leetcode-problemset/leetcode-cn/originData/count-vowel-strings-in-ranges.json

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        "question": {
            "questionId": "2691",
            "questionFrontendId": "2559",
            "categoryTitle": "Algorithms",
            "boundTopicId": 2089977,
            "title": "Count Vowel Strings in Ranges",
            "titleSlug": "count-vowel-strings-in-ranges",
            "content": "<p>You are given a <strong>0-indexed</strong> array of strings <code>words</code> and a 2D array of integers <code>queries</code>.</p>\n\n<p>Each query <code>queries[i] = [l<sub>i</sub>, r<sub>i</sub>]</code> asks us to find the number of strings present in the range <code>l<sub>i</sub></code> to <code>r<sub>i</sub></code> (both <strong>inclusive</strong>) of <code>words</code> that start and end with a vowel.</p>\n\n<p>Return <em>an array </em><code>ans</code><em> of size </em><code>queries.length</code><em>, where </em><code>ans[i]</code><em> is the answer to the </em><code>i</code><sup>th</sup><em> query</em>.</p>\n\n<p><strong>Note</strong> that the vowel letters are <code>&#39;a&#39;</code>, <code>&#39;e&#39;</code>, <code>&#39;i&#39;</code>, <code>&#39;o&#39;</code>, and <code>&#39;u&#39;</code>.</p>\n\n<p>&nbsp;</p>\n<p><strong class=\"example\">Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> words = [&quot;aba&quot;,&quot;bcb&quot;,&quot;ece&quot;,&quot;aa&quot;,&quot;e&quot;], queries = [[0,2],[1,4],[1,1]]\n<strong>Output:</strong> [2,3,0]\n<strong>Explanation:</strong> The strings starting and ending with a vowel are &quot;aba&quot;, &quot;ece&quot;, &quot;aa&quot; and &quot;e&quot;.\nThe answer to the query [0,2] is 2 (strings &quot;aba&quot; and &quot;ece&quot;).\nto query [1,4] is 3 (strings &quot;ece&quot;, &quot;aa&quot;, &quot;e&quot;).\nto query [1,1] is 0.\nWe return [2,3,0].\n</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> words = [&quot;a&quot;,&quot;e&quot;,&quot;i&quot;], queries = [[0,2],[0,1],[2,2]]\n<strong>Output:</strong> [3,2,1]\n<strong>Explanation:</strong> Every string satisfies the conditions, so we return [3,2,1].</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= words.length &lt;= 10<sup>5</sup></code></li>\n\t<li><code>1 &lt;= words[i].length &lt;= 40</code></li>\n\t<li><code>words[i]</code> consists only of lowercase English letters.</li>\n\t<li><code>sum(words[i].length) &lt;= 3 * 10<sup>5</sup></code></li>\n\t<li><code>1 &lt;= queries.length &lt;= 10<sup>5</sup></code></li>\n\t<li><code>0 &lt;= l<sub>i</sub> &lt;= r<sub>i</sub> &lt;&nbsp;words.length</code></li>\n</ul>\n",
            "translatedTitle": "统计范围内的元音字符串数",
            "translatedContent": "<p>给你一个下标从 <strong>0</strong> 开始的字符串数组 <code>words</code> 以及一个二维整数数组 <code>queries</code> 。</p>\n\n<p>每个查询 <code>queries[i] = [l<sub>i</sub>, r<sub>i</sub>]</code> 会要求我们统计在 <code>words</code> 中下标在 <code>l<sub>i</sub></code> 到 <code>r<sub>i</sub></code> 范围内（<strong>包含</strong> 这两个值）并且以元音开头和结尾的字符串的数目。</p>\n\n<p>返回一个整数数组，其中数组的第 <code>i</code> 个元素对应第 <code>i</code> 个查询的答案。</p>\n\n<p><strong>注意：</strong>元音字母是 <code>'a'</code>、<code>'e'</code>、<code>'i'</code>、<code>'o'</code> 和 <code>'u'</code> 。</p>\n\n<p>&nbsp;</p>\n\n<p><strong>示例 1：</strong></p>\n\n<pre>\n<strong>输入：</strong>words = [\"aba\",\"bcb\",\"ece\",\"aa\",\"e\"], queries = [[0,2],[1,4],[1,1]]\n<strong>输出：</strong>[2,3,0]\n<strong>解释：</strong>以元音开头和结尾的字符串是 \"aba\"、\"ece\"、\"aa\" 和 \"e\" 。\n查询 [0,2] 结果为 2（字符串 \"aba\" 和 \"ece\"）。\n查询 [1,4] 结果为 3（字符串 \"ece\"、\"aa\"、\"e\"）。\n查询 [1,1] 结果为 0 。\n返回结果 [2,3,0] 。\n</pre>\n\n<p><strong>示例 2：</strong></p>\n\n<pre>\n<strong>输入：</strong>words = [\"a\",\"e\",\"i\"], queries = [[0,2],[0,1],[2,2]]\n<strong>输出：</strong>[3,2,1]\n<strong>解释：</strong>每个字符串都满足这一条件，所以返回 [3,2,1] 。</pre>\n\n<p>&nbsp;</p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= words.length &lt;= 10<sup>5</sup></code></li>\n\t<li><code>1 &lt;= words[i].length &lt;= 40</code></li>\n\t<li><code>words[i]</code> 仅由小写英文字母组成</li>\n\t<li><code>sum(words[i].length) &lt;= 3 * 10<sup>5</sup></code></li>\n\t<li><code>1 &lt;= queries.length &lt;= 10<sup>5</sup></code></li>\n\t<li><code>0 &lt;= queries[j][0] &lt;= queries[j][1] &lt;&nbsp;words.length</code></li>\n</ul>\n",
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                    "code": "class Solution {\npublic:\n    vector<int> vowelStrings(vector<string>& words, vector<vector<int>>& queries) {\n        \n    }\n};",
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                    "code": "class Solution(object):\n    def vowelStrings(self, words, queries):\n        \"\"\"\n        :type words: List[str]\n        :type queries: List[List[int]]\n        :rtype: List[int]\n        \"\"\"",
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                    "code": "/**\n * Note: The returned array must be malloced, assume caller calls free().\n */\nint* vowelStrings(char ** words, int wordsSize, int** queries, int queriesSize, int* queriesColSize, int* returnSize){\n\n}",
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                    "code": "public class Solution {\n    public int[] VowelStrings(string[] words, int[][] queries) {\n\n    }\n}",
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                    "code": "/**\n * @param {string[]} words\n * @param {number[][]} queries\n * @return {number[]}\n */\nvar vowelStrings = function(words, queries) {\n\n};",
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                    "code": "class Solution {\n    fun vowelStrings(words: Array<String>, queries: Array<IntArray>): IntArray {\n\n    }\n}",
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                    "code": "class Solution {\n  List<int> vowelStrings(List<String> words, List<List<int>> queries) {\n\n  }\n}",
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                    "code": "# @param {String[]} words\n# @param {Integer[][]} queries\n# @return {Integer[]}\ndef vowel_strings(words, queries)\n\nend",
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                    "code": "object Solution {\n    def vowelStrings(words: Array[String], queries: Array[Array[Int]]): Array[Int] = {\n\n    }\n}",
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                    "code": "impl Solution {\n    pub fn vowel_strings(words: Vec<String>, queries: Vec<Vec<i32>>) -> Vec<i32> {\n\n    }\n}",
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                    "code": "-spec vowel_strings(Words :: [unicode:unicode_binary()], Queries :: [[integer()]]) -> [integer()].\nvowel_strings(Words, Queries) ->\n  .",
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                    "code": "defmodule Solution do\n  @spec vowel_strings(words :: [String.t], queries :: [[integer]]) :: [integer]\n  def vowel_strings(words, queries) do\n\n  end\nend",
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            "hints": [
                "Precompute the prefix sum of strings that start and end with vowels.",
                "Use unordered_set to store vowels.",
                "Check if the first and last characters of the string are present in the vowels set.",
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