leetcode-problemset/leetcode-cn/originData/disconnect-path-in-a-binary-matrix-by-at-most-one-flip.json

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            "title": "Disconnect Path in a Binary Matrix by at Most One Flip",
            "titleSlug": "disconnect-path-in-a-binary-matrix-by-at-most-one-flip",
            "content": "<p>You are given a <strong>0-indexed</strong> <code>m x n</code> <strong>binary</strong> matrix <code>grid</code>. You can move from a cell <code>(row, col)</code> to any of the cells <code>(row + 1, col)</code> or <code>(row, col + 1)</code> that has the value <code>1</code>.&nbsp;The matrix is <strong>disconnected</strong> if there is no path from <code>(0, 0)</code> to <code>(m - 1, n - 1)</code>.</p>\n\n<p>You can flip the value of <strong>at most one</strong> (possibly none) cell. You <strong>cannot flip</strong> the cells <code>(0, 0)</code> and <code>(m - 1, n - 1)</code>.</p>\n\n<p>Return <code>true</code> <em>if it is possible to make the matrix disconnect or </em><code>false</code><em> otherwise</em>.</p>\n\n<p><strong>Note</strong> that flipping a cell changes its value from <code>0</code> to <code>1</code> or from <code>1</code> to <code>0</code>.</p>\n\n<p>&nbsp;</p>\n<p><strong class=\"example\">Example 1:</strong></p>\n<img alt=\"\" src=\"https://assets.leetcode.com/uploads/2022/12/07/yetgrid2drawio.png\" style=\"width: 441px; height: 151px;\" />\n<pre>\n<strong>Input:</strong> grid = [[1,1,1],[1,0,0],[1,1,1]]\n<strong>Output:</strong> true\n<strong>Explanation:</strong> We can change the cell shown in the diagram above. There is no path from (0, 0) to (2, 2) in the resulting grid.\n</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n<img alt=\"\" src=\"https://assets.leetcode.com/uploads/2022/12/07/yetgrid3drawio.png\" />\n<pre>\n<strong>Input:</strong> grid = [[1,1,1],[1,0,1],[1,1,1]]\n<strong>Output:</strong> false\n<strong>Explanation:</strong> It is not possible to change at most one cell such that there is not path from (0, 0) to (2, 2).\n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>m == grid.length</code></li>\n\t<li><code>n == grid[i].length</code></li>\n\t<li><code>1 &lt;= m, n &lt;= 1000</code></li>\n\t<li><code>1 &lt;= m * n &lt;= 10<sup>5</sup></code></li>\n\t<li><code>grid[i][j]</code> is either <code>0</code> or <code>1</code>.</li>\n\t<li><code>grid[0][0] == grid[m - 1][n - 1] == 1</code></li>\n</ul>\n",
            "translatedTitle": "二进制矩阵中翻转最多一次使路径不连通",
            "translatedContent": "<p>给你一个下标从 <strong>0</strong>&nbsp;开始的&nbsp;<code>m x n</code>&nbsp;<strong>二进制</strong> 矩阵&nbsp;<code>grid</code>&nbsp;。你可以从一个格子&nbsp;<code>(row, col)</code>&nbsp;移动到格子&nbsp;<code>(row + 1, col)</code>&nbsp;或者&nbsp;<code>(row, col + 1)</code>&nbsp;，前提是前往的格子值为 <code>1</code>&nbsp;。如果从&nbsp;<code>(0, 0)</code>&nbsp;到&nbsp;<code>(m - 1, n - 1)</code>&nbsp;没有任何路径，我们称该矩阵是&nbsp;<strong>不连通</strong>&nbsp;的。</p>\n\n<p>你可以翻转 <strong>最多一个</strong>&nbsp;格子的值（也可以不翻转）。你 <strong>不能翻转</strong>&nbsp;格子&nbsp;<code>(0, 0)</code> 和&nbsp;<code>(m - 1, n - 1)</code>&nbsp;。</p>\n\n<p>如果可以使矩阵不连通，请你返回&nbsp;<code>true</code>&nbsp;，否则返回<em>&nbsp;</em><code>false</code><em>&nbsp;</em>。</p>\n\n<p><strong>注意</strong>&nbsp;，翻转一个格子的值，可以使它的值从&nbsp;<code>0</code>&nbsp;变&nbsp;<code>1</code>&nbsp;，或从&nbsp;<code>1</code>&nbsp;变&nbsp;<code>0</code>&nbsp;。</p>\n\n<p>&nbsp;</p>\n\n<p><strong>示例 1：</strong></p>\n\n<p><img alt=\"\" src=\"https://assets.leetcode.com/uploads/2022/12/07/yetgrid2drawio.png\" style=\"width: 441px; height: 151px;\" /></p>\n\n<pre>\n<b>输入：</b>grid = [[1,1,1],[1,0,0],[1,1,1]]\n<strong>输出：</strong>true\n<b>解释：</b>按照上图所示我们翻转蓝色格子里的值，翻转后从 (0, 0) 到 (2, 2) 没有路径。\n</pre>\n\n<p><strong>示例 2：</strong></p>\n\n<p><img alt=\"\" src=\"https://assets.leetcode.com/uploads/2022/12/07/yetgrid3drawio.png\" /></p>\n\n<pre>\n<b>输入：</b>grid = [[1,1,1],[1,0,1],[1,1,1]]\n<b>输出：</b>false\n<b>解释：</b>无法翻转至多一个格子，使 (0, 0) 到 (2, 2) 没有路径。\n</pre>\n\n<p>&nbsp;</p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code>m == grid.length</code></li>\n\t<li><code>n == grid[i].length</code></li>\n\t<li><code>1 &lt;= m, n &lt;= 1000</code></li>\n\t<li><code>1 &lt;= m * n &lt;= 10<sup>5</sup></code></li>\n\t<li><code>grid[0][0] == grid[m - 1][n - 1] == 1</code></li>\n</ul>\n",
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