leetcode-problemset/leetcode-cn/originData/count-unique-characters-of-all-substrings-of-a-given-string.json

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            "title": "Count Unique Characters of All Substrings of a Given String",
            "titleSlug": "count-unique-characters-of-all-substrings-of-a-given-string",
            "content": "<p>Let&#39;s define a function <code>countUniqueChars(s)</code> that returns the number of unique characters in&nbsp;<code>s</code>.</p>\n\n<ul>\n\t<li>For example, calling <code>countUniqueChars(s)</code> if <code>s = &quot;LEETCODE&quot;</code> then <code>&quot;L&quot;</code>, <code>&quot;T&quot;</code>, <code>&quot;C&quot;</code>, <code>&quot;O&quot;</code>, <code>&quot;D&quot;</code> are the unique characters since they appear only once in <code>s</code>, therefore <code>countUniqueChars(s) = 5</code>.</li>\n</ul>\n\n<p>Given a string <code>s</code>, return the sum of <code>countUniqueChars(t)</code> where <code>t</code> is a substring of <code>s</code>. The test cases are generated such that the answer fits in a 32-bit integer.</p>\n\n<p>Notice that some substrings can be repeated so in this case you have to count the repeated ones too.</p>\n\n<p>&nbsp;</p>\n<p><strong class=\"example\">Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> s = &quot;ABC&quot;\n<strong>Output:</strong> 10\n<strong>Explanation: </strong>All possible substrings are: &quot;A&quot;,&quot;B&quot;,&quot;C&quot;,&quot;AB&quot;,&quot;BC&quot; and &quot;ABC&quot;.\nEvery substring is composed with only unique letters.\nSum of lengths of all substring is 1 + 1 + 1 + 2 + 2 + 3 = 10\n</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> s = &quot;ABA&quot;\n<strong>Output:</strong> 8\n<strong>Explanation: </strong>The same as example 1, except <code>countUniqueChars</code>(&quot;ABA&quot;) = 1.\n</pre>\n\n<p><strong class=\"example\">Example 3:</strong></p>\n\n<pre>\n<strong>Input:</strong> s = &quot;LEETCODE&quot;\n<strong>Output:</strong> 92\n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= s.length &lt;= 10<sup>5</sup></code></li>\n\t<li><code>s</code> consists of uppercase English letters only.</li>\n</ul>\n",
            "translatedTitle": "统计子串中的唯一字符",
            "translatedContent": "<p>我们定义了一个函数 <code>countUniqueChars(s)</code> 来统计字符串 <code>s</code> 中的唯一字符，并返回唯一字符的个数。</p>\n\n<p>例如：<code>s = \"LEETCODE\"</code> ，则其中 <code>\"L\"</code>, <code>\"T\"</code>,<code>\"C\"</code>,<code>\"O\"</code>,<code>\"D\"</code> 都是唯一字符，因为它们只出现一次，所以 <code>countUniqueChars(s) = 5</code> 。</p>\n\n<p>本题将会给你一个字符串 <code>s</code> ，我们需要返回 <code>countUniqueChars(t)</code> 的总和，其中 <code>t</code> 是 <code>s</code> 的子字符串。输入用例保证返回值为&nbsp;32 位整数。</p>\n\n<p>注意，某些子字符串可能是重复的，但你统计时也必须算上这些重复的子字符串（也就是说，你必须统计 <code>s</code> 的所有子字符串中的唯一字符）。</p>\n\n<p>&nbsp;</p>\n\n<p><strong class=\"example\">示例 1：</strong></p>\n\n<pre>\n<strong>输入: </strong>s = \"ABC\"\n<strong>输出: </strong>10\n<strong>解释:</strong> 所有可能的子串为：\"A\",\"B\",\"C\",\"AB\",\"BC\" 和 \"ABC\"。\n     其中，每一个子串都由独特字符构成。\n     所以其长度总和为：1 + 1 + 1 + 2 + 2 + 3 = 10\n</pre>\n\n<p><strong class=\"example\">示例 2：</strong></p>\n\n<pre>\n<strong>输入: </strong>s = \"ABA\"\n<strong>输出: </strong>8\n<strong>解释: </strong>除了 countUniqueChars(\"ABA\") = 1 之外，其余与示例 1 相同。\n</pre>\n\n<p><strong class=\"example\">示例 3：</strong></p>\n\n<pre>\n<strong>输入：</strong>s = \"LEETCODE\"\n<strong>输出：</strong>92\n</pre>\n\n<p>&nbsp;</p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= s.length &lt;= 10<sup>5</sup></code></li>\n\t<li><code>s</code> 只包含大写英文字符</li>\n</ul>\n",
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