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leetcode-problemset/leetcode-cn/originData/implement-stack-using-queues.json
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{
"data": {
"question": {
"questionId": "225",
"questionFrontendId": "225",
"categoryTitle": "Algorithms",
"boundTopicId": 1233,
"title": "Implement Stack using Queues",
"titleSlug": "implement-stack-using-queues",
"content": "<p>Implement a last-in-first-out (LIFO) stack using only two queues. The implemented stack should support all the functions of a normal stack (<code>push</code>, <code>top</code>, <code>pop</code>, and <code>empty</code>).</p>\n\n<p>Implement the <code>MyStack</code> class:</p>\n\n<ul>\n\t<li><code>void push(int x)</code> Pushes element x to the top of the stack.</li>\n\t<li><code>int pop()</code> Removes the element on the top of the stack and returns it.</li>\n\t<li><code>int top()</code> Returns the element on the top of the stack.</li>\n\t<li><code>boolean empty()</code> Returns <code>true</code> if the stack is empty, <code>false</code> otherwise.</li>\n</ul>\n\n<p><b>Notes:</b></p>\n\n<ul>\n\t<li>You must use <strong>only</strong> standard operations of a queue, which means that only <code>push to back</code>, <code>peek/pop from front</code>, <code>size</code> and <code>is empty</code> operations are valid.</li>\n\t<li>Depending on your language, the queue may not be supported natively. You may simulate a queue using a list or deque (double-ended queue) as long as you use only a queue&#39;s standard operations.</li>\n</ul>\n\n<p>&nbsp;</p>\n<p><strong class=\"example\">Example 1:</strong></p>\n\n<pre>\n<strong>Input</strong>\n[&quot;MyStack&quot;, &quot;push&quot;, &quot;push&quot;, &quot;top&quot;, &quot;pop&quot;, &quot;empty&quot;]\n[[], [1], [2], [], [], []]\n<strong>Output</strong>\n[null, null, null, 2, 2, false]\n\n<strong>Explanation</strong>\nMyStack myStack = new MyStack();\nmyStack.push(1);\nmyStack.push(2);\nmyStack.top(); // return 2\nmyStack.pop(); // return 2\nmyStack.empty(); // return False\n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= x &lt;= 9</code></li>\n\t<li>At most <code>100</code> calls will be made to <code>push</code>, <code>pop</code>, <code>top</code>, and <code>empty</code>.</li>\n\t<li>All the calls to <code>pop</code> and <code>top</code> are valid.</li>\n</ul>\n\n<p>&nbsp;</p>\n<p><strong>Follow-up:</strong> Can you implement the stack using only one queue?</p>\n",
"translatedTitle": "用队列实现栈",
"translatedContent": "<p>请你仅使用两个队列实现一个后入先出LIFO的栈并支持普通栈的全部四种操作<code>push</code>、<code>top</code>、<code>pop</code> 和 <code>empty</code>)。</p>\n\n<p>实现 <code>MyStack</code> 类:</p>\n\n<ul>\n\t<li><code>void push(int x)</code> 将元素 x 压入栈顶。</li>\n\t<li><code>int pop()</code> 移除并返回栈顶元素。</li>\n\t<li><code>int top()</code> 返回栈顶元素。</li>\n\t<li><code>boolean empty()</code> 如果栈是空的,返回 <code>true</code> ;否则,返回 <code>false</code> 。</li>\n</ul>\n\n<p>&nbsp;</p>\n\n<p><strong>注意:</strong></p>\n\n<ul>\n\t<li>你只能使用队列的基本操作 —— 也就是&nbsp;<code>push to back</code>、<code>peek/pop from front</code>、<code>size</code> 和&nbsp;<code>is empty</code>&nbsp;这些操作。</li>\n\t<li>你所使用的语言也许不支持队列。&nbsp;你可以使用 list (列表)或者 deque双端队列来模拟一个队列&nbsp;, 只要是标准的队列操作即可。</li>\n</ul>\n\n<p>&nbsp;</p>\n\n<p><strong>示例:</strong></p>\n\n<pre>\n<strong>输入:</strong>\n[\"MyStack\", \"push\", \"push\", \"top\", \"pop\", \"empty\"]\n[[], [1], [2], [], [], []]\n<strong>输出:</strong>\n[null, null, null, 2, 2, false]\n\n<strong>解释:</strong>\nMyStack myStack = new MyStack();\nmyStack.push(1);\nmyStack.push(2);\nmyStack.top(); // 返回 2\nmyStack.pop(); // 返回 2\nmyStack.empty(); // 返回 False\n</pre>\n\n<p>&nbsp;</p>\n\n<p><strong>提示:</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= x &lt;= 9</code></li>\n\t<li>最多调用<code>100</code> 次 <code>push</code>、<code>pop</code>、<code>top</code> 和 <code>empty</code></li>\n\t<li>每次调用 <code>pop</code> 和 <code>top</code> 都保证栈不为空</li>\n</ul>\n\n<p>&nbsp;</p>\n\n<p><strong>进阶:</strong>你能否仅用一个队列来实现栈。</p>\n",
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"code": "type MyStack struct {\n\n}\n\n\nfunc Constructor() MyStack {\n\n}\n\n\nfunc (this *MyStack) Push(x int) {\n\n}\n\n\nfunc (this *MyStack) Pop() int {\n\n}\n\n\nfunc (this *MyStack) Top() int {\n\n}\n\n\nfunc (this *MyStack) Empty() bool {\n\n}\n\n\n/**\n * Your MyStack object will be instantiated and called as such:\n * obj := Constructor();\n * obj.Push(x);\n * param_2 := obj.Pop();\n * param_3 := obj.Top();\n * param_4 := obj.Empty();\n */",
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"code": "class MyStack\n def initialize()\n\n end\n\n\n=begin\n :type x: Integer\n :rtype: Void\n=end\n def push(x)\n\n end\n\n\n=begin\n :rtype: Integer\n=end\n def pop()\n\n end\n\n\n=begin\n :rtype: Integer\n=end\n def top()\n\n end\n\n\n=begin\n :rtype: Boolean\n=end\n def empty()\n\n end\n\n\nend\n\n# Your MyStack object will be instantiated and called as such:\n# obj = MyStack.new()\n# obj.push(x)\n# param_2 = obj.pop()\n# param_3 = obj.top()\n# param_4 = obj.empty()",
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