leetcode-problemset/leetcode-cn/originData/diagonal-traverse.json

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            "categoryTitle": "Algorithms",
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            "title": "Diagonal Traverse",
            "titleSlug": "diagonal-traverse",
            "content": "<p>Given an <code>m x n</code> matrix <code>mat</code>, return <em>an array of all the elements of the array in a diagonal order</em>.</p>\n\n<p>&nbsp;</p>\n<p><strong class=\"example\">Example 1:</strong></p>\n<img alt=\"\" src=\"https://assets.leetcode.com/uploads/2021/04/10/diag1-grid.jpg\" style=\"width: 334px; height: 334px;\" />\n<pre>\n<strong>Input:</strong> mat = [[1,2,3],[4,5,6],[7,8,9]]\n<strong>Output:</strong> [1,2,4,7,5,3,6,8,9]\n</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> mat = [[1,2],[3,4]]\n<strong>Output:</strong> [1,2,3,4]\n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>m == mat.length</code></li>\n\t<li><code>n == mat[i].length</code></li>\n\t<li><code>1 &lt;= m, n &lt;= 10<sup>4</sup></code></li>\n\t<li><code>1 &lt;= m * n &lt;= 10<sup>4</sup></code></li>\n\t<li><code>-10<sup>5</sup> &lt;= mat[i][j] &lt;= 10<sup>5</sup></code></li>\n</ul>\n",
            "translatedTitle": "对角线遍历",
            "translatedContent": "<p>给你一个大小为 <code>m x n</code> 的矩阵 <code>mat</code> ，请以对角线遍历的顺序，用一个数组返回这个矩阵中的所有元素。</p>\n\n<p>&nbsp;</p>\n\n<p><strong>示例 1：</strong></p>\n<img alt=\"\" src=\"https://assets.leetcode.com/uploads/2021/04/10/diag1-grid.jpg\" style=\"width: 334px; height: 334px;\" />\n<pre>\n<strong>输入：</strong>mat = [[1,2,3],[4,5,6],[7,8,9]]\n<strong>输出：</strong>[1,2,4,7,5,3,6,8,9]\n</pre>\n\n<p><strong>示例 2：</strong></p>\n\n<pre>\n<strong>输入：</strong>mat = [[1,2],[3,4]]\n<strong>输出：</strong>[1,2,3,4]\n</pre>\n\n<p>&nbsp;</p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code>m == mat.length</code></li>\n\t<li><code>n == mat[i].length</code></li>\n\t<li><code>1 &lt;= m, n &lt;= 10<sup>4</sup></code></li>\n\t<li><code>1 &lt;= m * n &lt;= 10<sup>4</sup></code></li>\n\t<li><code>-10<sup>5</sup> &lt;= mat[i][j] &lt;= 10<sup>5</sup></code></li>\n</ul>\n",
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