leetcode-problemset/leetcode-cn/originData/find-closest-node-to-given-two-nodes.json

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        "question": {
            "questionId": "2438",
            "questionFrontendId": "2359",
            "categoryTitle": "Algorithms",
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            "title": "Find Closest Node to Given Two Nodes",
            "titleSlug": "find-closest-node-to-given-two-nodes",
            "content": "<p>You are given a <strong>directed</strong> graph of <code>n</code> nodes numbered from <code>0</code> to <code>n - 1</code>, where each node has <strong>at most one</strong> outgoing edge.</p>\n\n<p>The graph is represented with a given <strong>0-indexed</strong> array <code>edges</code> of size <code>n</code>, indicating that there is a directed edge from node <code>i</code> to node <code>edges[i]</code>. If there is no outgoing edge from <code>i</code>, then <code>edges[i] == -1</code>.</p>\n\n<p>You are also given two integers <code>node1</code> and <code>node2</code>.</p>\n\n<p>Return <em>the <strong>index</strong> of the node that can be reached from both </em><code>node1</code><em> and </em><code>node2</code><em>, such that the <strong>maximum</strong> between the distance from </em><code>node1</code><em> to that node, and from </em><code>node2</code><em> to that node is <strong>minimized</strong></em>. If there are multiple answers, return the node with the <strong>smallest</strong> index, and if no possible answer exists, return <code>-1</code>.</p>\n\n<p>Note that <code>edges</code> may contain cycles.</p>\n\n<p>&nbsp;</p>\n<p><strong class=\"example\">Example 1:</strong></p>\n<img alt=\"\" src=\"https://assets.leetcode.com/uploads/2022/06/07/graph4drawio-2.png\" style=\"width: 321px; height: 161px;\" />\n<pre>\n<strong>Input:</strong> edges = [2,2,3,-1], node1 = 0, node2 = 1\n<strong>Output:</strong> 2\n<strong>Explanation:</strong> The distance from node 0 to node 2 is 1, and the distance from node 1 to node 2 is 1.\nThe maximum of those two distances is 1. It can be proven that we cannot get a node with a smaller maximum distance than 1, so we return node 2.\n</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n<img alt=\"\" src=\"https://assets.leetcode.com/uploads/2022/06/07/graph4drawio-4.png\" style=\"width: 195px; height: 161px;\" />\n<pre>\n<strong>Input:</strong> edges = [1,2,-1], node1 = 0, node2 = 2\n<strong>Output:</strong> 2\n<strong>Explanation:</strong> The distance from node 0 to node 2 is 2, and the distance from node 2 to itself is 0.\nThe maximum of those two distances is 2. It can be proven that we cannot get a node with a smaller maximum distance than 2, so we return node 2.\n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>n == edges.length</code></li>\n\t<li><code>2 &lt;= n &lt;= 10<sup>5</sup></code></li>\n\t<li><code>-1 &lt;= edges[i] &lt; n</code></li>\n\t<li><code>edges[i] != i</code></li>\n\t<li><code>0 &lt;= node1, node2 &lt; n</code></li>\n</ul>\n",
            "translatedTitle": "找到离给定两个节点最近的节点",
            "translatedContent": "<p>给你一个 <code>n</code>&nbsp;个节点的 <strong>有向图</strong>&nbsp;，节点编号为&nbsp;<code>0</code>&nbsp;到&nbsp;<code>n - 1</code>&nbsp;，每个节点 <strong>至多</strong>&nbsp;有一条出边。</p>\n\n<p>有向图用大小为 <code>n</code>&nbsp;下标从 <strong>0</strong>&nbsp;开始的数组&nbsp;<code>edges</code>&nbsp;表示，表示节点&nbsp;<code>i</code>&nbsp;有一条有向边指向&nbsp;<code>edges[i]</code>&nbsp;。如果节点&nbsp;<code>i</code>&nbsp;没有出边，那么&nbsp;<code>edges[i] == -1</code>&nbsp;。</p>\n\n<p>同时给你两个节点&nbsp;<code>node1</code> 和&nbsp;<code>node2</code>&nbsp;。</p>\n\n<p>请你返回一个从 <code>node1</code>&nbsp;和 <code>node2</code>&nbsp;都能到达节点的编号，使节点 <code>node1</code>&nbsp;和节点 <code>node2</code>&nbsp;到这个节点的距离 <b>较大值最小化</b>。如果有多个答案，请返回 <strong>最小</strong>&nbsp;的节点编号。如果答案不存在，返回 <code>-1</code>&nbsp;。</p>\n\n<p>注意&nbsp;<code>edges</code>&nbsp;可能包含环。</p>\n\n<p>&nbsp;</p>\n\n<p><strong>示例 1：</strong></p>\n\n<p><img alt=\"\" src=\"https://assets.leetcode.com/uploads/2022/06/07/graph4drawio-2.png\" style=\"width: 321px; height: 161px;\"></p>\n\n<pre><b>输入：</b>edges = [2,2,3,-1], node1 = 0, node2 = 1\n<b>输出：</b>2\n<b>解释：</b>从节点 0 到节点 2 的距离为 1 ，从节点 1 到节点 2 的距离为 1 。\n两个距离的较大值为 1 。我们无法得到一个比 1 更小的较大值，所以我们返回节点 2 。\n</pre>\n\n<p><strong>示例 2：</strong></p>\n\n<p><img alt=\"\" src=\"https://assets.leetcode.com/uploads/2022/06/07/graph4drawio-4.png\" style=\"width: 195px; height: 161px;\"></p>\n\n<pre><b>输入：</b>edges = [1,2,-1], node1 = 0, node2 = 2\n<b>输出：</b>2\n<b>解释：</b>节点 0 到节点 2 的距离为 2 ，节点 2 到它自己的距离为 0 。\n两个距离的较大值为 2 。我们无法得到一个比 2 更小的较大值，所以我们返回节点 2 。\n</pre>\n\n<p>&nbsp;</p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code>n == edges.length</code></li>\n\t<li><code>2 &lt;= n &lt;= 10<sup>5</sup></code></li>\n\t<li><code>-1 &lt;= edges[i] &lt; n</code></li>\n\t<li><code>edges[i] != i</code></li>\n\t<li><code>0 &lt;= node1, node2 &lt; n</code></li>\n</ul>\n",
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                    "code": "class Solution(object):\n    def closestMeetingNode(self, edges, node1, node2):\n        \"\"\"\n        :type edges: List[int]\n        :type node1: int\n        :type node2: int\n        :rtype: int\n        \"\"\"",
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                "How can you find the shortest distance from one node to all nodes in the graph?",
                "Use BFS to find the shortest distance from both node1 and node2 to all nodes in the graph. Then iterate over all nodes, and find the node with the minimum max distance."
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