\n\n<p>The <strong>level sum</strong> in the tree is the sum of the values of the nodes that are on the <strong>same</strong> level.</p>\n\n<p>Return<em> the </em><code>k<sup>th</sup></code><em> <strong>largest</strong> level sum in the tree (not necessarily distinct)</em>. If there are fewer than <code>k</code> levels in the tree, return <code>-1</code>.</p>\n\n<p><strong>Note</strong> that two nodes are on the same level if they have the same distance from the root.</p>\n\n<p> </p>\n<p><strong class=\"example\">Example 1:</strong></p>\n<img alt=\"\" src=\"https://assets.leetcode.com/uploads/2022/12/14/binaryytreeedrawio-2.png\" style=\"width: 301px; height: 284px;\" />\n<pre>\n<strong>Input:</strong> root = [5,8,9,2,1,3,7,4,6], k = 2\n<strong>Output:</strong> 13\n<strong>Explanation:</strong> The level sums are the following:\n- Level 1: 5.\n- Level 2: 8 + 9 = 17.\n- Level 3: 2 + 1 + 3 + 7 = 13.\n- Level 4: 4 + 6 = 10.\nThe 2<sup>nd</sup> largest level sum is 13.\n</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n<img alt=\"\" src=\"https://assets.leetcode.com/uploads/2022/12/14/treedrawio-3.png\" style=\"width: 181px; height: 181px;\" />\n<pre>\n<strong>Input:</strong> root = [1,2,null,3], k = 1\n<strong>Output:</strong> 3\n<strong>Explanation:</strong> The largest level sum is 3.\n</pre>\n\n<p> </p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li>The number of nodes in the tree is <code>n</code>.</li>\n\t<li><code>2 <= n <= 10<sup>5</sup></code></li>\n\t<li><code>1 <= Node.val <= 10<sup>6</sup></code></li>\n\t<li><code>1 <= k <= n</code></li>\n</ul>\n",
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"translatedTitle": "二叉树中的第 K 大层和",
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"translatedContent": "<p>给你一棵二叉树的根节点 <code>root</code> 和一个正整数 <code>k</code> 。</p>\n\n<p>树中的 <strong>层和</strong> 是指 <strong>同一层</strong> 上节点值的总和。</p>\n\n<p>返回树中第 <code>k</code> 大的层和（不一定不同）。如果树少于 <code>k</code> 层，则返回 <code>-1</code> 。</p>\n\n<p><strong>注意</strong>，如果两个节点与根节点的距离相同，则认为它们在同一层。</p>\n\n<p> </p>\n\n<p><strong>示例 1：</strong></p>\n\n<p><img alt=\"\" src=\"https://assets.leetcode.com/uploads/2022/12/14/binaryytreeedrawio-2.png\" style=\"width: 301px; height: 284px;\" /></p>\n\n<pre>\n<strong>输入：</strong>root = [5,8,9,2,1,3,7,4,6], k = 2\n<strong>输出：</strong>13\n<strong>解释：</strong>树中每一层的层和分别是：\n- Level 1: 5\n- Level 2: 8 + 9 = 17\n- Level 3: 2 + 1 + 3 + 7 = 13\n- Level 4: 4 + 6 = 10\n第 2 大的层和等于 13 。\n</pre>\n\n<p><strong>示例 2：</strong></p>\n\n<p><img alt=\"\" src=\"https://assets.leetcode.com/uploads/2022/12/14/treedrawio-3.png\" style=\"width: 181px; height: 181px;\" /></p>\n\n<pre>\n<strong>输入：</strong>root = [1,2,null,3], k = 1\n<strong>输出：</strong>3\n<strong>解释：</strong>最大的层和是 3 。\n</pre>\n\n<p> </p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li>树中的节点数为 <code>n</code></li>\n\t<li><code>2 <= n <= 10<sup>5</sup></code></li>\n\t<li><code>1 <= Node.val <= 10<sup>6</sup></code></li>\n\t<li><code>1 <= k <= n</code></li>\n</ul>\n",
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"code": "/**\n * Definition for a binary tree node.\n * struct TreeNode {\n * int val;\n * TreeNode *left;\n * TreeNode *right;\n * TreeNode() : val(0), left(nullptr), right(nullptr) {}\n * TreeNode(int x) : val(x), left(nullptr), right(nullptr) {}\n * TreeNode(int x, TreeNode *left, TreeNode *right) : val(x), left(left), right(right) {}\n * };\n */\nclass Solution {\npublic:\n long long kthLargestLevelSum(TreeNode* root, int k) {\n \n }\n};",
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"code": "# Definition for a binary tree node.\n# class TreeNode(object):\n# def __init__(self, val=0, left=None, right=None):\n# self.val = val\n# self.left = left\n# self.right = right\nclass Solution(object):\n def kthLargestLevelSum(self, root, k):\n \"\"\"\n :type root: Optional[TreeNode]\n :type k: int\n :rtype: int\n \"\"\"",
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"code": "/**\n * Definition for a binary tree node.\n * public class TreeNode {\n * public int val;\n * public TreeNode left;\n * public TreeNode right;\n * public TreeNode(int val=0, TreeNode left=null, TreeNode right=null) {\n * this.val = val;\n * this.left = left;\n * this.right = right;\n * }\n * }\n */\npublic class Solution {\n public long KthLargestLevelSum(TreeNode root, int k) {\n\n }\n}",
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"code": "/**\n * Definition for a binary tree node.\n * function TreeNode(val, left, right) {\n * this.val = (val===undefined ? 0 : val)\n * this.left = (left===undefined ? null : left)\n * this.right = (right===undefined ? null : right)\n * }\n */\n/**\n * @param {TreeNode} root\n * @param {number} k\n * @return {number}\n */\nvar kthLargestLevelSum = function(root, k) {\n\n};",
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"code": "/**\n * Definition for a binary tree node.\n * class TreeNode {\n * val: number\n * left: TreeNode | null\n * right: TreeNode | null\n * constructor(val?: number, left?: TreeNode | null, right?: TreeNode | null) {\n * this.val = (val===undefined ? 0 : val)\n * this.left = (left===undefined ? null : left)\n * this.right = (right===undefined ? null : right)\n * }\n * }\n */\n\nfunction kthLargestLevelSum(root: TreeNode | null, k: number): number {\n \n};",
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"code": "/**\n * Definition for a binary tree node.\n * class TreeNode {\n * public $val = null;\n * public $left = null;\n * public $right = null;\n * function __construct($val = 0, $left = null, $right = null) {\n * $this->val = $val;\n * $this->left = $left;\n * $this->right = $right;\n * }\n * }\n */\nclass Solution {\n\n /**\n * @param TreeNode $root\n * @param Integer $k\n * @return Integer\n */\n function kthLargestLevelSum($root, $k) {\n\n }\n}",
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"code": "/**\n * Definition for a binary tree node.\n * public class TreeNode {\n * public var val: Int\n * public var left: TreeNode?\n * public var right: TreeNode?\n * public init() { self.val = 0; self.left = nil; self.right = nil; }\n * public init(_ val: Int) { self.val = val; self.left = nil; self.right = nil; }\n * public init(_ val: Int, _ left: TreeNode?, _ right: TreeNode?) {\n * self.val = val\n * self.left = left\n * self.right = right\n * }\n * }\n */\nclass Solution {\n func kthLargestLevelSum(_ root: TreeNode?, _ k: Int) -> Int {\n\n }\n}",
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"code": "/**\n * Example:\n * var ti = TreeNode(5)\n * var v = ti.`val`\n * Definition for a binary tree node.\n * class TreeNode(var `val`: Int) {\n * var left: TreeNode? = null\n * var right: TreeNode? = null\n * }\n */\nclass Solution {\n fun kthLargestLevelSum(root: TreeNode?, k: Int): Long {\n\n }\n}",
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"code": "/**\n * Definition for a binary tree node.\n * class TreeNode {\n * int val;\n * TreeNode? left;\n * TreeNode? right;\n * TreeNode([this.val = 0, this.left, this.right]);\n * }\n */\nclass Solution {\n int kthLargestLevelSum(TreeNode? root, int k) {\n \n }\n}",
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"code": "/**\n * Definition for a binary tree node.\n * type TreeNode struct {\n * Val int\n * Left *TreeNode\n * Right *TreeNode\n * }\n */\nfunc kthLargestLevelSum(root *TreeNode, k int) int64 {\n\n}",
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"code": "# Definition for a binary tree node.\n# class TreeNode\n# attr_accessor :val, :left, :right\n# def initialize(val = 0, left = nil, right = nil)\n# @val = val\n# @left = left\n# @right = right\n# end\n# end\n# @param {TreeNode} root\n# @param {Integer} k\n# @return {Integer}\ndef kth_largest_level_sum(root, k)\n\nend",
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"code": "/**\n * Definition for a binary tree node.\n * class TreeNode(_value: Int = 0, _left: TreeNode = null, _right: TreeNode = null) {\n * var value: Int = _value\n * var left: TreeNode = _left\n * var right: TreeNode = _right\n * }\n */\nobject Solution {\n def kthLargestLevelSum(root: TreeNode, k: Int): Long = {\n\n }\n}",
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"code": "// Definition for a binary tree node.\n// #[derive(Debug, PartialEq, Eq)]\n// pub struct TreeNode {\n// pub val: i32,\n// pub left: Option<Rc<RefCell<TreeNode>>>,\n// pub right: Option<Rc<RefCell<TreeNode>>>,\n// }\n//\n// impl TreeNode {\n// #[inline]\n// pub fn new(val: i32) -> Self {\n// TreeNode {\n// val,\n// left: None,\n// right: None\n// }\n// }\n// }\nuse std::rc::Rc;\nuse std::cell::RefCell;\nimpl Solution {\n pub fn kth_largest_level_sum(root: Option<Rc<RefCell<TreeNode>>>, k: i32) -> i64 {\n\n }\n}",
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"code": "%% Definition for a binary tree node.\n%%\n%% -record(tree_node, {val = 0 :: integer(),\n%% left = null :: 'null' | #tree_node{},\n%% right = null :: 'null' | #tree_node{}}).\n\n-spec kth_largest_level_sum(Root :: #tree_node{} | null, K :: integer()) -> integer().\nkth_largest_level_sum(Root, K) ->\n .",
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"code": "# Definition for a binary tree node.\n#\n# defmodule TreeNode do\n# @type t :: %__MODULE__{\n# val: integer,\n# left: TreeNode.t() | nil,\n# right: TreeNode.t() | nil\n# }\n# defstruct val: 0, left: nil, right: nil\n# end\n\ndefmodule Solution do\n @spec kth_largest_level_sum(root :: TreeNode.t | nil, k :: integer) :: integer\n def kth_largest_level_sum(root, k) do\n \n end\nend",
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"Find the sum of values of nodes on each level and return the kth largest one.",
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"To find the sum of the values of nodes on each level, you can use a DFS or BFS algorithm to traverse the tree and keep track of the level of each node."
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